Chapter F, Problem G.16E

(a)

Interpretation Introduction

Interpretation:

Molarity of ${\text{CuSO}}_{\text{4}}$ in the final solution prepared has to be calculated.

Concept Introduction:

Dilution is addition of water to a substance that is soluble in water.  This process does not change the number of solute particles present in the solution, instead the concentration of the solution is alone changed.  Dilution increases the volume of solution.

Molarity of the solution is defined as the number of moles of solute that is dissolved in the volume of solution in liters.  Unit of molarity is $\text{mol}\cdot {\text{L}}^{-1}$.  The equation for molarity is given as follows;

    $\text{Molarity (M)}=\frac{\text{Amount of solute in moles}}{\text{Volume of solution in liters}}$

(b)

Interpretation Introduction

Interpretation:

Mass of ${\text{CuSO}}_{\text{4}}\cdot {\text{5H}}_{\text{2}}\text{O}$ that has to be weighed directly to make $\text{250}\text{.0}\text{mL}$ of solution has to be calculated.