Concept explainers
Interpretation:
Reasonable structures for two isomeric chlorides formed in the addition of hydrogen chloride in approximately equal amounts for
Concept introduction:
When an unsymmetrically substituted alkene is reacted with a hydrogen chloride, a proton is added to the carbon that has the greater number of hydrogen atoms, and chlorine is added to the carbon that hasfewer number of hydrogen atoms. This is Markovnikov's rule of addition.
A less stable carbocation is rearranged to a more stable carbocation through carbocation rearrangements such as hydride or methyl shift.
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ORGANIC CHEMISTRY-PACKAGE >CUSTOM<
- Compound C has the molecular formula C;H12. On catalytic hydrogenation, 1 mol of C absorbs 1 mol of hydrogen and yields a compound with the molecular formula C7H14. On ozonolysis and subsequent treatment with zinc and acetic acid, C yields only: The structure of C is:arrow_forwardOne mole of an unknown hydrocarbon, compoundC,in the presence of a platinum catalyst, adds 98.9L of hydrogen, measured at 744mm Hg and 22°C, to form a saturated alkanewhich containsone ring. Whenone mole of compound Cis reacted with ozone,followed by reduction with (CH3)2S, four moles of only oneproductwasformed, whose condensed molecular formula is CHO-CHO. Give the structure ofcompound C. Explain your reasoning.arrow_forwardTwo isomers, A and B, of molecular formula C5H8 undergo catalytic hydrogenation with hydrogen gas and palladium on carbon to form the same C5H10 product. On ozonolysis followed by treatment with hydrogen peroxide (H₂O2), isomer A gave a product of molecular formula C5H8O4 that has two carboxylic acid groups in it whereas isomer B gave a product of molecular formula C5H8O3 that contains a carboxylic acid group and a ketone group. Which of the following isomeric pairs best match this data? a. Isomer A is cyclopentene and isomer is 1-pentyne O b. Isomer A is cyclopentene and isomer B is 1-methylcyclobutene c. Isomer A is cyclopentene and isomer B is 3-methylcyclobutene d. Isomer A is 1-methylcyclobutene and isomer B is 3-methylcyclobutenearrow_forward
- Two isomers, A and B, of molecular formula C5H8 undergo catalytic hydrogenation with hydrogen gas and palladium on carbon to form the same C5H10 product. On ozonolysis followed by treatment with hydrogen peroxide (H2O2), isomer A gave a product of molecular formula C5H8O4 that has two carboxylic acid groups in it whereas isomer B gave a product of molecular formula C5H8O3 that contains a carboxylic acid group and a ketone group. What is the isometric pair of A and B that corresponds?arrow_forwardTwo isomers, A and B, of molecular formula C5H8 undergo catalytic hydrogenation with hydrogen gas and palladium on carbon to form the same C5H10 product. On ozonolysis followed by treatment with hydrogen peroxide (H2O2), isomer A gave a product of molecular formula C5H8O4 that has two carboxylic acid groups in it whereas isomer B gave a product of molecular formula C5H8O3 that contains a carboxylic acid group and a ketone group. Which of the following isomeric pairs best match this data?arrow_forwardTreatment of cis-4-bromocyclohexanol with HO– affords compound A and cyclohex-3-en-1-ol. Treatment of trans-4- bromocyclohexanol under the same conditions forms compound B and cyclohex-3-en-1-ol. A and B contain different functional groups and are not isomers of each other. Propose structures for A and B and offer an explanation for their formation.arrow_forward
- The reaction of 3,4-dimethyl-3-hexanol (3,4-dimethylhexan-3-ol) with HBr generates compound A as the major product. Treatment of compound A with a strong base gives two isomers of compound B as the major product, along with one isomer of compound C and one isomer of compound D as minor products, all of which have one double-bond equivalent. Identify compounds A, B, C, and D and give their names. By what mechanism does the reaction of 3,4-dimethyl-3-hexanol with HBr occur? By what mechanism does the reaction of A with strong base to form B occur? Propose reaction conditions for an alternative, one-step method for converting 3,4-dimethyl-3-hexanol directly to compound B.arrow_forward(a) The Friedel-Crafts reaction of benzene with 2-chloro-3-methylbutane in the presence of AlCl3 occurs with a carbocation rearrangement. Give mechanistic explanation and the product formed. (b) Predict the product(s) will be formed from the following reactions: (i) Bromination of p-methylbenzoic acid (ii) Sulphonation of m-bromoanisole (iii) Friedel-craft acylation of o-bromonitrobenzenearrow_forwardDeduce the structures of compounds A and B, two of the major components of jasmine oil, from the given data. Compound A: C9H10O2; IR absorptions at 3091–2895 and 1743 cm-1; 1H NMR signals at 2.06 (singlet, 3 H), 5.08 (singlet, 2 H), and 7.33 (broad singlet, 5 H) ppm. Compound B: C14H12O2; IR absorptions at 3091–2953 and 1718 cm-1; 1H NMR signals at 5.35 (singlet, 2 H) and 7.26–8.15 (multiplets, 10 H) ppm.arrow_forward
- Write the structure of the major organic product formed in the reaction of 1-pentene with each of the following: (a) Hydrogen chloride (b) Dilute sulfuric acid (c) Diborane in diglyme, followed by basic hydrogen peroxide (d) Bromine in carbon tetrachloride (e) Bromine in water (f) Peroxyacetic acid (g) Ozone (h) Product of part (g) treated with zinc and water (i) Product of part (g) treated with dimethyl sulfide (CH3)2Sarrow_forwardAddition of HBr to 3,3-dimethyl-1-butene gives a mixture of two isomeric alkyl bromide products. Please daw structures for the two products, and give a mechanistic explanation for their formation.arrow_forward(c) Compound C has a molecular formula of C6H14O. The IR spectrum shows strong absorption bands at 2980, 2850 and 1100 cm-1. The 'H NMR spectrum shows three singlets at &H 1.25 (9H), 3.23 (3H) and 3.79 (2H). Based on the spectral data given, deduce the structure of compound C.arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning