equations and values: E can bind to two different substrates, S and I. The binding reactions are described by the following E+S ES K for ES = 10 E+1=El K for El = 2 Based on the equilibrium constant values, which one of the following statements is true? E binds I more tightly than S. When S is present in excess, no I molecules will bind to E. The binding energy of the ES interaction is greater than that of the El interaction. Changing an amino acid on the binding surface of I from a basic amino acid to an acidic one will likely make the free energy of association with E more negative. A. B. C. D. Remember that K = [C][D]/[A][B] for the reaction A + B C + D
Enzyme kinetics
In biochemistry, enzymes are proteins that act as biological catalysts. Catalysis is the addition of a catalyst to a chemical reaction to speed up the pace of the reaction. Catalysis can be categorized as either homogeneous or heterogeneous, depending on whether the catalysts are distributed in the same phase as that of the reactants. Enzymes are an essential part of the cell because, without them, many organic processes would slow down and thus will affect the processes that are important for cell survival and sustenance.
Regulation of Enzymes
A substance that acts as a catalyst to regulate the reaction rate in the living organism's metabolic pathways without itself getting altered is an enzyme. Most of the biological reactions and metabolic pathways in the living systems are carried out by enzymes. They are specific for their works and work in particular conditions. It maintains the best possible rate of reaction in the most stable state. The enzymes have distinct properties as they can proceed with the reaction in any direction, their particular binding sites, pH specificity, temperature specificity required in very few amounts.
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![The enzyme E can bind to two different substrates, S and I. The binding reactions are described by the following equations and values:
\[ E + S \rightleftharpoons ES \]
\[ E + I \rightleftharpoons EI \]
\[ \text{K for ES} = 10 \]
\[ \text{K for EI} = 2 \]
Based on the equilibrium constant values, which of the following statements is true?
A. E binds I more tightly than S.
B. When S is present in excess, no I molecules will bind to E.
C. The binding energy of the ES interaction is greater than that of the EI interaction.
D. Changing an amino acid on the binding surface of I from a basic amino acid to an acidic one will likely make the free energy of association with E more negative.
Remember that \( K = \frac{[C][D]}{[A][B]} \) for the reaction \( A + B \rightleftharpoons C + D \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F637a8243-98d2-45ca-8dd1-4e9d7d0f97ca%2Fae2e695e-869d-4ec7-8752-7138922fe93a%2Fx7135oxj.jpeg&w=3840&q=75)
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