Holt Mcdougal Larson Pre-algebra: Student Edition 2012
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN: 9780547587776
Author: HOLT MCDOUGAL
Publisher: HOLT MCDOUGAL
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Chapter 8.3, Problem 9E
To determine

To write:

An equation describing the possible amounts of ground beef and chicken that you can buy. Use intercepts to graph the equation.

Expert Solution & Answer
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Answer to Problem 9E

Our required equation would be 3x+5y=30 .

x -intercept: (10,0)

y -intercept: (0,6)

Explanation of Solution

Given:

You are in charge of buying food for a barbecue. You have budgeted $30 for ground beef and chicken. Ground beef costs $3 per pound, and chicken costs $5 per pound.

Calculation:

Let x represent the pounds of ground beef and y represent the pounds of chicken.

We have been given that ground beef costs $3 per pound, so cost of x pounds of ground beef would be 3x .

We have been given that chicken costs $5 per pound, so cost of y pounds of chicken would be 5y .

Since the budget for buying food is $30, so cost of x pounds of ground beef and y pounds of chicken would be equal to $30. We can represent this information in an equation as:

  3x+5y=30

Therefore, our required equation would be 3x+5y=30 .

To find x -intercept, we will substitute y=0 in our given equation and solve for xas shown below:

  3x+5y=30 (Given equation)3x+5(0)=30 (Substituting y=0)3x=303x3=303x=10

Therefore, the x -intercept of our given equation is (10,0) .

To find y- intercept, we will substitute x=0 in our given equation and solve for yas shown below:

  3x+5y=30 (Given equation)3(0)+5y=30 (Substituting x=0)5y=305y5=305 (Dividing both sides by 5)y=6

Therefore, the y -intercept of our given equation is (0,6) .

Upon graphing our given equation, we will get our required graph as shown below:

Holt Mcdougal Larson Pre-algebra: Student Edition 2012, Chapter 8.3, Problem 9E

Chapter 8 Solutions

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Ch. 8.1 - Prob. 7ECh. 8.1 - Prob. 8ECh. 8.1 - Prob. 9ECh. 8.1 - Prob. 10ECh. 8.1 - Prob. 11ECh. 8.1 - Prob. 12ECh. 8.1 - Prob. 13ECh. 8.1 - Prob. 14ECh. 8.1 - Prob. 15ECh. 8.1 - Prob. 16ECh. 8.1 - Prob. 17ECh. 8.1 - Prob. 18ECh. 8.1 - Prob. 19ECh. 8.1 - Prob. 20ECh. 8.1 - Prob. 21ECh. 8.1 - Prob. 22ECh. 8.1 - Prob. 23ECh. 8.1 - Prob. 24ECh. 8.1 - Prob. 25ECh. 8.1 - Prob. 26ECh. 8.1 - Prob. 27ECh. 8.1 - Prob. 28ECh. 8.1 - Prob. 29ECh. 8.1 - Prob. 30ECh. 8.1 - Prob. 31ECh. 8.1 - Prob. 32ECh. 8.1 - Prob. 33ECh. 8.1 - Prob. 34ECh. 8.1 - Prob. 35ECh. 8.1 - Prob. 36ECh. 8.1 - Prob. 37ECh. 8.2 - Prob. 1CCh. 8.2 - Prob. 2CCh. 8.2 - Prob. 3CCh. 8.2 - Prob. 4CCh. 8.2 - Prob. 5CCh. 8.2 - Prob. 6CCh. 8.2 - Prob. 7CCh. 8.2 - Prob. 8CCh. 8.2 - Prob. 9CCh. 8.2 - Prob. 10CCh. 8.2 - Prob. 1ECh. 8.2 - Prob. 2ECh. 8.2 - Prob. 3ECh. 8.2 - Prob. 4ECh. 8.2 - Prob. 5ECh. 8.2 - Prob. 6ECh. 8.2 - Prob. 7ECh. 8.2 - Prob. 8ECh. 8.2 - Prob. 9ECh. 8.2 - Prob. 10ECh. 8.2 - Prob. 11ECh. 8.2 - Prob. 12ECh. 8.2 - Prob. 13ECh. 8.2 - Prob. 14ECh. 8.2 - Prob. 15ECh. 8.2 - Prob. 16ECh. 8.2 - Prob. 17ECh. 8.2 - Prob. 18ECh. 8.2 - Prob. 19ECh. 8.2 - Prob. 20ECh. 8.2 - Prob. 21ECh. 8.2 - Prob. 22ECh. 8.2 - Prob. 23ECh. 8.2 - Prob. 24ECh. 8.2 - Prob. 25ECh. 8.2 - Prob. 26ECh. 8.2 - Prob. 27ECh. 8.2 - Prob. 28ECh. 8.2 - Prob. 29ECh. 8.2 - Prob. 30ECh. 8.2 - Prob. 31ECh. 8.2 - Prob. 32ECh. 8.2 - Prob. 33ECh. 8.2 - Prob. 34ECh. 8.2 - Prob. 35ECh. 8.2 - Prob. 36ECh. 8.2 - Prob. 37ECh. 8.2 - Prob. 38ECh. 8.2 - Prob. 39ECh. 8.2 - Prob. 40ECh. 8.2 - Prob. 41ECh. 8.2 - Prob. 42ECh. 8.2 - Prob. 43ECh. 8.2 - Prob. 44ECh. 8.2 - Prob. 45ECh. 8.2 - Prob. 46ECh. 8.2 - Prob. 47ECh. 8.2 - Prob. 48ECh. 8.2 - Prob. 49ECh. 8.2 - Prob. 50ECh. 8.2 - Prob. 51ECh. 8.2 - Prob. 52ECh. 8.2 - Prob. 53ECh. 8.2 - Prob. 54ECh. 8.2 - Prob. 55ECh. 8.2 - Prob. 56ECh. 8.3 - Prob. 1CCh. 8.3 - Prob. 2CCh. 8.3 - Prob. 3CCh. 8.3 - Prob. 1ECh. 8.3 - Prob. 2ECh. 8.3 - Prob. 3ECh. 8.3 - Prob. 4ECh. 8.3 - Prob. 5ECh. 8.3 - Prob. 6ECh. 8.3 - Prob. 7ECh. 8.3 - Prob. 8ECh. 8.3 - 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