Calcium carbide, CaC 2 , can be produced in an electric furnace by strongly heating calcium oxide (lime) with carbon. The unbalanced equation is :math> CaO ( s ) + C ( s ) → CaC 2 ( s ) + CO ( g ) lcium carbide is useful because it reacts readily with water to form the flammable gas acetylene, C 2 H 2 , which is used ex tensively in the welding industry. The unbalanced equation is :math> CaC 2 ( s ) + H 2 O ( l ) → C 2 H 2 ( g ) + Ca ( OH ) 2 ( s ) at mass of acetylene gas, C 2 H 2 , would he produced by complete reaction of 3.75 g of calcium carbide?
Calcium carbide, CaC 2 , can be produced in an electric furnace by strongly heating calcium oxide (lime) with carbon. The unbalanced equation is :math> CaO ( s ) + C ( s ) → CaC 2 ( s ) + CO ( g ) lcium carbide is useful because it reacts readily with water to form the flammable gas acetylene, C 2 H 2 , which is used ex tensively in the welding industry. The unbalanced equation is :math> CaC 2 ( s ) + H 2 O ( l ) → C 2 H 2 ( g ) + Ca ( OH ) 2 ( s ) at mass of acetylene gas, C 2 H 2 , would he produced by complete reaction of 3.75 g of calcium carbide?
Solution Summary: The author explains that the mass of acetylene gas produced by complete reaction of 3.75 g of calcium carbide should be calculated.
Calcium carbide,
CaC
2
, can be produced in an electric furnace by strongly heating calcium oxide (lime) with carbon. The unbalanced equation is
:math>
CaO
(
s
)
+
C
(
s
)
→
CaC
2
(
s
)
+
CO
(
g
)
lcium carbide is useful because it reacts readily with water to form the flammable gas acetylene,
C
2
H
2
, which is used ex tensively in the welding industry. The unbalanced equation is
:math>
CaC
2
(
s
)
+
H
2
O
(
l
)
→
C
2
H
2
(
g
)
+
Ca
(
OH
)
2
(
s
)
at mass of acetylene gas,
C
2
H
2
, would he produced by complete reaction of 3.75 g of calcium carbide?
12. Choose the best diene and dienophile pair that would react the fastest.
CN
CN
CO₂Et
-CO₂Et
.CO₂Et
H3CO
CO₂Et
A
B
C
D
E
F
(6 pts - 2 pts each part) Although we focused our discussion on hydrogen light emission, all
elements have distinctive emission spectra. Sodium (Na) is famous for its spectrum being
dominated by two yellow emission lines at 589.0 and 589.6 nm, respectively. These lines result
from electrons relaxing to the 3s subshell.
a. What is the photon energy (in J) for one of these emission lines? Show your work.
b. To what electronic transition in hydrogen is this photon energy closest to? Justify your
answer-you shouldn't need to do numerical calculations.
c. Consider the 3s subshell energy for Na - use 0 eV as the reference point for n=∞. What
is the energy of the subshell that the electron relaxes from? Choose the same emission
line that you did for part (a) and show your work.
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