12. Show the final data and tags of the two levels of cache, the given memory contents and data access sequence. Consider 5-bit memory addresses and single byte instructions. Assume that the L1 caches are direct mapped and the L2 cache is fully associative, using LRU for replacement. All caches can place a single byte of data in each block. Also assume that addresses greater than 19 contain instructions whereas addresses smaller than 19 contain data. Access Seq. Op. Adr. FETCH 20 LDRB 15 FETCH 30 LDRB 16 FETCH 31 LDRB 15 FETCH 20 LDRB 17 FETCH 28 LDRB 15 FETCH 30 Tag Tag L1(Instruction) miss rate= LII Cache Data LID Cache Data Tag L1(Data) miss rate= L2 Cache Data L2 miss rate= Memory Adr. Data 14 101 15 126 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 3 86 2 91 5 7 13 4 42 0 76 12 3 29 17

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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12. Show the final data and tags of the two levels of cache, the given memory contents and data access
sequence. Consider 5-bit memory addresses and single byte instructions. Assume that the L1 caches are
direct mapped and the L2 cache is fully associative, using LRU for replacement. All caches can place a
single byte of data in each block. Also assume that addresses greater than 19 contain instructions
whereas addresses smaller than 19 contain data.
Access Seq.
Op. Adr.
FETCH 20
LDRB 15
FETCH 30
LDRB 16
FETCH 31
LDRB 15
FETCH 20
LDRB 17
FETCH 28
LDRB
15
FETCH 30
Tag
Tag
L1(Instruction) miss rate=
LII Cache
Data
LID Cache
Data
L2 Cache
Tag Data
L1(Data) miss rate =
L2 miss rate=
Memory
Adr. Data
14
101
15
126
16
3
17
86
18
2
19
20
21
22
23
24
25
26
27
28
29
30
31
91
5
66
7
13
4
42
0
76
12
3
29
17
Transcribed Image Text:12. Show the final data and tags of the two levels of cache, the given memory contents and data access sequence. Consider 5-bit memory addresses and single byte instructions. Assume that the L1 caches are direct mapped and the L2 cache is fully associative, using LRU for replacement. All caches can place a single byte of data in each block. Also assume that addresses greater than 19 contain instructions whereas addresses smaller than 19 contain data. Access Seq. Op. Adr. FETCH 20 LDRB 15 FETCH 30 LDRB 16 FETCH 31 LDRB 15 FETCH 20 LDRB 17 FETCH 28 LDRB 15 FETCH 30 Tag Tag L1(Instruction) miss rate= LII Cache Data LID Cache Data L2 Cache Tag Data L1(Data) miss rate = L2 miss rate= Memory Adr. Data 14 101 15 126 16 3 17 86 18 2 19 20 21 22 23 24 25 26 27 28 29 30 31 91 5 66 7 13 4 42 0 76 12 3 29 17
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