Baking powder is a mixture of cream of tartar ( KHC 4 H 4 O 6 ) and baking soda ( NaHCO 3 ) . When it is placed in an oven at typical baking temperatures (as part of a cake, ¡or example), it under goes the following reaction ( CO 2 makes the cake rise): msp; ( KHC 4 H 4 O 6 ) ( s ) + NaHCO 3 ( s ) → KNaC 4 H 4 O 6 ( s ) + H 2 O ( g ) + CO 2 ( g ) u decide to make a cake one clay, and the recipe calls for baking powder. Unfortunately, you have no baking powder. You do have cream of tartar and baking soda, so you use stoichiometry to figure out how much of each to mix. the following choices, which is the best way to make baking powder? The amounts given in the choices are in teaspoons (that is, you will use a teaspoon to measure the baking soda and cream of tartar). Justify your choice. sume a teaspoon of cream of tartar has the same mass as a teaspoon of baking soda. l type='a'> Add equal amounts of baking soda and cream of tartar. i>Add a bit more than twice as much cream of tartar as baking soda. i>Add a hit more than twice as much baking soda as cream of tartar. i>Add more cream of tartar than baking soda, hut not quite twice as much. i>Add more baking soda than cream of tartar, hut not quite twice as much.
Baking powder is a mixture of cream of tartar ( KHC 4 H 4 O 6 ) and baking soda ( NaHCO 3 ) . When it is placed in an oven at typical baking temperatures (as part of a cake, ¡or example), it under goes the following reaction ( CO 2 makes the cake rise): msp; ( KHC 4 H 4 O 6 ) ( s ) + NaHCO 3 ( s ) → KNaC 4 H 4 O 6 ( s ) + H 2 O ( g ) + CO 2 ( g ) u decide to make a cake one clay, and the recipe calls for baking powder. Unfortunately, you have no baking powder. You do have cream of tartar and baking soda, so you use stoichiometry to figure out how much of each to mix. the following choices, which is the best way to make baking powder? The amounts given in the choices are in teaspoons (that is, you will use a teaspoon to measure the baking soda and cream of tartar). Justify your choice. sume a teaspoon of cream of tartar has the same mass as a teaspoon of baking soda. l type='a'> Add equal amounts of baking soda and cream of tartar. i>Add a bit more than twice as much cream of tartar as baking soda. i>Add a hit more than twice as much baking soda as cream of tartar. i>Add more cream of tartar than baking soda, hut not quite twice as much. i>Add more baking soda than cream of tartar, hut not quite twice as much.
Solution Summary: The author explains that stoichiometry helps determine the relationship between the number of moles of the reactants and products that are involved in a reaction.
Baking powder is a mixture of cream of tartar
(
KHC
4
H
4
O
6
)
and baking soda
(
NaHCO
3
)
. When it is placed in an oven at typical baking temperatures (as part of a cake, ¡or example), it under goes the following reaction (
CO
2
makes the cake rise):
msp;
(
KHC
4
H
4
O
6
)
(
s
)
+
NaHCO
3
(
s
)
→
KNaC
4
H
4
O
6
(
s
)
+
H
2
O
(
g
)
+
CO
2
(
g
)
u decide to make a cake one clay, and the recipe calls for baking powder. Unfortunately, you have no baking powder. You do have cream of tartar and baking soda, so you use stoichiometry to figure out how much of each to mix.
the following choices, which is the best way to make baking powder? The amounts given in the choices are in teaspoons (that is, you will use a teaspoon to measure the baking soda and cream of tartar). Justify your choice.
sume a teaspoon of cream of tartar has the same mass as a teaspoon of baking soda.
l type='a'>
Add equal amounts of baking soda and cream of tartar.
i>Add a bit more than twice as much cream of tartar as baking soda.
i>Add a hit more than twice as much baking soda as cream of tartar.
i>Add more cream of tartar than baking soda, hut not quite twice as much.
i>Add more baking soda than cream of tartar, hut not quite twice as much.
It is not unexpected that the methoxyl substituent on a cyclohexane ring
prefers to adopt the equatorial conformation.
OMe
H
A G₂ = +0.6 kcal/mol
OMe
What is unexpected is that the closely related 2-methoxytetrahydropyran
prefers the axial conformation:
H
H
OMe
OMe
A Gp=-0.6 kcal/mol
Methoxy: CH3O group
Please be specific and clearly write the reason why this is observed. This effect that provides
stabilization of the axial OCH 3 group in this molecule is called the anomeric effect. [Recall in the way of
example, the staggered conformer of ethane is more stable than eclipsed owing to bonding MO
interacting with anti-bonding MO...]
206 Pb
82
Express your answers as integers. Enter your answers separated by a comma.
▸ View Available Hint(s)
VAΣ
ΜΕ ΑΣΦ
Np, N₁ = 82,126
Submit
Previous Answers
?
protons, neutrons
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Calorimetry Concept, Examples and Thermochemistry | How to Pass Chemistry; Author: Melissa Maribel;https://www.youtube.com/watch?v=nSh29lUGj00;License: Standard YouTube License, CC-BY