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- 3. Attach the structures below to draw a sphingolipid. CH3-(CH2)12-CH=CH-CH-OH sphingosine CH–NH2 CH₂-OH H-O-P-0-H 0* HO NH2-CH₂-CH2-OH13. Which statement(s) correctly describe this disaccharide? CH2OH CH2OH A. It's the alpha anomer, and it's a reducing sugar. CH-O CH-O OH B. It's the alpha anomer, and it's a nonreducing sugar. CH CH CH CH OH C. It's the beta anomer, and it's a reducing sugar. ОН СН—СH CH-CH D. It's the beta anomer, and it's a nonreducing sugar. OH OH OHF 9. In sugars that contain many chiral centers, only the chiral center that is most distant from the carbonyl carbon is designated as D (right) or L (left). Determine which of the structures below are D and L sugars. H-C-OH HIC OH H-C-OH I CH₂OH D-Ribose HO C-H H-C-OH H-C-OH I CH₂OH D-Arabinose H-C-OH HO-C-H H-C-OH H-C-OH T HO-C-H I H-C-OH I CH₂OH D-Xylose D-Aldoses Five carbons H-C-OH H-C-OH HO-C-H H-C-OH HO-C-H HO-C-H H-C-OH CH₂OH CH₂OH CH₂OH CH₂OH D-Ribose D-Arabinose D-Xylose D-Lyxose HO-C-H HO-C-H H- H-C-OH CHO IMPORTANT NOTE: most hexoses in living organism are D isomers. Thus, the D prefix is often omitted. DO NOT confuse this with amino acids. Remember that the most common amino acids in living organism are L isomers. L sugars are mirror images of D sugars. H-C-OH -OH 10. Sugars (monosaccharides) can be trioses, tetroses, pentoses, hexoses, heptoses, etc., depending on the number of carbons they have. Determine the number of carbons in the structures above (#9) and determine…
- 1 Describe the difference between amylose and amylopectin. 2 what is the monosaccharide that results from the complete hydrolysis of amylose? 3 What is the chemical difference between cellulose and starch ( amylose and amylopectin).CH2OH CH2OH 12. What type of linkage is found in this carbohydrate? CH-O CH—0 Н A. a-1,4 В. В-1,4 CH OH CH CH С. а-1,6 D. B-1,6 ОН СН—СН CH-CH CH2OH ОН E. None of these is correct.Which of the structures above is a component of sucrose and predominantly forms a furanose ring structure? A. H C I H-C-OH НО-С-Н I Н-С-ОН I H-C-OH I CH2OH A В D B. H =O но-с-н I но-с-н I н-с-он Н-С-ОН I CH₂OH CH2OH I c=0 I но-с-н I H— C -ОН H— C-OH CH₂OH D. COOH H-C-OH НО-С-Н I но-с-н I н-с-он CH₂OH
- 1. At pH 7, the net charge of lysine is A. -2 В. -1 С. О D. +1 Е. +2 2. All 20 amino acids have A. one chiral carbon В. one a-carbon C. one carboxyl group D. ionizable R group E. neutral charge at physiological pH 3. The a helix structure of a polypeptide is maintained by A. peptide bonds B. van der Waal's force C. hydrogen bonds D. ionic bonds E. disulphide bonds 4. Which side chain of the following amino acid is deprotonated at pH 9? A. Methionine B. Alanine C. Isoleucine D. Histidine Е. Тyгosine 5. How many chiral carbons are in the following sugar? А. 1 В. 2 С. 3 D. 4 Е. 5Classify the monosaccharides. H H-C- -OH H-C- -OH H- CH₂OH D-erythrose H- CH₂OH FO -OH H. CH₂OH D-erythrulose H- -OH -OH H-C OH CH₂OH H- D-ribose CH₂OH OH H-C OH CH₂OH D-ribulose H H-C- CH₂OH D-glyceraldehyde -OH HO- -C- H- CH₂OH FO -H -C- -OH H-C OH CH₂OH D-fructose CH₂OH C=O CH₂OH Dihydroxyacetone triose Answer Bank ketose hexose aldose tetrose pentoseHO. CH₂ OH NH₂ 'N OH N Molecule 3 O pyrimidine, deoxyribose O pyrimidine, ribose O purine, deoxyribose purine, ribose
- Aldose monosaccharides can be oxidized when treated with a mild oxidizing agent. In this reaction, the aldehyde group of the open-chain aldose is oxidized to a carboxylic acid group. In basic solution, ketose monosaccharides can also be oxidized, forming carboxylic acids because they can undergo a rearrangement to an aldose form. Monosaccharides (cyclic hemiacetals) can also react with an alcohol to form acetals, called glycosides, and water. In this reaction, the OH of the anomeric carbon is replaced by the OR group of the alcohol. D-ribose (Figure 1) is treated with a mild oxidizing agent. Edit the structure for D-ribose to show the product of this reaction. M Edit the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. The single bond is active by default. Include all hydrogen atoms. ► View Available Hint(s) [1] A H 12D H H H H 7 L EXP. CONT.i L 1 -O-H O H ew -O-H enodic Table -O-H H C N O S CI Br I P FStyles 1. The complex I structure contains the lipid shown to the right, which contains two linked phospholipids. Circle the two phospholipids. Briefly explain your choice. tes) D. Focus A 83°F ENC DELL F4 F5 F6 F7 F8 F9 F10 F11 F12 PrtScr In %23 %24 & 7 8. R Y K す1- Please refer to the Fisher representation of the 5 monosaccharides below: ÇH2OH CHO CHO CHO CHO H- H- он H- OH OH HO HO но- H- OH HO Но- H- -OH H- H- -OH HO- OH HO H- -OH H- -OH HO HO H- OH ČH2OH ČH2CH ČH2CH ČH2CH ČH2CH D-Fructose D-Glucose L-Glucose L-Idose D-Galactose 1a- Which one(s) of the above molecules belong(s) to the subcategory of aldohexoses? and which one(s) of these molecules belong(s) to the subcategory of ketohexoses? Briefly explain your response. 1b- Which one of the above molecules is an enantiomer of D-Glucose? and which one is an epimer of L-Ildose? Briefly explain your response.