Interpretation:
Reason for the compound undergoes
Concept Introduction:
The
The first step of
Frist step is the slow step also rate determining step so the rate of the reaction is depends on the concentration of substrate only.
Nucleophile attacks the both front and back side of carbocation in
Order of the substrate that favored in
Structure of the substrate plays a major role in
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Chapter 9 Solutions
Organic Chemistry
- Bicyclo-2,5-heptadiene can be prepared in two steps from cyclopentadiene and vinyl chloride. Provide a mechanism for each step.arrow_forwardTwo substitution products result from the reaction between 3-chloro-3-methyl-1- butene with sodium acetate (CH3COO – Na +) in acetic acid under SN1. Identify the products.arrow_forwardTreatment of 1,3-dichloropropane with potassium cyanide results in the formation of pentanedinitrile. The rate of this reaction is about 1000 times greater in DMSO than in ethanol. Account for this difference in rate. CI + 2 KCN NC + 2 KCI CN 1,3-Dichloropropane Pentanedinitrilearrow_forward
- When the alkyl bromides (listed here) were subjected to hydrolysis in a mixture of ethanol and water (80% EtOH/20% H2O) at 55 °C, the rates of the reaction showed the following order: (CH3)3CBR > CH3Br > CH3CH2Br > (CH3)2CHBR Provide an explanation for this order of reactivity.arrow_forwardAlkylation of benzene with 1-chlorobutane in the presence of AlCl3 gave not only the expected butylbenzene product but also, as a major product, (1-methylpropyl)benzene. Write an equation for the reaction Propose a mechanism to account for the formation of butylbenzene Propose a mechanism to account for the formation of (1-methylpropyl)benzenearrow_forwardTributyltin hydride (Bu3SnH) is used synthetically to reduce alkyl halides, replacing a halogen atom with hydrogen. Free-radical initiators promote this reaction, and free-radical inhibitors are known to slow or stop it. Your job is todevelop a mechanism,arrow_forward
- Ethane reacts with chlorine (Cl2) in the presence of ultra-violet (UV) light, to produce 1-chloropropane (CH3CH2Cl) and hydrogen bromide (HCl). As shown in the equation below. CH3CH3 + Cl2 → CH3CH2Cl + HCl Describe the reaction mechanism of the reaction between ethane and chlorine to produce 1-chloroethane. The description should be detailed and must include the type of bond fission that takes place. You may sketch and insert suitable diagrams to aid your description if you wish. Would this reaction (question 34(c)) give a high yield of 1-chloroethanearrow_forwardEthane reacts with chlorine (Cl2) in the presence of ultra-violet (UV) light, to produce 1-chloropropane (CH3CH2Cl) and hydrogen bromide (HCl). As shown in the equation below. CH3CH3 + Cl2 → CH3CH2Cl + HCl Describe the reaction mechanism of the reaction between ethane and chlorine to produce 1-chloroethane. The description should be detailed and must include the type of bond fission that takes placearrow_forwardEthane reacts with chlorine (Cl2) in the presence of ultra-violet (UV) light, to produce 1-chloropropane (CH3CH2Cl) and hydrogen bromide (HCl). As shown in the equation below. CH3CH3 + Cl2 → CH3CH2Cl + HCl Describe the reaction mechanism of the reaction between ethane and chlorine to produce 1-chloroethane. The description should be detailed and must include the type of bond fission that takes place. You may sketch and insert suitable diagrams to aid your description if you wish.arrow_forward
- The reaction of (2S)-2-chloro-3-methylpentane with sodium iodide yields two products: (2R)-2-iodo-3-methylpentane and racemic 3-iodo-2-methylpentane. Account for the formation of each of these two products. For each product, you should show how it is formed and what that tells you about the mechanism of that specific reaction.arrow_forwardAddition of HBr to 3,3-dimethyl-1-butene gives a mixture of two isomeric alkyl bromide products. Draw structures for the two products, and give a mechanistic explanation for their formation.arrow_forwardThe relative rates of reaction of ethane, toluene, and ethylbenzene with bromine atoms have been measured. The most reactive hydrocarbon undergoes hydrogen atom abstraction a million times faster than does the least reactive one. Arrange these hydrocarbons order of decreasing reactivity.arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning