1. An electrochemical cell consist of 0.2715 Ibs of MnO2, and 0.2524 Ibs of PbO2. A current flow through a 1.1 ohm resistor of electrochemical cell for 45 mins. The reaction takes place at 400k and the total volume of the solution is 504.9 cm^3. Use the standard reduction cell potential table for MnO2 and PbO2: concentration of Mn2+ (2.81 M) and PbO2 (0.95 M) Cell Potential E=0.48 V current when it passes through a 1.1 ohm resistor = 0.44 ampere   Determine the following: a. quantity of electricity/charge, Q b. Energy consumed in Joules c. Power in Kilowatts

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