Question 2Determine the design shear strength of the given shape, using Fy=50 ksi. Blank 1W14x53A =...15.60in.^2d =13.900in.tw =0.370in.bf =8.060in.tf =0.660in.T=10-7/8in.k =1.2500in.k1 =1.0000in.gage =5-1/2in.rt =2.150in.d/Af =2.62Ix =541.00in. ^4Sx =77.80in.^3rx =5.890in.ly =Sy =57.70in.414.30in.43ry =1.920in.Zx =87.10in.43Zy =|22.00in.43J =Cw =1.94in.^42540in.46a =58.22in.Wno =26.70in.^2Sw =35.50in.4Qf =16.80in 43Qw =|42.60in.^3 Question 3Determine the following considering the section given in Problem no 2 and Live load = 450lb/ft, Permissible live load = L/60 where Lis equal to 30 ft.a) live load deflections in inches. Blank 1b) Adequate or Not, type A if Adequate and type N if not. Blank 2Blank 1 Add your answerBlank 2Add your answer

The shear strength for a given shape of the beam with given parameters is calculated as per given…

Determine the design shear strength of the given shape, using Fy=50 ksi. Blank 1 W14x53 15.60 13.900 A = d= tw = bf= tf = T= k= k1= gage = rt= d/Af= lx = Sx = rx = ly= Sy= 0.370 8.060 0.660 10-7/8 1.2500 1.0000 5-1/2 2.150 2.62 541.00 77.80 5.890 57.70 14.30 in.^2 in. in. in. in. in. in. in. in. in. in.4 in.43 in. in.^4 in.^3

Determine the design shear strength of the given shape, using Fy=50 ksi. Blank 1 W14x53 15.60 13.900 A = d= tw = bf= tf = T= k= k1= gage = rt= d/Af= lx = Sx = rx = ly= Sy= 0.370 8.060 0.660 10-7/8 1.2500 1.0000 5-1/2 2.150 2.62 541.00 77.80 5.890 57.70 14.30 in.^2 in. in. in. in. in. in. in. in. in. in.4 in.43 in. in.^4 in.^3

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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