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Concept explainers
(a)
Interpretation:
Synthesis of n-pentane from 1-Bromo propane should be shown.
Concept Introduction:
Target molecule is nothing but the desired product.
Terminal
The acetylide carbanion is a good nucleophile and can undergo nucleophilic substitution reactions (usually
3o alkyl halides are more likely to undergo elimination.
One or both of the terminal H atoms in ethylene (acetylene)
The product is also an alkyne; it can also undergo the other reactions.
(b)
Interpretation:
Synthesis of 2-pentanone from 1-Bromo propane should be shown.
Concept Introduction:
Target molecule is nothing but the desired product.
Terminal alkynes are unusual for simple hydrocarbons in that they can be deprotonated (pKa = 26) using an appropriate base to generate a carbanion.
The acetylide carbanion is a good nucleophile and can undergo nucleophilic substitution reactions (usually
3o alkyl halides are more likely to undergo elimination.
One or both of the terminal H atoms in ethylene (acetylene)
The product is also an alkyne; it can also undergo the other reactions.
(c)
Interpretation:
Synthesis of Pentanal from 1-Bromo propane should be shown.
Concept Introduction:
Target molecule is nothing but the desired product.
Terminal alkynes are unusual for simple hydrocarbons in that they can be deprotonated (pKa = 26) using an appropriate base to generate a carbanion.
The acetylide carbanion is a good nucleophile and can undergo nucleophilic substitution reactions (usually
3o alkyl halides are more likely to undergo elimination.
One or both of the terminal H atoms in ethylene (acetylene)
The product is also an alkyne; it can also undergo the other reactions.
(d)
Interpretation:
Synthesis of 1, 2-epoxypentane from 1-Bromo propane should be shown.
Concept Introduction:
Target molecule is nothing but the desired product.
Terminal alkynes are unusual for simple hydrocarbons in that they can be deprotonated (pKa = 26) using an appropriate base to generate a carbanion.
The acetylide carbanion is a good nucleophile and can undergo nucleophilic substitution reactions (usually
3o alkyl halides are more likely to undergo elimination.
One or both of the terminal H atoms in ethylene (acetylene)
The product is also an alkyne; it can also undergo the other reactions.
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Chapter 9 Solutions
Organic Chemistry; Modified MasteringChemistry with Pearson eText -- ValuePack Access Card; Study Guide and Student Solutions Manual for Organic Chemistry, Books a la Carte Edition (7th Edition)
- %Reflectance 95 90- 85 22 00 89 60 55 50 70 65 75 80 50- 45 40 WA 35 30- 25 20- 4000 3500 Date: Thu Feb 06 17:21:21 2025 (GMT-05:0(UnknownD Scans: 8 Resolution: 2.000 3000 2500 Wavenumbers (cm-1) 100- 2981.77 1734.25 2000 1500 1000 1372.09 1108.01 2359.09 1469.82 1181.94 1145.20 1017.01 958.45 886.97 820.49 668.25 630.05 611.37arrow_forwardNonearrow_forwardCH3 CH H3C CH3 H OH H3C- -OCH2CH3 H3C H -OCH3 For each of the above compounds, do the following: 1. List the wave numbers of all the IR bands in the 1350-4000 cm-1 region. For each one, state what bond or group it represents. 2. Label equivalent sets of protons with lower-case letters. Then, for each 1H NMR signal, give the 8 value, the type of splitting (singlet, doublet etc.), and the number protons it represents. of letter δ value splitting # of protons 3. Redraw the compound and label equivalent sets of carbons with lower-case letters. Then for each set of carbons give the 5 value and # of carbons it represents. letter δ value # of carbonsarrow_forward
- Nonearrow_forwardCarbohydrates- Draw out the Hawthorne structure for a sugar from the list given in class. Make sure to write out all atoms except for carbons within the ring. Make sure that groups off the carbons in the ring are in the correct orientation above or below the plane. Make sure that bonds are in the correct orientation. Include the full name of the sugar. You can draw out your curve within the text box or upload a drawing below.arrow_forwardHow many milliliters of 97.5(±0.5) wt% H2SO4 with a density of 1.84(±0.01) g/mL will you need to prepare 2.000 L of 0.110 M H2SO4? If the uncertainty in delivering H2SO4 is ±0.01 mL, calculate the absolute uncertainty in the molarity (0.110 M). Assume there is negligible uncertainty in the formula mass of H2SO4 and in the final volume (2.000 L) and assume random error.arrow_forward
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