rriente i, suministra al circuito una potencia compleja S. 10.000-j8.000. Calcular: a) valores Ry L de la impedancia conectada en serie con el generador de tensión ; b) diferencia de potencial in- stantánea en bornes del condensador de 0,05 F: c) potencias activas, reactivas y aparentes suminis- tradas por los demás generadores al circuito. www. -000 RQ L(H) 1-10/2sen 10r A Impedancia Z 0,02 F √√210 cos 10r 000 0,1 H ΖΩ 0,4 H B 19 0,1 F ud S=10.000-j8.000 0,05 F + ic i=2100 cos 10r √220 cos 10

rriente i, suministra al circuito una potencia compleja S. 10.000-j8.000. Calcular: a) valores Ry L de la impedancia conectada en serie con el generador de tensión ; b) diferencia de potencial in- stantánea en bornes del condensador de 0,05 F: c) potencias activas, reactivas y aparentes suminis- tradas por los demás generadores al circuito. www. -000 RQ L(H) 1-10/2sen 10r A Impedancia Z 0,02 F √√210 cos 10r 000 0,1 H ΖΩ 0,4 H B 19 0,1 F ud S=10.000-j8.000 0,05 F + ic i=2100 cos 10r √220 cos 10

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter2: Fundamentals

Section: Chapter Questions

Problem 2.14MCQ: The instantaneous power absorbed by the load in a single-phase ac circuit, for a general R LC load...

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