Assume that you have a solution of 0.1 M glucose 6-phosphate. To this solution, you add the enzyme phosphoglucomutase, which catalyzes the reaction: Glucose 6-phosphate glucose 1-phosphate The standard free-energy change (AG°') for the reaction is +7.5 kJ mol-¹ (+1.8 kcal mol-¹). Phosphoglucomutase What is the final concentration of glucose 6-phosphate (G6P)? [G6P] = What is the final concentration of glucose 1-phosphate (G1P)? [G1P] = M M

Biochemistry
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Chapter1: Biochemistry: An Evolving Science
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Assume that you have a solution of 0.1 M glucose 6-phosphate. To this solution, you add the enzyme phosphoglucomutase,
which catalyzes the reaction:
Glucose 6-phosphate
glucose 1-phosphate
The standard free-energy change (AGº') for the reaction is +7.5 kJ mol¯¹ (+1.8 kcal mol−¹).
Phosphoglucomutase
What is the final concentration of glucose 6-phosphate (G6P)?
[G6P] =
What is the final concentration of glucose 1-phosphate (G1P)?
[G1P] =
M
M
Transcribed Image Text:Assume that you have a solution of 0.1 M glucose 6-phosphate. To this solution, you add the enzyme phosphoglucomutase, which catalyzes the reaction: Glucose 6-phosphate glucose 1-phosphate The standard free-energy change (AGº') for the reaction is +7.5 kJ mol¯¹ (+1.8 kcal mol−¹). Phosphoglucomutase What is the final concentration of glucose 6-phosphate (G6P)? [G6P] = What is the final concentration of glucose 1-phosphate (G1P)? [G1P] = M M
Does the reaction proceed as written?
Yes, because the standard free-energy change for the reaction is positive.
No, because the equilibrium constant is less than 1, which favors the reactant.
Yes, because the enzyme will shift the equilibrium point toward the product.
Yes, because the reactant concentration is much higher than the product concentration at equilibrium.
Under what cellular conditions could you produce G1P at a high rate?
Supply G1P and G6P at a high rate.
Supply G1P at a high rate and remove G6P at a high rate by other reactions.
Supply G6P at a high rate and remove G1P at a high rate by other reactions.
Remove G1P and G6P at a high rate by other reactions.
Transcribed Image Text:Does the reaction proceed as written? Yes, because the standard free-energy change for the reaction is positive. No, because the equilibrium constant is less than 1, which favors the reactant. Yes, because the enzyme will shift the equilibrium point toward the product. Yes, because the reactant concentration is much higher than the product concentration at equilibrium. Under what cellular conditions could you produce G1P at a high rate? Supply G1P and G6P at a high rate. Supply G1P at a high rate and remove G6P at a high rate by other reactions. Supply G6P at a high rate and remove G1P at a high rate by other reactions. Remove G1P and G6P at a high rate by other reactions.
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