THERMODYNAMICS (LL)-W/ACCESS >CUSTOM<
9th Edition
ISBN: 9781266657610
Author: CENGEL
Publisher: MCG CUSTOM
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Chapter 9.12, Problem 195FEP
To determine
The thermal efficiency of the ideal diesel cycle.
- (a)
- (b)
- (c)
- (d)
- (e)
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(9) Figure Q9 shows a 2 m long symmetric I beam where the upper and lower sections are 2X wide and the middle section is X wide, where X
is 31 mm. The I beam sections are all Y=33 mm in depth. The beam is loaded in the middle with a load of Z=39 kN causing reaction forces at
either end of the beam's supports.
What is the maximum (positive) bending stress experienced in the beam in terms of mega-Pascals?
State your answer to the nearest whole number.
Y mm
Y mm
Y mm
Xmm
2X mm
Figure Q9
Z KN
2 m
(5) Figure Q5 shows a beam which rests on two pivots at positions A and C (as illustrated below). The beam is loaded with a UDL of 100 kN/m
spanning from position B and ending at position D (as illustrated). The start location of B is Y=1.2 m from A. The total span of the UDL is
twice the length of Z, where Z=2.2 m.
What is the bending moment value at position X=2.5 m, (using the convention given to you in the module's formula book).
State your answer in terms of kilo-Newton-metres to 1 decimal place.
Bending Moment
Value?
UDL = 100 kN/m
A
Ym
X = ?
B
Zm
Figure Q5
C
*
Zm
D
You are required to state your answer in millimetres to the nearest whole number.
30 mm
30 mm
A. No Valid Answer
B. 27
○ C. 26
O D.33
○ E. 34
30 mm
50 mm
Figure Q14
1m
Chapter 9 Solutions
THERMODYNAMICS (LL)-W/ACCESS >CUSTOM<
Ch. 9.12 - What are the air-standard assumptions?Ch. 9.12 - What is the difference between air-standard...Ch. 9.12 - Prob. 3PCh. 9.12 - How does the thermal efficiency of an ideal cycle,...Ch. 9.12 - How are the combustion and exhaust processes...Ch. 9.12 - What does the area enclosed by the cycle represent...Ch. 9.12 - Prob. 7PCh. 9.12 - Can the mean effective pressure of an automobile...Ch. 9.12 - What is the difference between spark-ignition and...Ch. 9.12 - Prob. 10P
Ch. 9.12 - Prob. 11PCh. 9.12 - Can any ideal gas power cycle have a thermal...Ch. 9.12 - Prob. 13PCh. 9.12 - Prob. 14PCh. 9.12 - Prob. 15PCh. 9.12 - Prob. 16PCh. 9.12 - Prob. 17PCh. 9.12 - Prob. 18PCh. 9.12 - Prob. 19PCh. 9.12 - Repeat Prob. 919 using helium as the working...Ch. 9.12 - The thermal energy reservoirs of an ideal gas...Ch. 9.12 - Consider a Carnot cycle executed in a closed...Ch. 9.12 - Consider a Carnot cycle executed in a closed...Ch. 9.12 - What four processes make up the ideal Otto cycle?Ch. 9.12 - Are the processes that make up the Otto cycle...Ch. 9.12 - How do the efficiencies of the ideal Otto cycle...Ch. 9.12 - How does the thermal efficiency of an ideal Otto...Ch. 9.12 - Why are high compression ratios not used in...Ch. 9.12 - An ideal Otto cycle with a specified compression...Ch. 9.12 - Prob. 30PCh. 9.12 - Prob. 31PCh. 9.12 - Determine the mean effective pressure of an ideal...Ch. 9.12 - Reconsider Prob. 932E. Determine the rate of heat...Ch. 9.12 - An ideal