Explanation The number of atoms of silicon in the left pan is seven. Number of moles of silicon atoms is calculated as shown below; 7 atoms of silicon = 7 atoms×1 mol 6 .0221×10 23 atoms = 1.16 × 10 − 23 mol Therefore, moles of silicon is 1.16 × 10 − 23 mol . From this the mass of silicon atoms is calculated as follows; Mass of gallium = Number of moles of Gallium×Molar mass of gallium = 1.16 × 10 − 23 mol × 28 g ⋅ mol − 1 = 32.48 × 10 − 23 g Therefore, 32.48 × 10 − 23 g is the mass on the left pan. In order to make the mass equal on both pans, the pan that contain lithium atoms must have mass of 32.48 × 10 − 23 g

ACHIEVE/CHEMICAL PRINCIPLES ACCESS 2TERM

7th Edition

ISBN: 9781319403959

Author: ATKINS

Publisher: MAC HIGHER

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Chapter F, Problem E.4E

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The number of lithium atoms that has to be present in the right pan has to be calculated in order to make the mass of two pans equal has to be calculated.

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Chapter F, Problem E.3E

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Chapter F Solutions

ACHIEVE/CHEMICAL PRINCIPLES ACCESS 2TERM

Ch. F - Prob. A.1AST Ch. F - Prob. A.1BST Ch. F - Prob. A.2AST Ch. F - Prob. A.2BST Ch. F - Prob. A.3AST Ch. F - Prob. A.3BST Ch. F - Prob. A.4AST Ch. F - Prob. A.4BST Ch. F - Prob. A.5AST Ch. F - Prob. A.5BST

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The number of lithium atoms that has to be present in the right pan has to be calculated in order to make the mass of two pans equal has to be calculated.

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Interpretation: The number of lithium atoms that has to be present in the right pan has to be calculated in order to make the mass of two pans equal has to be calculated.

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Chapter F Solutions

Interpretation:

The number of lithium atoms that has to be present in the right pan has to be calculated in order to make the mass of two pans equal has to be calculated.