A Elastic bar AB is connected to rigid member ACD as shown in the figure. Determine the displacement of point D due to the applied loading. ·A• 2 FBD 7.5 X rigid A=200mm² ME=80 GPa No AZ FAB X AZ FAB 2 Cy dimensions in meters 7.500mm = cos x=cos 81.87⁰ x=53,03 mm 0.5 Cx x=90-8=81.87° JOKN ~ why to ? ΣMc=0:12 FAB (1.5) - 12 F₁B (2) +10(2)=0 FAB=56.57KN 10KH PL 8= À why do we use cos? B=45-tan (2)=8.130° _ 56.57-10³ (2121)_. 200 (80×10²) 7.500mm 0=X= 53.03 2500 How do we get this value? - where do we get this value 0.02121 rad. Sp-OLco 0.02121(2000) 42.43mm upward ↳ where does 2000 come from?
A Elastic bar AB is connected to rigid member ACD as shown in the figure. Determine the displacement of point D due to the applied loading. ·A• 2 FBD 7.5 X rigid A=200mm² ME=80 GPa No AZ FAB X AZ FAB 2 Cy dimensions in meters 7.500mm = cos x=cos 81.87⁰ x=53,03 mm 0.5 Cx x=90-8=81.87° JOKN ~ why to ? ΣMc=0:12 FAB (1.5) - 12 F₁B (2) +10(2)=0 FAB=56.57KN 10KH PL 8= À why do we use cos? B=45-tan (2)=8.130° _ 56.57-10³ (2121)_. 200 (80×10²) 7.500mm 0=X= 53.03 2500 How do we get this value? - where do we get this value 0.02121 rad. Sp-OLco 0.02121(2000) 42.43mm upward ↳ where does 2000 come from?
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Elastic bar AB is connected to rigid member ACD as shown in the
figure. Determine the displacement of point D due to the applied loading.
FBD
7.5
X
A=Zoo mm²
ME=80 GPa
5.
rigid
X
1.5-
AZ FAB
AZ FAB
f
A
B
04
Cy
dimensions in meters
7.500mm
0.5
why?
EM₁=0:¹ (1.5)-12 FAB (2) +10 (2) = 0
FAB=56.57KN
x=90-B=81.87°
IOKN
10kH
S = À
2=cosα=cos 81.87°
x=53,03 mm
why do we use cos?
PL_56.57-10³ (2121)
200 (80×10³)
B=45°-tan' (2)=8.130°
B
How do we get
this value?
7.500 mm
where do we get
this value
53.03
2.500
Sp-OLco=0.02121(2000) 42.43mm upward
0=X=5 =0.02121 rad.
I where does 2000
come from?
Expert Solution
Step 1
Given
Area , A= 200 mm2
Modulus of Elasticity, E= 80 Gpa
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