Investigate the adequacy of the below equal angle shape using LRFD and ASD. Use case 2 for shear lag factor. Equal Angle Dimension: Anglength= 180.00 +0.4 SN (mm) Angleikness 10.00 +0.1 SN (mm) O O O O O O O O O Hallar Bolt Diameter: boltsam Material Grade: Bolt Holes spacing: s1= $2= g1= g2= g3- 84- Tensile Loadings: DL= LL= 16.00 +0.1 SN (mm) 248.00 +1.SN 400.00 +1.SN (Mpa) (Mpa) 25.00 +0.1 SN (mm) 30.00 +0.1 SN (mm) 25.00 +0.1 SN (mm) 35.00 +0.1 SN (mm) 30.00 +0.1 SN (mm) 40.00 +0.1 SN (mm) 350.00 +1.SN 300.00+1 SN (KN) (KN)
Investigate the adequacy of the below equal angle shape using LRFD and ASD. Use case 2 for shear lag factor. Equal Angle Dimension: Anglength= 180.00 +0.4 SN (mm) Angleikness 10.00 +0.1 SN (mm) O O O O O O O O O Hallar Bolt Diameter: boltsam Material Grade: Bolt Holes spacing: s1= $2= g1= g2= g3- 84- Tensile Loadings: DL= LL= 16.00 +0.1 SN (mm) 248.00 +1.SN 400.00 +1.SN (Mpa) (Mpa) 25.00 +0.1 SN (mm) 30.00 +0.1 SN (mm) 25.00 +0.1 SN (mm) 35.00 +0.1 SN (mm) 30.00 +0.1 SN (mm) 40.00 +0.1 SN (mm) 350.00 +1.SN 300.00+1 SN (KN) (KN)
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
SN = 11

Transcribed Image Text:Investigate the adequacy of the below equal angle shape using LRFD and ASD. Use case 2 for shear lag factor.
Equal Angle Dimension:
AngleLength =
Angle thickness=
Bolt Diameter:
O
O
O
0
O
O
O
O
SHERLER
boltalam =
Material Grade:
F₁ =
F₁ =
Bolt Holes spacing:
s1=
s2 =
g1=
g2=
g3=
g4=
180.00 +0.4 SN (mm)
10.00 +0.1SN (mm)
Tensile Loadings:
DL=
LL=
16.00 +0.1 SN (mm)
248.00 +1* SN
400.00 +1* SN
(Mpa)
(Mpa)
25.00 +0.1 SN
(mm)
30.00 +0.1SN (mm)
25.00 +0.1*SN (mm)
35.00 +0.1 SN (mm)
30.00 +0.1 SN (mm)
40.00 +0.1SN
(mm)
350.00 +1* SN
300.00+1 SN
(KN)
(KN)
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