Aspartame is an artificial sweetener marketed under the name Nutra-Sweet. A partial Lewis structure for aspartame is shown below. Aspartame can be classified as an organic compound (a compound based on carbon atoms). The majority of Lewis structures for simple organic compounds have all atoms with a formal charge of zero. Therefore, add lone pairs and multiple bonds to the structure above to give each atom a formal charge of zero when drawing the Lewis structure. Also note that the six-sided ring is shorthand notation for a benzene ring (—C 6 H 5 ). Benzene is discussed in Section 4-7. Complete the Lewis structure for aspartame. How many C and N atoms exhibit sp 1 hybridization? How many C and O atoms exhibit sp 3 hybridization? How many σ and π bonds are in aspartame?
Aspartame is an artificial sweetener marketed under the name Nutra-Sweet. A partial Lewis structure for aspartame is shown below. Aspartame can be classified as an organic compound (a compound based on carbon atoms). The majority of Lewis structures for simple organic compounds have all atoms with a formal charge of zero. Therefore, add lone pairs and multiple bonds to the structure above to give each atom a formal charge of zero when drawing the Lewis structure. Also note that the six-sided ring is shorthand notation for a benzene ring (—C 6 H 5 ). Benzene is discussed in Section 4-7. Complete the Lewis structure for aspartame. How many C and N atoms exhibit sp 1 hybridization? How many C and O atoms exhibit sp 3 hybridization? How many σ and π bonds are in aspartame?
Solution Summary: The author explains the Lewis structure for aspertame and the hybridization of the carbon nitrogen and oxygen atoms present.
Aspartame is an artificial sweetener marketed under the name Nutra-Sweet. A partial Lewis structure for aspartame is shown below.
Aspartame can be classified as an organic compound (a compound based on carbon atoms). The majority of Lewis structures for simple organic compounds have all atoms with a formal charge of zero. Therefore, add lone pairs and multiple bonds to the structure above to give each atom a formal charge of zero when drawing the Lewis structure. Also note that the six-sided ring is shorthand notation for a benzene ring (—C6H5). Benzene is discussed in Section 4-7. Complete the Lewis structure for aspartame. How many C and N atoms exhibit sp1 hybridization? How many C and O atoms exhibit sp3 hybridization? How many σ and π bonds are in aspartame?
Here are the energies (in kcal/mol) for staggered and eclipsed interactions
for CH, CC, and CBr bonds
eclipsed (0°) staggered (60°)
bonds
CH/CH
1.0
0.0
CH/CC
1.3
0.0
Br:
CC/CC
3.0
0.9
Br
CH/CBr
1.8
0.0
CC / CBr
3.3
1.0
CBr / CBr
3.7
1.2
a) I've drawn the Newman projection for one of the staggered conformations of the molecule
above, looking down the C2-C3 bond. Draw Newman projections for the other two staggered
and the three eclipsed conformations (in order).
CH₂
H3C.
H'
H
Br
b) Calculate the relative energies for each of the conformations and write them below each
conformation.
90. Draw the stereoisomers obtained from each of the following reactions:
a.
H₂
b.
H₂
C.
H₂
Pd/C
Pd/C
Pd/C
36. The emission spectrum below for a one-electron (hydrogen-like) species in the gas
phase shows all the lines, before they merge together, resulting from transitions to the
first excited state from higher energy states. Line A has a wavelength of 434 nm.
BA
Increasing wavelength, λ
(a) What are the upper and lower principal quantum numbers corresponding to the lines
labeled A and B? (b) Identify the one-electron species that exhibits the spectrum.
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