a. What is the formula weight of sodium oxide? b. How many oxide ions are present in 0.25 mol sodium oxide? c. How many sodium ions are present in 0.25 mol of sodium oxide? d. How many oxide ions are present in 2.30 g of sodium oxide? e. How many sodium ions are present in 2.30 g of sodium oxide? 11. (3.79) Isovaleric acid (CsH10O2) is the molecule responsible for foot odor. To smell this compound, it must be present in the air at a minimum of 250 parts per billion. This means that a 0.50 L volume of air would hold 0.00013 g of isovaleric acid. a. To how many moles of isovaleric acid does this correspond? b. To how many molecules of isovaleric acid does this correspond?

Principles Of Pharmacology Med Assist
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ISBN:9781337512442
Author:RICE
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Chapter4: The Metric System
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Please explain question 10: a,b,c,d,e and question 11: a,b thoroughly. 

  • How would I find the formula weight of sodium oxide?
a. What is the formula weight of sodium oxide?
b. How many oxide ions are present in 0.25 mol sodium oxide?
c. How many sodium ions are present in 0.25 mol of sodium oxide?
d. How many oxide ions are present in 2.30 g of sodium oxide?
e. How many sodium ions are present in 2.30 g of sodium oxide?
11. (3.79) Isovaleric acid (CsH10O2) is the molecule responsible for foot odor. To smell this
compound, it must be present in the air at a minimum of 250 parts per billion. This means
that a 0.50 L volume of air would hold 0.00013 g of isovaleric acid.
a. To how many moles of isovaleric acid does this correspond?
b. To how many molecules of isovaleric acid does this correspond?
Transcribed Image Text:a. What is the formula weight of sodium oxide? b. How many oxide ions are present in 0.25 mol sodium oxide? c. How many sodium ions are present in 0.25 mol of sodium oxide? d. How many oxide ions are present in 2.30 g of sodium oxide? e. How many sodium ions are present in 2.30 g of sodium oxide? 11. (3.79) Isovaleric acid (CsH10O2) is the molecule responsible for foot odor. To smell this compound, it must be present in the air at a minimum of 250 parts per billion. This means that a 0.50 L volume of air would hold 0.00013 g of isovaleric acid. a. To how many moles of isovaleric acid does this correspond? b. To how many molecules of isovaleric acid does this correspond?
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