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P1 Uo Սլ = R₁ (R 1 + R₂ + R1) (3.3) IL Use equation (3.3) and give the equation for the load current ½ through the load resis- tor R₁ depending on the load voltage U₁ and the load resistor RL. (3.4) R1 R2 12 A V IL RL UL

P1 Uo Սլ = R₁ (R 1 + R₂ + R1) (3.3) IL Use equation (3.3) and give the equation for the load current ½ through the load resis- tor R₁ depending on the load voltage U₁ and the load resistor RL. (3.4) R1 R2 12 A V IL RL UL

Power System Analysis and Design (MindTap Course List)
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter6: Power Flows
Section: Chapter Questions
Problem 6.61P
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P1 Uo Սլ = R₁ (R 1 + R₂ + R1) (3.3) IL Use equation (3.3) and give the equation for the load current ½ through the load resis- tor R₁ depending on the load voltage U₁ and the load resistor RL. (3.4)
Transcribed Image Text:P1 Uo Սլ = R₁ (R 1 + R₂ + R1) (3.3) IL Use equation (3.3) and give the equation for the load current ½ through the load resis- tor R₁ depending on the load voltage U₁ and the load resistor RL. (3.4)
R1 R2 12 A V IL RL UL
Transcribed Image Text:R1 R2 12 A V IL RL UL
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