Otto cycle has a compression ratio of 8....Ch. 9.12 - Prob. 36PCh. 9.12 - A spark-ignition engine has a compression ratio of...Ch. 9.12 - An ideal Otto cycle has a compression ratio of 7....Ch. 9.12 - Prob. 39PCh. 9.12 - An ideal Otto cycle with air as the working fluid...Ch. 9.12 - Repeat Prob. 940E using argon as the working...Ch. 9.12 - Someone has suggested that the air-standard Otto...Ch. 9.12 - Repeat Prob. 942 when isentropic processes are...Ch. 9.12 - Prob. 44PCh. 9.12 - Prob. 45PCh. 9.12 - Prob. 46PCh. 9.12 - Prob. 47PCh. 9.12 - Prob. 48PCh. 9.12 - Prob. 49PCh. 9.12 - Prob. 50PCh. 9.12 - Prob. 51PCh. 9.12 - Prob. 52PCh. 9.12 - Prob. 53PCh. 9.12 - Prob. 54PCh. 9.12 - Prob. 55PCh. 9.12 - Prob. 56PCh. 9.12 - Prob. 57PCh. 9.12 - Repeat Prob. 957, but replace the isentropic...Ch. 9.12 - Prob. 60PCh. 9.12 - Prob. 61PCh. 9.12 - The compression ratio of an ideal dual cycle is...Ch. 9.12 - Repeat Prob. 962 using constant specific heats at...Ch. 9.12 - Prob. 65PCh. 9.12 - Prob. 66PCh. 9.12 - Prob. 67PCh. 9.12 - An air-standard cycle, called the dual cycle, with...Ch. 9.12 - Prob. 69PCh. 9.12 - Prob. 70PCh. 9.12 - Consider the ideal Otto, Stirling, and Carnot...Ch. 9.12 - Consider the ideal Diesel, Ericsson, and Carnot...Ch. 9.12 - An ideal Ericsson engine using helium as the...Ch. 9.12 - An ideal Stirling engine using helium as the...Ch. 9.12 - Prob. 75PCh. 9.12 - Prob. 76PCh. 9.12 - Prob. 77PCh. 9.12 - Prob. 78PCh. 9.12 - Prob. 79PCh. 9.12 - For fixed maximum and minimum temperatures, what...Ch. 9.12 - What is the back work ratio? What are typical back...Ch. 9.12 - Why are the back work ratios relatively high in...Ch. 9.12 - How do the inefficiencies of the turbine and the...Ch. 9.12 - A simple ideal Brayton cycle with air as the...Ch. 9.12 - A stationary gas-turbine power plant operates on a...Ch. 9.12 - A gas-turbine power plant operates on the simple...Ch. 9.12 - Prob. 87PCh. 9.12 - Prob. 88PCh. 9.12 - Repeat Prob. 988 when the isentropic efficiency of...Ch. 9.12 - Repeat Prob. 988 when the isentropic efficiency of...Ch. 9.12 - Repeat Prob. 988 when the isentropic efficiencies...Ch. 9.12 - Air is used as the working fluid in a simple ideal...Ch. 9.12 - An aircraft engine operates on a simple ideal...Ch. 9.12 - Repeat Prob. 993 for a pressure ratio of 15.Ch. 9.12 - A gas-turbine power plant operates on the simple...Ch. 9.12 - A simple ideal Brayton cycle uses argon as the...Ch. 9.12 - A gas-turbine power plant operates on a modified...Ch. 9.12 - A gas-turbine power plant operating on the simple...Ch. 9.12 - Prob. 99PCh. 9.12 - Prob. 100PCh. 9.12 - Prob. 101PCh. 9.12 - Prob. 102PCh. 9.12 - Prob. 103PCh. 9.12 - Prob. 104PCh. 9.12 - A gas turbine for an automobile is designed with a...Ch. 9.12 - Rework Prob. 9105 when the compressor isentropic...Ch. 9.12 - A gas-turbine engine operates on the ideal Brayton...Ch. 9.12 - An ideal regenerator (T3 = T5) is added to a...Ch. 9.12 - Prob. 109PCh. 9.12 - Prob. 111PCh. 9.12 - A Brayton cycle with regeneration using air as the...Ch. 9.12 - Prob. 113PCh. 9.12 - Prob. 114PCh. 9.12 - Prob. 115PCh. 9.12 - Prob. 116PCh. 