Homework Help is Here – Start Your Trial Now!
Engineering
Civil Engineering
AW 5 x 16 wide flange is subjected to a suspended tensile load at one end. There are 6 sets of 25 mm diameter fasteners holes at the web center along the direction of loading. The distance between center of the holes is 80 mm along the direction of force. Using Fy = 248 MPa and Fu = 440 MPa find the tensile capacity (LRFD & ASD). Use U = 0.70 (see table 504.3.1 of NSCP 2015 diameter of hole = 25 mm bf = 127 mm tf = 9.14 mm Ag = 3,019 sq mm d = 127.25 mm tw = 6.1 mm U = 0.70

AW 5 x 16 wide flange is subjected to a suspended tensile load at one end. There are 6 sets of 25 mm diameter fasteners holes at the web center along the direction of loading. The distance between center of the holes is 80 mm along the direction of force. Using Fy = 248 MPa and Fu = 440 MPa find the tensile capacity (LRFD & ASD). Use U = 0.70 (see table 504.3.1 of NSCP 2015 diameter of hole = 25 mm bf = 127 mm tf = 9.14 mm Ag = 3,019 sq mm d = 127.25 mm tw = 6.1 mm U = 0.70

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
See similar textbooks
icon
Related questions
Question
AW 5 x 16 wide flange is subjected to a suspended tensile load at one end. There are 6 sets of 25 mm diameter fasteners holes at the web center along the direction of loading. The distance between center of the holes is 80 mm along the direction of force. Using Fy = 248 MPa and Fu = 440 MPa find the tensile capacity (LRFD & ASD). Use U = 0.70 (see table 504.3.1 of NSCP 2015 diameter of hole = 25 mm bf = 127 mm tf = 9.14 mm Ag = 3,019 sq mm d = 127.25 mm tw = 6.1 mm U = 0.70
Transcribed Image Text:AW 5 x 16 wide flange is subjected to a suspended tensile load at one end. There are 6 sets of 25 mm diameter fasteners holes at the web center along the direction of loading. The distance between center of the holes is 80 mm along the direction of force. Using Fy = 248 MPa and Fu = 440 MPa find the tensile capacity (LRFD & ASD). Use U = 0.70 (see table 504.3.1 of NSCP 2015 diameter of hole = 25 mm bf = 127 mm tf = 9.14 mm Ag = 3,019 sq mm d = 127.25 mm tw = 6.1 mm U = 0.70
Expert Solution
steps

Step by step

Solved in 2 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Loads and reactive forces
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Structural Analysis
Structural Analysis
Civil Engineering
ISBN:
9781337630931
Author:
KASSIMALI, Aslam.
Publisher:
Cengage,
Structural Analysis (10th Edition)
Structural Analysis (10th Edition)
Civil Engineering
ISBN:
9780134610672
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Principles of Foundation Engineering (MindTap Cou…
Principles of Foundation Engineering (MindTap Cou…
Civil Engineering
ISBN:
9781337705028
Author:
Braja M. Das, Nagaratnam Sivakugan
Publisher:
Cengage Learning
Fundamentals of Structural Analysis
Fundamentals of Structural Analysis
Civil Engineering
ISBN:
9780073398006
Author:
Kenneth M. Leet Emeritus, Chia-Ming Uang, Joel Lanning
Publisher:
McGraw-Hill Education
Sustainable Energy
Sustainable Energy
Civil Engineering
ISBN:
9781337551663
Author:
DUNLAP, Richard A.
Publisher:
Cengage,
Traffic and Highway Engineering
Traffic and Highway Engineering
Civil Engineering
ISBN:
9781305156241
Author:
Garber, Nicholas J.
Publisher:
Cengage Learning
SEE MORE TEXTBOOKS