Cx=0 P=150N 20 -60 30 180 B εFx =0= Cx JP=150N Dimensions in millimeters -900N = By B Bx=0 Q B. Су EFx =0=Bx GEM c = 0 = By (30mm) + 150N (180 nm) By = -900N GEMA=0 = Q(20mm) + (-900N) (60~~) Q = 2700 N
Cx=0 P=150N 20 -60 30 180 B εFx =0= Cx JP=150N Dimensions in millimeters -900N = By B Bx=0 Q B. Су EFx =0=Bx GEM c = 0 = By (30mm) + 150N (180 nm) By = -900N GEMA=0 = Q(20mm) + (-900N) (60~~) Q = 2700 N
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
4.2 Suppose that P=91lbs. What will the force Q be in this case
Transcribed Image Text:Cx=0
P=150N
20 -60
30
180
B
εFx =0= Cx
JP=150N
Dimensions in millimeters
-900N = By
B
Bx=0
Q
B.
Су
EFx =0=Bx
GEM c = 0 = By (30mm) + 150N (180 nm)
By = -900N
GEMA=0 = Q(20mm) + (-900N) (60~~)
Q
= 2700 N
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