Concept explainers
For each of the following balanced chemical equations, calculate how many grams of the product(s) would be produced by complete reaction of 0.125 mole of the first reactant.
msp;
msp;
msp;
msp;
(a)
Interpretation:
Grams of the product(s) produced by complete reaction of
Concept Introduction:
For a substance, number of moles is related to mass and molar mass of the substance as follows:
Here, m is mass of substance in g and M is molar mass of substance in g/mol.
Thus, from number of moles, mass can be calculated as follows:
Answer to Problem 13QAP
Mass of AgOH ( s ) Produced =
Mass of LiNO3 ( a q ) produced =
Explanation of Solution
According to the balanced equation, mole ratio between AgNO3 ( a q ) and AgOH ( s ) =
So, Amount of AgOH ( s ) produced =
=
Molar mass of AgOH ( s ) =
Mass of AgOH ( s ) Produced =
=
According to the balanced equation, mole ratio between AgNO3 ( a q ) and LiNO3 ( a q ) =
So, Amount of LiNO3 ( a q ) produced =
=
Molar mass of LiNO3 ( a q ) =
Mass of LiNO3 ( a q ) produced =
=
(b)
Interpretation:
Grams of the product(s) produced by complete reaction of
Concept Introduction:
For a substance, number of moles is related to mass and molar mass of the substance as follows:
Here, m is mass of substance in g and M is molar mass of substance in g/mol.
Thus, from number of moles, mass can be calculated as follows:
Answer to Problem 13QAP
Mass of AlCl3 ( a q ) produced =
Mass of CaSO4 ( s ) produced =
Explanation of Solution
According to the balanced equation, mole ratio between Al2 (SO4 )3 ( a q ) and AlCl3 ( a q ) =
So, Amount of AlCl3 ( a q ) produced =
=
Molar mass of AlCl3 ( a q ) =
Mass of AlCl3 ( a q ) Produced =
=
According to the balanced equation, mole ratio between Al2 (SO4 )3 ( a q ) and CaSO4 ( s ) =
So, Amount of CaSO4 ( s ) produced =
=
Molar mass of CaSO4 ( s ) =
Mass of CaSO4 ( s ) produced =
=
(c)
Interpretation:
Grams of the product(s) produced by complete reaction of
Concept Introduction:
For a substance, number of moles is related to mass and molar mass of the substance as follows:
Here, m is mass of substance in g and M is molar mass of substance in g/mol.
Thus, from number of moles, mass can be calculated as follows:
Answer to Problem 13QAP
Mass of CaCl2 ( a q ) Produced =
Mass of CO2 ( g ) produced =
Mass of H2 O( l ) produced =
Explanation of Solution
According to the balanced equation, mole ratio between CaCO3 ( s ) and CaCl2 ( a q ) =
So, Amount of CaCl2 ( a q ) produced =
=
Molar mass of CaCl2 ( a q ) =
Mass of CaCl2 ( a q ) Produced =
=
According to the balanced equation, mole ratio between CaCO3 ( s ) and CO2 ( g ) =
So, Amount of CO2 ( g ) produced =
=
Molar mass of CO2 ( g ) =
Mass of CO2 ( g ) produced =
=
According to the balanced equation, mole ratio between CaCO3 ( s ) and H2 O( l ) =
So, Amount of H2 O( l ) produced =
=
Molar mass of H2 O( l ) =
Mass of H2 O( l ) produced =
=
(d)
Interpretation:
Grams of the product(s) produced by complete reaction of
Concept Introduction:
For a substance, number of moles is related to mass and molar mass of the substance as follows:
Here, m is mass of substance in g and M is molar mass of substance in g/mol.
Thus, from number of moles, mass can be calculated as follows:
Answer to Problem 13QAP
Mass of CO2 ( g ) produced =
Mass of H2 O( g ) produced =
Explanation of Solution
According to the balanced equation, mole ratio between C4 H1 0 ( g ) and CO2 ( g ) =
So, Amount of CO2 ( g ) produced =
=
Molar mass of CO2 ( g ) =
Mass of CO2 ( g ) produced =
=
According to the balanced equation, mole ratio between C4 H1 0 ( g ) and H2 O( g ) =
So, Amount of H2 O( g ) produced =
=
Molar mass of H2 O( g ) =
Mass of H2 O( g ) produced =
=
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Chapter 9 Solutions
Introductory Chemistry: A Foundation
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