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Concept explainers
(a)
Interpretation:
The formulas of the ionic compounds that will form from the pairs of elements potassium and sulfur, potassium and chlorine have to be determined. Also, the pair among potassium and sulfur, potassium and chlorine that has the greater lattice energy has to be explained.
Concept Introduction:
Lattice energy is used to determine the bond strength in ionic compounds. It is the heat of formation for ions of opposite charge in the gaseous phase combine to form an ionic solid.
Lattice energy is the energy required to separate a mole of an ionic solid into gaseous ions. It cannot be measured empirically but it can be estimated by the Born-Haber cycle.
The two main factors responsible for the magnitude of the lattice energy are the charge and radius of the bonded ions. The effect of those factors is as follows:
1. If the charge of the ions increases, the lattice energy increases.
2. If the size of the ions increases, the lattice energy decreases.
The magnitude of the lattice energy for any given ionic solid is determined by equation written as follows:
Here,
(b)
Interpretation:
The formulas of the ionic compounds that will form from the pairs of elements lithium and fluorine, rubidium and chlorine have to be determined. Also, the pair among potassium and sulfur, potassium and chlorine that has the greater lattice energy has to be explained.
Concept Introduction:
Refer to part (a).
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Chapter 9 Solutions
Chemistry Principles And Practice
- 1. For the four structures provided, Please answer the following questions in the table below. a. Please draw π molecular orbital diagram (use the polygon-and-circle method if appropriate) and fill electrons in each molecular orbital b. Please indicate the number of π electrons c. Please indicate if each molecule provided is anti-aromatic, aromatic, or non- aromatic TT MO diagram Number of π e- Aromaticity Evaluation (X choose one) Non-aromatic Aromatic Anti-aromatic || ||| + IVarrow_forward1.3 grams of pottasium iodide is placed in 100 mL of o.11 mol/L lead nitrate solution. At room temperature, lead iodide has a Ksp of 4.4x10^-9. How many moles of precipitate will form?arrow_forwardQ3: Circle the molecules that are optically active: ДДДДarrow_forward
- 6. How many peaks would be observed for each of the circled protons in the compounds below? 8 pts CH3 CH3 ΤΙ A. H3C-C-C-CH3 I (₁₁ +1)= 7 H CI B. H3C-C-CI H (3+1)=4 H LIH)=2 C. (CH3CH2-C-OH H D. CH3arrow_forwardNonearrow_forwardQ1: Draw the most stable and the least stable Newman projections about the C2-C3 bond for each of the following isomers (A-C). Are the barriers to rotation identical for enantiomers A and B? How about the diastereomers (A versus C or B versus C)? H Br H Br (S) CH3 (R) CH3 H3C (S) H3C H Br Br H A C enantiomers H Br H Br (R) CH3 H3C (R) (S) CH3 H3C H Br Br H B D identicalarrow_forward
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