9.12 - Prob. 117PCh. 9.12 - Prob. 118PCh. 9.12 - Prob. 119PCh. 9.12 - Prob. 120PCh. 9.12 - A simple ideal Brayton cycle without regeneration...Ch. 9.12 - A simple ideal Brayton cycle is modified to...Ch. 9.12 - Consider a regenerative gas-turbine power plant...Ch. 9.12 - Repeat Prob. 9123 using argon as the working...Ch. 9.12 - Consider an ideal gas-turbine cycle with two...Ch. 9.12 - Repeat Prob. 9125, assuming an efficiency of 86...Ch. 9.12 - A gas turbine operates with a regenerator and two...Ch. 9.12 - Prob. 128PCh. 9.12 - Prob. 129PCh. 9.12 - Prob. 130PCh. 9.12 - Prob. 131PCh. 9.12 - Air at 7C enters a turbojet engine at a rate of 16...Ch. 9.12 - Prob. 133PCh. 9.12 - A turbojet is flying with a velocity of 900 ft/s...Ch. 9.12 - A pure jet engine propels an aircraft at 240 m/s...Ch. 9.12 - A turbojet aircraft is flying with a velocity of...Ch. 9.12 - Prob. 137PCh. 9.12 - Prob. 138PCh. 9.12 - Reconsider Prob. 9138E. How much change would...Ch. 9.12 - Consider an aircraft powered by a turbojet engine...Ch. 9.12 - An ideal Otto cycle has a compression ratio of 8....Ch. 9.12 - An air-standard Diesel cycle has a compression...Ch. 9.12 - Prob. 144PCh. 9.12 - Prob. 145PCh. 9.12 - Prob. 146PCh. 9.12 - Prob. 147PCh. 9.12 - A Brayton cycle with regeneration using air as the...Ch. 9.12 - Prob. 150PCh. 9.12 - A gas turbine operates with a regenerator and two...Ch. 9.12 - A gas-turbine power plant operates on the...Ch. 9.12 - Prob. 153PCh. 9.12 - An air-standard cycle with variable specific heats...Ch. 9.12 - Prob. 155RPCh. 9.12 - Prob. 156RPCh. 9.12 - Prob. 157RPCh. 9.12 - Prob. 158RPCh. 9.12 - Prob. 159RPCh. 9.12 - Prob. 160RPCh. 9.12 - Prob. 161RPCh. 9.12 - Consider an engine operating on the ideal Diesel...Ch. 9.12 - Repeat Prob. 9162 using argon as the working...Ch. 9.12 - Prob. 164RPCh. 9.12 - Prob. 165RPCh. 9.12 - Prob. 166RPCh. 9.12 - Prob. 167RPCh. 9.12 - Consider an ideal Stirling cycle using air as the...Ch. 9.12 - Prob. 169RPCh. 9.12 - Consider a simple ideal Brayton cycle with air as...Ch. 9.12 - Prob. 171RPCh. 9.12 - A Brayton cycle with a pressure ratio of 15...Ch. 9.12 - Helium is used as the working fluid in a Brayton...Ch. 9.12 - Consider an ideal gas-turbine cycle with one stage...Ch. 9.12 - Prob. 176RPCh. 9.12 - Prob. 177RPCh. 9.12 - Prob. 180RPCh. 9.12 - Prob. 181RPCh. 9.12 - Prob. 182RPCh. 9.12 - For specified limits for the maximum and minimum...Ch. 9.12 - A Carnot cycle operates between the temperature...Ch. 9.12 - Prob. 194FEPCh. 9.12 - Prob. 195FEPCh. 9.12 - Helium gas in an ideal Otto cycle is compressed...Ch. 9.12 - Prob. 197FEPCh. 9.12 - Prob. 198FEPCh. 9.12 - In an ideal Brayton cycle, air is compressed from...Ch. 9.12 - In an ideal Brayton cycle, air is compressed from...Ch. 9.12 - Consider an ideal Brayton cycle executed between...Ch. 9.12 - An ideal Brayton cycle has a net work output of...Ch. 9.12 - In an ideal Brayton cycle with regeneration, argon...Ch. 9.12 - In an ideal Brayton cycle with regeneration, air...Ch. 9.12 - Consider a gas turbine that has a pressure ratio...Ch. 9.12 - An ideal gas turbine cycle with many stages of...
