Microbiology: A Systems Approach
4th Edition
ISBN: 9780073402437
Author: Marjorie Kelly Cowan Professor
Publisher: McGraw-Hill Education
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Chapter 9.5, Problem 19AYP
Summary Introduction
To define:
The term mutation and also give one positive and negative example of it in microorganisms.
Introduction:
Mutation in an organism is defined as a sudden alteration of “
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Chapter 9 Solutions
Microbiology: A Systems Approach
Ch. 9.1 - Define the terms genome and gene.Ch. 9.1 - Differentiate between genotype and phenotype.Ch. 9.1 - Diagram a segment of DNA, labeling all important...Ch. 9.1 - Summarize the steps of bacterial DNA replication...Ch. 9.1 - Compare and contrast the synthesis of leading and...Ch. 9.2 - Explain how the classical view of the central...Ch. 9.2 - Prob. 7AYPCh. 9.2 - Illustrate the steps of transcription, noting the...Ch. 9.2 - Prob. 9AYPCh. 9.2 - Prob. 10AYP
Ch. 9.2 - Identify the locations of the promoter, the start...Ch. 9.2 - Prob. 12AYPCh. 9.2 - Prob. 13AYPCh. 9.3 - Define the term operon and explain one advantage...Ch. 9.3 - Differentiate between repressive and inducible...Ch. 9.3 - Prob. 16AYPCh. 9.4 - Explain the defining characteristics of a...Ch. 9.4 - Describe three forms of horizontal gene transfer...Ch. 9.5 - Prob. 19AYPCh. 9.5 - Prob. 20AYPCh. 9 - Prob. 1CFCh. 9 - What is the smallest unit of heredity? a....Ch. 9 - The nitrogen bases in DNA are bonded to the a....Ch. 9 - DNA replication is semiconservative because the...Ch. 9 - In DNA, adenine is the complementary base for...Ch. 9 - Transfer RNA is the molecule that a. contributes...Ch. 9 - Prob. 6MCQCh. 9 - The lac operon is usually in the _____ position...Ch. 9 - Prob. 8MCQCh. 9 - Prob. 9MCQCh. 9 - When genes are turned on differently under...Ch. 9 - The DNA pairs are held together primarily by...Ch. 9 - Prob. 12TFCh. 9 - Prob. 13TFCh. 9 - Prob. 14TFCh. 9 - Prob. 15TFCh. 9 - Explain the relationship among the following...Ch. 9 - Prob. 2CTQCh. 9 - On paper, replicate the following segment of DNA:...Ch. 9 - Provide evidence in support of or refuting the...Ch. 9 - Prob. 5CTQCh. 9 - Prob. 6CTQCh. 9 - Prob. 7CTQCh. 9 - Prob. 8CTQCh. 9 - Prob. 9CTQCh. 9 - Use your knowledge of DNA recombination events to...Ch. 9 - Prob. 1CCCh. 9 - Prob. 2CCCh. 9 - Prob. 3CCCh. 9 - Prob. 1VCCh. 9 - From chapter 4, figure 4.11a. Speculate on why...Ch. 9 - Concept Mapping | Blooms Level 6: Create Appendix...
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- You implant an FGF10-coated bead into the anterior flank of a chicken embryo, directly below the level of the wing bud. What is the phenotype of the resulting ectopic limb? Briefly describe the expected expression domains of 1) Shh, 2) Tbx4, and 3) Tbx5 in the resulting ectopic limb bud.arrow_forwardDesign a grafting experiment to determine if limb mesoderm determines forelimb / hindlimb identity. Include the experiment, a control, and an interpretation in your answer.arrow_forwardThe Snapdragon is a popular garden flower that comes in a variety of colours, including red, yellow, and orange. The genotypes and associated phenotypes for some of these flowers are as follows: aabb: yellow AABB, AABb, AaBb, and AaBB: red AAbb and Aabb: orange aaBB: yellow aaBb: ? Based on this information, what would the phenotype of a Snapdragon with the genotype aaBb be and why? Question 21 options: orange because A is epistatic to B yellow because A is epistatic to B red because B is epistatic to A orange because B is epistatic to A red because A is epistatic to B yellow because B is epistatic to Aarrow_forward
- A sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation? The cell membranes are more resistant than normal. An isotonic solution had been added instead of water. A solution of 0.1 M NaCl had been added instead of water. Not enough water had been added to the red blood cell pellet. The man had sickle-cell anaemia.arrow_forwardA sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation? The cell membranes are more resistant than normal. An isotonic solution had been added instead of water. A solution of 0.1 M NaCl had been added instead of water. Not enough water had been added to the red blood cell pellet. The man had sickle-cell anaemia.arrow_forwardWith reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobinarrow_forward
- With reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobinarrow_forwardWhich ONE of the following is FALSE regarding haemoglobin? It has two alpha subunits and two beta subunits. The subunits are joined by disulphide bonds. Each subunit covalently binds a haem group. Conformational change in one subunit can be transmitted to another. There are many variant ("mutant") forms of haemoglobin that are not harmful.arrow_forwardWhich ONE of the following is FALSE regarding haemoglobin? It has two alpha subunits and two beta subunits. The subunits are joined by disulphide bonds. Each subunit covalently binds a haem group. Conformational change in one subunit can be transmitted to another. There are many variant ("mutant") forms of haemoglobin that are not harmful.arrow_forward
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Mitochondrial mutations; Author: Useful Genetics;https://www.youtube.com/watch?v=GvgXe-3RJeU;License: CC-BY