Enzyme 3 (diagram) is involved in negative feedback inhibition. It binds ATP at an inhibitory allosteric enzyme site on phosphofructokinase. What reagents does phosphofructokinase take into its active site. What are the products of the reaction that phosphofructokinase mediates. What do you think the ΔG (free energy) of this reaction is positive or negative, endothermic vs exothermic? Explain your answer above
Enzyme 3 (diagram) is involved in negative feedback inhibition. It binds ATP at an inhibitory allosteric enzyme site on phosphofructokinase. What reagents does phosphofructokinase take into its active site. What are the products of the reaction that phosphofructokinase mediates. What do you think the ΔG (free energy) of this reaction is positive or negative, endothermic vs exothermic? Explain your answer above
Human Anatomy & Physiology (11th Edition)
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- Enzyme 3 (diagram) is involved in negative feedback inhibition. It binds ATP at an inhibitory allosteric enzyme site on phosphofructokinase.
- What reagents does phosphofructokinase take into its active site.
- What are the products of the reaction that phosphofructokinase mediates.
- What do you think the ΔG (free energy) of this reaction is positive or negative, endothermic vs exothermic?
- Explain your answer above
- ATP is the end-product of ETC (electron transport chain), and at high concentrations of ATP, phosphofructokinase is inhibited allosterically. Please note that ATP is required in the active site. How does this mechanism act as a regulator for the entire ATP production pathway in mitochondria?
![PROCESS: GLYCOLYSIS
What goes in: ATP.
HOCH₂
Н
НО
O
Н
OH H
H
OH
1
H OH
Glucose Enzyme
What comes out:
2011 Pearson Education, Inc.
P OCH2
H
HO
ADP
o H
H
он н
OH
H OH
Glucose-
6-phosphate
| All 10 reactions
of glycolysis
occur in cytosol
72
P OCH₂
О
Н НО
H.COH
Н
НО Н Н
Fructose-
6-phosphate
ATP
Glycolysis begins with an
energy-investment
phase: 2 ATP-- 2 ADP
OH
7
2 P
P OCH₂
ADP
2 NAD+
6
H
0
Н НО
НО Н Н
Fructose-
1,6-bisphosphate
2 NADH
H₂CO P
3
OH
POC=O
HCOH
H₂CO P
POCH₂
2 ADP
c=0
H.COH
H
5
c=0
HCOH
H₂CO P
| The "2" indicates that glucose
has been split into two 3-carbon
sugars (only one is shown)
2 ATP
2
О
c=0
HCOH
H₂CO P
-
8
с 0
HCO P
H.COH
1.
9
2
о
c=0
CO P
||
CH₂
During the energy payoff phase, 4 ATP
are produced for a net gain of 2 ATP
2 ADP
10
2
c=0
c=0
CH₂
Pyruvate
2 ATP](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5cfa549f-cf3d-449e-abcb-d48b9e08c6d8%2F2e9febe5-91f6-44ed-85dd-478fb342f406%2Fz88f57p_processed.jpeg&w=3840&q=75)
Transcribed Image Text:PROCESS: GLYCOLYSIS
What goes in: ATP.
HOCH₂
Н
НО
O
Н
OH H
H
OH
1
H OH
Glucose Enzyme
What comes out:
2011 Pearson Education, Inc.
P OCH2
H
HO
ADP
o H
H
он н
OH
H OH
Glucose-
6-phosphate
| All 10 reactions
of glycolysis
occur in cytosol
72
P OCH₂
О
Н НО
H.COH
Н
НО Н Н
Fructose-
6-phosphate
ATP
Glycolysis begins with an
energy-investment
phase: 2 ATP-- 2 ADP
OH
7
2 P
P OCH₂
ADP
2 NAD+
6
H
0
Н НО
НО Н Н
Fructose-
1,6-bisphosphate
2 NADH
H₂CO P
3
OH
POC=O
HCOH
H₂CO P
POCH₂
2 ADP
c=0
H.COH
H
5
c=0
HCOH
H₂CO P
| The "2" indicates that glucose
has been split into two 3-carbon
sugars (only one is shown)
2 ATP
2
О
c=0
HCOH
H₂CO P
-
8
с 0
HCO P
H.COH
1.
9
2
о
c=0
CO P
||
CH₂
During the energy payoff phase, 4 ATP
are produced for a net gain of 2 ATP
2 ADP
10
2
c=0
c=0
CH₂
Pyruvate
2 ATP
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