Three steel bolts are to be used to attach the steel plate shown to a wooden beam. The plate will support a 110KN and the ultimate shearing stress for the steel used is 360MPA and that a factor of safety of 3.35 is desired, determine the decrease in the bolt diameter required if the 110KN load is decreased to 90kN.

Three steel bolts are to be used to attach the steel plate shown to a wooden beam. The plate will support a 110KN and the ultimate shearing stress for the steel used is 360MPA and that a factor of safety of 3.35 is desired, determine the decrease in the bolt diameter required if the 110KN load is decreased to 90kN.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

(N) 32900
The five-bolt connection shown must support an applied load of P = 371 kN. If the average shear stress in the bolts must be limited to 174 MPa, determine the minimum bolt diameter that may be used in the connection. Answer: d = i mm.
2. A steel plate is 360 mm wide and 20 mm thick with four bolts hole into the place as shown in the figure. Compute the following: a. Critical net area required by the NSCP specs. b. Max. critical net area required by the NSP specs. Note that, Max. net area is 85% of the critical net area Capacity of the joint if the allowable tensile stress is 0.75Fy. Use A36 steel Fy=248 MPa 25 mm= DIAMETER OF BOLTS 45 45mm fmmy C. 90mm 90mm 90mm Comm P
Problem For the frame shown, design the maximum permissible value of P with a factor of safety of 2.5. Design the maximum permissible value of P based on the following conditions: ✓ Ultimate tensile strength of each member CD is 300 ksi Ultimate shear strength of the bolts in A, C, E, and F is 200 ksi ✓ Ultimate bearing strength of member BDE is 150 ksi ✓ Ultimate bearing strength of the support plates is 250 ksi Members CD and BDE have cross-sectional dimensions of 5 in x 3 in (the larger dimension is the width). The diameters of the bolts are as follows: A and B - 1.5 in: C and D-2 in E and F - 1 in. 1.5 in. thick Support Plates -2 ft + D 3 ft B 2 in thick Support Mate Solution Step 1. Identify the conditions for design. Stress normal stress in each member CD, OCD shear stress in bolt A, TA shear stress in bolt C, T shear stress in bolt E, T shear stress in bolt F, T bearing stress on member BDE due to: bolt B, BDE-B bolt D, OBDE-D bolt E, OBDE-E bearing stress on support plates at…
The five-bolt connection shown must support an applied load of P = 300 N. The thickness of the axial member: = 1.5 mm. and the width = 18 mm If the ultimate shear stress in the bolts must be limited to 265 MPa with F.O.S = 3.7 . And the ultimate normal stress in the axial member = 250 MPa, with F.O.S = 2.8 , And the ultimate bearing stress in the axial member = 110 MPa, F.O.S = 2.5 Determine the minimum bolt diameter that may be used in the connection
A plate with width of 420 mm and thickness of 13 mm is to be connected to a plate of the same width and thickness by 30 mm diameter bolts, as shown in the Figure 1. The holes are 3mm larger than the bolt diameter. The plate is A36 steel with yield strength Fy = 248MPa. Assume allowable tensile stress on net area is 0.60Fy. It is required to determine the value of b such that the net width along bolts 1-2-3-4 is equl to the net width along bolts 1-2-4. W = 420 mm t = 13 mm a = 64 mm c = 104 mm d = 195 mm Bolt Diameter = 30 mm Holes Diameter = 30 mm + 3 = 33 mm ?? = 248 MPa Allowable Tensile Stress on ?? = 0.60Fy a. Calculate the vaue of b in millimeters. b. Calculate the value of the net area for tension in plates in square millimeters. c. Calculate the value of P so that the allowable tensile stress on net area will not be exceeded.
An A36 steel plate with width of 400 mm and thickness of 12 mm is to beconnected to a plate of the same width and thickness by 34 mm diametersbolts, as shown in the figure (next slide). The holes are 2 mm larger thanthe bolt diameter. The yield strength of the steel plate is Fy = 248 MPa.Assume allowable tensile stress on net area is 0.60Fy. It is required todetermine the value of b such that the net width along bolts 1-2-3-4 isequal to the net width along bolts 1-2-4.a. Calculate the value of b in mm.b. Calculate the value of the net area for tension in plates in mm².c. Calculate the value of P so that the allowable tensile stress on net areawill not be exceeded.(Use at least 2 decimal points on your answers.)
A PL40 mm X 250 mm (smaller member) is connected to a gusset plate (bigger member) as shown. The diameter of the holes are 25 mm. The pitch and gage of the holes are 50 mm and 75 mm, respectively. The yield strength of the steel is 260 MPa while the ultimate tensile strength of the steel is 400 MPa. Determine the design (LRFD) tensile strength of the tension member in kN. Neglect block shear. H FO E. • D A В
Problem No 2 A flanged-bolt coupling consisting of six 4 inch diameter steel bolts evenly spaced around a bolt circle 12 inches in diameter and four inch diameter aluminum bolts on a concentric circle 8 inches in diameter. What stresses are developed on each bolt of the two bolt-circles when a torque T=75 Kip-in is applied. Use Gs=12 x 10° psi and GA = 4 x10° psi.