25. The protease papain, which can be isolated from papaya fruit, isa monomer with one active site per protein molecule. Theactivity of purified papain enzyme was measured at varioussubstrate concentrations and plotted as initial velocity on thefollowing graph.(mM/min)3530255/5°2020151052525200-10 -505 1015201(mM) 1[Substrate]3030 Considering that the enzyme concentration was held constant inthese experiments at 1.2 × 107 M, answer the followingquestions about this enzyme.a. Calculate Km for this substrate.b. Calculate Vmax for this substrate.c. Calculate keat for papain with this substrate.d. What fraction of total enzyme has substrate bound when thesubstrate concentration is 2.5 × 10 4 M?

Given:Lineweaver-Burk plotEnzyme concentration ([E]) = 1.2 x 10^-10 MSubstrate concentration ([S]) =…

Answered: 25. The protease papain, which can be…

Curren'S Math For Meds: Dosages & Sol

11th Edition

ISBN:9781305143531

Author:CURREN

Publisher:CURREN

Chapter21: Heparin Infusion Calculations

Section: Chapter Questions

Problem 1.3P

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b. Compounds A, B, C, and D are known to be intermediates in the pathway for production of protein E. To determine where the block in protein-E production occurred in each individual, the various intermediates were given to each individuals cel Is in culture. After a few weeks of growth with the intermediate, the cells were assayed for the production of protein E. The results for each individuals cells are given in the following table. A plus sign means that protein E was produced after the cells were given the intermediate listed at the top of the column. A minus sign means that the cells still could not produce protein E even after being exposed to the intermediate at the top of the column. Denote the point in the pathway in which each individual is blocked.
a. Compounds A, B, C, and D are known to be intermediates in the pathway for production of protein E. To determine where the block in protein-E production occurred in each individual, the various intermediates were given to each individuals cel Is in culture. After a few weeks of growth with the intermediate, the cells were assayed for the production of protein E. The results for each individuals cells are given in the following table. A plus sign means that protein E was produced after the cells were given the intermediate listed at the top of the column. A minus sign means that the cells still could not produce protein E even after being exposed to the intermediate at the top of the column. Draw the pathway leading to the production of protein E.
Distinguishing the Mechanisms of Class I and Class I Aldolases Fructose bisphosphate aldolase in animal muscle is a class 1 aldolase, which forms a Schiff base intermediate between substrate (for example. fructose-1, 6-bisphosphate or dihydroxyacetone phosphate) and a lysine at the active site (see Figure I8.12). The chemical evidence for this intermediate conies from studies with aldolase and the reducing agent sodium borohydride, NaBH4. Incubation of the enzyme with dihydroxyacetone phosphate and NaBH4 inactivates the enzyme. Interestingly, no inactivation is observed if NabH4 is added to the enzyme in the absence of substrate. Write a mechanism that explains these observations and provides evidence for the formation of a Schiff base intermediate in the aldolase reaction.
MATHEMATICAL The enzyme -methylaspartase catalyzes the deamination of -methylaspartate [V. Williams and J. Selbin, J. Biol. Chem. 239, 1636 (1964)]. The rate of the reaction was determined by monitoring the absorbance of the product at 240 nm(A240). From the data in the following table, determine KM for the reaction. How does the method of calculation differ from that in Questions 26 and 27?
Which of the following analogies best describes the induced-fit model of enzyme-substrate binding? a hug between two people a key fitting into a lock a square peg fitting through the square bole and a round peg fitting through the round hole of a children’s toy the fitting together of two jigsaw puzzle pieces
Amino acids are not stored in the body. Describe how excess amino acids are processed in the cell.
AB+CDAD+BE Is this a legitimate example of an exchange reaction? Why or why not?
Which of the following statements about the allosteric site is true? a. The allosteric site is a second active site on a substrate in a metabolic pathway. b. The allosteric site on an enzyme can allow the product of a metabolic pathway to inhibit that enzyme and stop the pathway. c. When the allosteric site of an enzyme is occupied, the reaction is irreversible and the enzyme cannot react again. d. An allosteric activator prevents binding at the active site. e. An enzyme that possesses allosteric sites does not possess an active site.
Energetic of Fructose-1 ,6-bis P Hydrolysis (Integrates with Chapter 3.) The standard free energy change (G) for hydrolysis of fructose-1. 6-bisphosphate (FBP) to fructose-S-phosphate (F-6-P) and P: is -16.7 KJ/mol: FBP + H2O fructose-6-P + Pi The standard free energy change (G) for ATP hydrolysis is -30.5 KJ/mol: ATP + H2O ADP + Pj What is the standard free energy change for the phosphofructokinase reaction: ATP + fructose-6-P ADP + FBP b. What is the equilibrium constant for this reaction? c. Assuming the intracellular concentrations of [ATP] and (ADP] are maintained constant at 4 mM and 1.6 mM, respectively, in a rat liver cell, what will be the ratio of [FBP]/[fructose-6-P] when the phosphofructokinase reaction reaches equilibrium?

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