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4. Use the Bode tool to obtain the Bode plot automatically. Close the function generator and scope. • Open the Bode tool ⚫ Choose 15 steps per decade and run the Bode analyzer. • Sketch the Bode plot for the underdamped case. 5. Find the Resonant Frequency ⚫ Measure the frequency of the peak magnitude of the Bode plot. Resonant frequency (obtained from Bode plot): Compare to the value obtained in Part C, Step 3. Hz Part C) Bode Plot Underdamped Case The underdamped circuit has a resonant frequency, where the frequency response magnitude plot has a peak value that is larger than the DC value. 1. Replace the 1000 resistor with a potentiometer (either 10k, 5k, or 1k 2). The schematic becomes: +15 Scope Channel0 FGEN IN PIN 8 Al:0+ PIN 3 OUT Scope Channel 1 AO:0 PIN 1 1k pot Al: 1+ 3.3mH + -15 0.22µf PIN 2 PIN 4 AO: AGND Al: 1- Al:0- 2. Adjust the pot until you have an underdamped case. The easiest way to do this is to look at the time response as was done in Lab 6: • Close the Bode tool. • Set the function generator to a square wave ⚫ View the input and output voltage waveforms on the scope • Adjust the pot until you have an underdamped response 3. The resonant frequency is the frequency in a underdamped circuit where the ratio of the output amplitude to input amplitude is maximized, that is, |H(f)| = A./A; is maximized. Find the resonant frequency from a sine sweep • Set the Vp-p to 2v, and FGEN to a sine wave, and slowly increase the frequency of the input signal in FGEN (change the time/div scale on the SCOPE as needed to see the sine wave clearly) from 100 Hz to 9000 Hz. Notice that the output amplitude is significantly larger than the input amplitude near the resonant frequency. Determine the frequency where the output amplitude is the largest: Resonant frequency (obtained from the manual sine sweep): Hz

4. Use the Bode tool to obtain the Bode plot automatically. Close the function generator and scope. • Open the Bode tool ⚫ Choose 15 steps per decade and run the Bode analyzer. • Sketch the Bode plot for the underdamped case. 5. Find the Resonant Frequency ⚫ Measure the frequency of the peak magnitude of the Bode plot. Resonant frequency (obtained from Bode plot): Compare to the value obtained in Part C, Step 3. Hz Part C) Bode Plot Underdamped Case The underdamped circuit has a resonant frequency, where the frequency response magnitude plot has a peak value that is larger than the DC value. 1. Replace the 1000 resistor with a potentiometer (either 10k, 5k, or 1k 2). The schematic becomes: +15 Scope Channel0 FGEN IN PIN 8 Al:0+ PIN 3 OUT Scope Channel 1 AO:0 PIN 1 1k pot Al: 1+ 3.3mH + -15 0.22µf PIN 2 PIN 4 AO: AGND Al: 1- Al:0- 2. Adjust the pot until you have an underdamped case. The easiest way to do this is to look at the time response as was done in Lab 6: • Close the Bode tool. • Set the function generator to a square wave ⚫ View the input and output voltage waveforms on the scope • Adjust the pot until you have an underdamped response 3. The resonant frequency is the frequency in a underdamped circuit where the ratio of the output amplitude to input amplitude is maximized, that is, |H(f)| = A./A; is maximized. Find the resonant frequency from a sine sweep • Set the Vp-p to 2v, and FGEN to a sine wave, and slowly increase the frequency of the input signal in FGEN (change the time/div scale on the SCOPE as needed to see the sine wave clearly) from 100 Hz to 9000 Hz. Notice that the output amplitude is significantly larger than the input amplitude near the resonant frequency. Determine the frequency where the output amplitude is the largest: Resonant frequency (obtained from the manual sine sweep): Hz

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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4. Use the Bode tool to obtain the Bode plot automatically. Close the function generator and scope. • Open the Bode tool ⚫ Choose 15 steps per decade and run the Bode analyzer. • Sketch the Bode plot for the underdamped case. 5. Find the Resonant Frequency ⚫ Measure the frequency of the peak magnitude of the Bode plot. Resonant frequency (obtained from Bode plot): Compare to the value obtained in Part C, Step 3. Hz
Transcribed Image Text:4. Use the Bode tool to obtain the Bode plot automatically. Close the function generator and scope. • Open the Bode tool ⚫ Choose 15 steps per decade and run the Bode analyzer. • Sketch the Bode plot for the underdamped case. 5. Find the Resonant Frequency ⚫ Measure the frequency of the peak magnitude of the Bode plot. Resonant frequency (obtained from Bode plot): Compare to the value obtained in Part C, Step 3. Hz
Part C) Bode Plot Underdamped Case The underdamped circuit has a resonant frequency, where the frequency response magnitude plot has a peak value that is larger than the DC value. 1. Replace the 1000 resistor with a potentiometer (either 10k, 5k, or 1k 2). The schematic becomes: +15 Scope Channel0 FGEN IN PIN 8 Al:0+ PIN 3 OUT Scope Channel 1 AO:0 PIN 1 1k pot Al: 1+ 3.3mH + -15 0.22µf PIN 2 PIN 4 AO: AGND Al: 1- Al:0- 2. Adjust the pot until you have an underdamped case. The easiest way to do this is to look at the time response as was done in Lab 6: • Close the Bode tool. • Set the function generator to a square wave ⚫ View the input and output voltage waveforms on the scope • Adjust the pot until you have an underdamped response 3. The resonant frequency is the frequency in a underdamped circuit where the ratio of the output amplitude to input amplitude is maximized, that is, |H(f)| = A./A; is maximized. Find the resonant frequency from a sine sweep • Set the Vp-p to 2v, and FGEN to a sine wave, and slowly increase the frequency of the input signal in FGEN (change the time/div scale on the SCOPE as needed to see the sine wave clearly) from 100 Hz to 9000 Hz. Notice that the output amplitude is significantly larger than the input amplitude near the resonant frequency. Determine the frequency where the output amplitude is the largest: Resonant frequency (obtained from the manual sine sweep): Hz
Transcribed Image Text:Part C) Bode Plot Underdamped Case The underdamped circuit has a resonant frequency, where the frequency response magnitude plot has a peak value that is larger than the DC value. 1. Replace the 1000 resistor with a potentiometer (either 10k, 5k, or 1k 2). The schematic becomes: +15 Scope Channel0 FGEN IN PIN 8 Al:0+ PIN 3 OUT Scope Channel 1 AO:0 PIN 1 1k pot Al: 1+ 3.3mH + -15 0.22µf PIN 2 PIN 4 AO: AGND Al: 1- Al:0- 2. Adjust the pot until you have an underdamped case. The easiest way to do this is to look at the time response as was done in Lab 6: • Close the Bode tool. • Set the function generator to a square wave ⚫ View the input and output voltage waveforms on the scope • Adjust the pot until you have an underdamped response 3. The resonant frequency is the frequency in a underdamped circuit where the ratio of the output amplitude to input amplitude is maximized, that is, |H(f)| = A./A; is maximized. Find the resonant frequency from a sine sweep • Set the Vp-p to 2v, and FGEN to a sine wave, and slowly increase the frequency of the input signal in FGEN (change the time/div scale on the SCOPE as needed to see the sine wave clearly) from 100 Hz to 9000 Hz. Notice that the output amplitude is significantly larger than the input amplitude near the resonant frequency. Determine the frequency where the output amplitude is the largest: Resonant frequency (obtained from the manual sine sweep): Hz
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