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- A beam supports a uniform load and an axial load P = 30 kips. If the maximum allowable tensile stress in the beam is 24 ksi and a maximum allowable compressive stress is 20 ksi, what uniform load can the beam support? Assume P passes through the centroid of the section.arrow_forwardBending Moment Value? 40 kN 100 kN 100 kN 100 kN 40 kN A B C D E Ym Zm Zm Ym X = ?arrow_forward(4) Figure Q4 shows a symmetrically loaded beam. The beam is loaded at position A (x = 0 m) and the end of the beam at position E with 30 kN. There is an additional load of 101 kN both at position B (Y = 0.87 m), in the middle at C and at position D. The middle section is 2Z, where Z = 0.82 m). Given that the reaction forces at RB and RD both equal 180 kN, calculate the Bending Moment value (using the convention given to you in the module's formula book) at a position of x=2.30m. State your answer in terms of kilo-Newton-metres to one decimal place. Bending Moment Value? 40 kN 100 kN 100 kN 100 kN 40 kN B D E Ym Zm Zm Ym X = ? Figure Q4arrow_forward
- (8) Figure Q8 shows a T cross-section of a T beam which is constructed from three metal plates each having a width of 12 mm and sectional engths of X=72 mm, Y=65 mm and Z=88 mm, where the plates are used for the web section, and the two flange sections respectively, as llustrated in Figure Q8. Calculate the neutral axis of the T-beam cross-section (as measured from the base) in units of millimetres, stating your answer to the nearest 1 decimal place. Z mm Y mm 12 mm X mm Figure Q8 12 mm 12 mmarrow_forward(10) A regular cross-section XXY mm beam, where X-94 m and Y=62 m and 1800 mm long, is loaded from above in the middle with a load of Z=2 kN causing a compressive Bending Stress at the top of the beam and tensile Bending Stress at the bottom of the beam. The beam in addition experiences a tensile end loading in order to reduce the compressive stress in the beam to a near zero value. The configuration of the beam is illustrated in Figure Q10. Calculate the end loading force required in order to reduce total compressive stress experienced in the beam to be near zero? State your answer to the nearest 1 decimal place in terms of kilo-Newtons. Z kN Y mm 1800 mm X mm ? KN Figure Q10 ? KNarrow_forward(12) Figure Q12 shows a framework consisting of 3 upward pointing isosceles triangles and 2 downward pointing isosceles triangles. The framework is loaded at joint F with a downward force of 20 kN. The applied force causes a vertical reaction force at A and D. The design of the framework is such that horizontal base of the isosceles triangles form an angle of 30° degrees with the diagonal members. You are asked to find the internal force in member AE in kilo-Newtons to 1 decimal place (using the standard sign convention given in the module formula booklet)? Select the valid option from the list below. E F S 20 kN RAX = ?? KN 30° 30° 30° 30° 30° 30° A H H B D RAV = ?? KN Roy = ?? KN A. The solution to the problem is found to be -20.0 kN. ○ B. The solution to the problem is found to be -10.0 kN. ○ C. The solution to the problem is found to be +11.5 kN. OD. The solution to the problem is found to be +23.1 kN. O E. No Valid Answerarrow_forward
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