At 300 K, what fold improvement in a reaction rate do you expect if AG* is brought down from 40 kJ/mol to 20 kJ/mol, without changing of the reaction mechanism, as a result of enzymatic catalysis? е. f. The following may or may not be affected by the addition of an enzyme to a chemical reaction. State if there will be (1) no effect, (2) an increase, or (3) a decrease? A) activation energy of the reaction B) standard free energy of the reaction C) time to reach equilibrium D) equilibrium constant of the reaction E) initial velocity of the reaction g. Remember the simple kinetic mechanism for an enzyme-catalyzed reaction. It was reported that the rate-limiting step is the following reaction ES > P Under these circumstances, the Michaelis constant becomes equivalent to A) [S], when Vo = Vmax B) Turnover number C) Specificity constant D) kcat E) the dissociation constant for the Enzyme-Substrate (ES) complex

At 300 K, what fold improvement in a reaction rate do you expect if AG* is brought down from 40 kJ/mol to 20 kJ/mol, without changing of the reaction mechanism, as a result of enzymatic catalysis? е. f. The following may or may not be affected by the addition of an enzyme to a chemical reaction. State if there will be (1) no effect, (2) an increase, or (3) a decrease? A) activation energy of the reaction B) standard free energy of the reaction C) time to reach equilibrium D) equilibrium constant of the reaction E) initial velocity of the reaction g. Remember the simple kinetic mechanism for an enzyme-catalyzed reaction. It was reported that the rate-limiting step is the following reaction ES > P Under these circumstances, the Michaelis constant becomes equivalent to A) [S], when Vo = Vmax B) Turnover number C) Specificity constant D) kcat E) the dissociation constant for the Enzyme-Substrate (ES) complex

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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Select the incorrect statement. With regards to free energy ΔG of the reaction below E+S ⇌ ES Negative ΔG mean the reaction toward is facourable More negative value of ΔG indicates stronger binding to S to E It is possible to compute disassociation constant from the ΔG value alone It is possible to calculate the term ( ΔH – T ΔS) from the value of ΔGalone ΔG = 0 indicates (ES)/(E)(S) =1 None of the above
The rate constants of an enzyme-catalyzed reaction, obeying the Michaelis-Menten kinetics, have been determined : E + S K₁ = 2 x 108 M-¹ S-¹ -1 -1 -1 K-₁= 1 x 10³ S K₂ = 5 x 10³ S-1 K₁ 1 K-1 ES K₂ E +P 1- Determine the Michaelis constant Km of the enzyme. 2- Determine the catalytic constant (kcat) of the enzyme. 3- Determine the catalytic efficiency of the enzyme.
5.50 1/V, min/umol 5.00 4.50 4.00 y = 0.9474x + 2.6649 y = 0.9997x + 2.032 0.00 1.00 2.00 2.50 3.00 1/[S], uM -1 Looking at the double reciprocal plot for an enzyme in the absence of inhibitor and in the presence of two concentrations of inhibitor, what would be the Vmax for the uninhibited enzyme? (bottom graph) Equation is given. Choose the one best answer. 3.50 3.00 2.50 2.00
Which of the following statements are true about the relationships of [S], KM, and Vmax? (Choose all that are true) As the [S] is increased, vo approaches the limiting value, Vmax KM = Vmax/2 The rate of product formed, vo, is at Vmax when [S] <<< KM KM and Vmax assist in finding the rate of the enzyme catalyzed reaction only if the reaction is considered irreversible.
A competitive inhibitor interacts with the free enzyme to form an enzyme•inhibitor complex(E•I). This equilibrium reaction can be described as follows:E + I ⇌ EIModify the simplified kinetic scheme for the reaction E + S ⇌ E + P to include this equilibriumexpression
Consider the following free energy diagram for an uncatalyzed and enzyme-catalyzed reaction. Select all the statements that are true. Without enzyme With enzyme A+B Time AB O a. The rate of the enzyme catalyzed reaction is faster than the uncatalyzed reaction O b. The change in free energy for the reaction is greater in the catalyzed reaction, compared to the uncatalyzed reaction O c. The enzyme stabilizes the transition state for the reaction Od. The reaction is exergonic е. The reaction is now spontaneous due to the addition of enzyme Released Energy
1) Is the ratio of the forward rate constant and reverse rate constant changed by the presence of an enzyme catalyst? 2) 4) What is the simplest mathematical relationship between substrate concentrations [S], initial velocity (Vo) of an enzyme catalyzed reaction, the maximal velocity of the reaction (Vmax), and the ½ maximal Vo (i.e. Km) ? (Hint: what is the Michaelis-Menten Equation? 3) Graphically illustrate the most useful derivation of the Michaelis-Menton equation (that darn linearized, double-reciprocal)