The first reaction in glycolysis is the phosphorylation of glucose to form glucose 6-phosphate: P: + glucose glucose 6-phosphate + H₂O This is a thermodynamically unfavorable reaction, with AG=+13.8 kJ/mol. a) In a liver cell at 37°C the concentrations of both phosphate and glucose are normally maintained at about 5 mM each. What is the equilibrium concentration of glucose 6- phosphate, according to the above reaction? b) This very low concentration of glucose 6-phosphate is unfavorable for glycolysis. In fact, the reaction is coupled to the hydrolysis of ATP: ATP + H₂O = ADP + P +H AG¹ = -32.2 kJ/mol Write the expression for the overall reaction and calculate AG** c) In addition to the glucose and phosphate concentrations listed in part (a) above, assume that the liver cell concentrations of ATP and ADP are 3 mM and 1 mM, respectively. Calculate the theoretical equilibrium concentration of glucose 6-phosphate at pH = 7.4 and 37 °C.

Biochemistry
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Chapter1: Biochemistry: An Evolving Science
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The first reaction in glycolysis is the phosphorylation of glucose to form glucose 6-phosphate:

\[ P_i + \text{glucose} \rightleftharpoons \text{glucose 6-phosphate} + \text{H}_2\text{O} \]

This is a thermodynamically unfavorable reaction, with \(\Delta G^\circ' = +13.8 \, \text{kJ/mol}\).

a) In a liver cell at 37°C, the concentrations of both phosphate and glucose are normally maintained at about 5 mM each. What is the equilibrium concentration of glucose 6-phosphate, according to the above reaction?

b) This very low concentration of glucose 6-phosphate is unfavorable for glycolysis. In fact, the reaction is coupled to the hydrolysis of ATP:

\[ \text{ATP} + \text{H}_2\text{O} \rightleftharpoons \text{ADP} + P_i + \text{H}^+ \quad \Delta G^\circ' = -32.2 \, \text{kJ/mol} \]

Write the expression for the overall reaction and calculate \(\Delta G^\circ'\).

c) In addition to the glucose and phosphate concentrations listed in part (a) above, assume that the liver cell concentrations of ATP and ADP are 3 mM and 1 mM, respectively. Calculate the theoretical equilibrium concentration of glucose 6-phosphate at pH = 7.4 and 37°C.
Transcribed Image Text:The first reaction in glycolysis is the phosphorylation of glucose to form glucose 6-phosphate: \[ P_i + \text{glucose} \rightleftharpoons \text{glucose 6-phosphate} + \text{H}_2\text{O} \] This is a thermodynamically unfavorable reaction, with \(\Delta G^\circ' = +13.8 \, \text{kJ/mol}\). a) In a liver cell at 37°C, the concentrations of both phosphate and glucose are normally maintained at about 5 mM each. What is the equilibrium concentration of glucose 6-phosphate, according to the above reaction? b) This very low concentration of glucose 6-phosphate is unfavorable for glycolysis. In fact, the reaction is coupled to the hydrolysis of ATP: \[ \text{ATP} + \text{H}_2\text{O} \rightleftharpoons \text{ADP} + P_i + \text{H}^+ \quad \Delta G^\circ' = -32.2 \, \text{kJ/mol} \] Write the expression for the overall reaction and calculate \(\Delta G^\circ'\). c) In addition to the glucose and phosphate concentrations listed in part (a) above, assume that the liver cell concentrations of ATP and ADP are 3 mM and 1 mM, respectively. Calculate the theoretical equilibrium concentration of glucose 6-phosphate at pH = 7.4 and 37°C.
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