To construct: The 95% confidence interval for the population mean percent body fat of the female graduate physical therapy students.

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Answer 1

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Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 8.2, Problem 84E

a.

To determine

To construct: The 95% confidence interval for the population mean percent body fat of the female graduate physical therapy students.

b.

To determine

To find: The margin of error for the 95% confidence interval obtained in part (a).

c.

To determine

To interpret: The margin of error of the 95% confidence interval of the population mean.

d.

To determine

To find: The number of female graduates required to be sampled for the margin of error to be within 1.55 percent body fat for each of the 99% confidence interval.

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Body Fat. J. McWhorter et al. of the College of Health Sciences at the University of Nevada, Las Vegas, studied physical therapy students during their graduate-school years. The researchers were interested in the fact that, although graduate physical-therapy students are taught the principles of fitness, some have difficulty finding the time to implement those principles. In the study, published as “An Evaluation of Physical Fitness Parameters for Graduate Students” (Journal of American College Health, Vol. 51, No. 1, pp. 32–37), a sample of 27 female graduate physical-therapy students had a mean of 22.46 percent body fat. a. Assuming that percent body fat of female graduate physicaltherapy students is normally distributed with standard deviation 4.10 percent body fat, determine a 95% confidence interval for the mean percent body fat of all female graduate physical-therapy students. b. Obtain the margin of error, E, for the confidence interval you found in part (a). c. Explain the…

5) Alcohol consumption is influenced by price and packaging, but what about glassware? Atwood et al. (2012) measured whether the time taken to drink a beer was influenced by the shape of the glass in which it was served. Participants were given a 12 oz. of chilled lager and were told that they should drink it at their own pace while watching a nature documentary. The participants were randomly assigned to receive their beer in either a straight-sided glass or a curved, fluted glass. The data below are the total time in minutes to drink the glass of beer by the 19 women participants in the study. Straight glass: 11.63 10.37 17.89 6.96 20.40 20.64 9.26 18.11 10.33 23.54 Curved glass: 7.46 9.28 8.90 6.73 8.25 6.16 13.09 2.10 6.37 a. Show the data in a graph. What trend is suggested? Comment on other differences between the frequency distributions of the two samples. b. Test whether the mean total time to drink the beer differs depending on beer glass shape.

In a study of palatability of antibiotics for children, Doreen Matsui and her colleagues used a voluntary sample of healthy children to assess their reactions to the taste of four antibiotics. The children’s responses were measured on a 10-centimeter visual analog scale that incorporated the use of faces, from sad (low score) to happy (high score). The minimum and maximum scores were, respectively, 0 and 10. The data in the following table (simulated from the results given in Matsui’s report) were obtained when each of five children were asked to rate the taste of all four antibiotics. AntibioticChild I II III IV 1 4.8 2.2 6.8 6.22 8.1 9.2 6.6 9.63 5.0 2.6 3.6 6.54 7.9 9.4 5.3 8.55 3.9 7.4 2.1…

Answer 2

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Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 8.2, Problem 84E

a.

To determine

To construct: The 95% confidence interval for the population mean percent body fat of the female graduate physical therapy students.

b.

To determine

To find: The margin of error for the 95% confidence interval obtained in part (a).

c.

To determine

To interpret: The margin of error of the 95% confidence interval of the population mean.

d.

To determine

To find: The number of female graduates required to be sampled for the margin of error to be within 1.55 percent body fat for each of the 99% confidence interval.

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Answer 3

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Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 8.2, Problem 84E

a.

To determine

To construct: The 95% confidence interval for the population mean percent body fat of the female graduate physical therapy students.

b.

To determine

To find: The margin of error for the 95% confidence interval obtained in part (a).

c.

To determine

To interpret: The margin of error of the 95% confidence interval of the population mean.

d.

To determine

To find: The number of female graduates required to be sampled for the margin of error to be within 1.55 percent body fat for each of the 99% confidence interval.

Expert Solution & Answer

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Answer 4

Question

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 8.2, Problem 84E

a.

To determine

To construct: The 95% confidence interval for the population mean percent body fat of the female graduate physical therapy students.

b.

To determine

To find: The margin of error for the 95% confidence interval obtained in part (a).

c.

To determine

To interpret: The margin of error of the 95% confidence interval of the population mean.

d.

To determine

To find: The number of female graduates required to be sampled for the margin of error to be within 1.55 percent body fat for each of the 99% confidence interval.

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Answer 5

Chapter 8.2, Problem 84E

a.

To determine

To construct: The 95% confidence interval for the population mean percent body fat of the female graduate physical therapy students.

b.

To determine

To find: The margin of error for the 95% confidence interval obtained in part (a).

c.

To determine

To interpret: The margin of error of the 95% confidence interval of the population mean.

d.

To determine

To find: The number of female graduates required to be sampled for the margin of error to be within 1.55 percent body fat for each of the 99% confidence interval.

Answer 6

Chapter 8.2, Problem 84E

a.

To determine

To construct: The 95% confidence interval for the population mean percent body fat of the female graduate physical therapy students.

Answer 7

Chapter 8.2, Problem 84E

a.

To determine

To construct: The 95% confidence interval for the population mean percent body fat of the female graduate physical therapy students.

Answer 8

b.

To determine

To find: The margin of error for the 95% confidence interval obtained in part (a).

Answer 9

b.

To determine

To find: The margin of error for the 95% confidence interval obtained in part (a).

Answer 10

c.

To determine

To interpret: The margin of error of the 95% confidence interval of the population mean.

Answer 11

c.

To determine

To interpret: The margin of error of the 95% confidence interval of the population mean.

Answer 12

d.

To determine

To find: The number of female graduates required to be sampled for the margin of error to be within 1.55 percent body fat for each of the 99% confidence interval.

Answer 13

d.

To determine

To find: The number of female graduates required to be sampled for the margin of error to be within 1.55 percent body fat for each of the 99% confidence interval.

Answer 14

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Answer 15

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Answer 16

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Answer 17

Ch. 8.1 - The value of a statistic used to estimate a...Ch. 8.1 - What is a confidence-interval estimate of a...Ch. 8.1 - Prob. 3E Ch. 8.1 - Prob. 4E Ch. 8.1 - Prob. 5E Ch. 8.1 - Suppose that you lake 500 simple random samples...Ch. 8.1 - Prob. 7E Ch. 8.1 - A simple random sample is taken from a population...Ch. 8.1 - Refer to Exercise 8.7 and find a point estimate...Ch. 8.1 - Prob. 10E

To construct: The 95% confidence interval for the population mean percent body fat of the female graduate physical therapy students.

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To construct: The 95% confidence interval for the population mean percent body fat of the female graduate physical therapy students.

To find: The margin of error for the 95% confidence interval obtained in part (a).

To interpret: The margin of error of the 95% confidence interval of the population mean.

To find: The number of female graduates required to be sampled for the margin of error to be within 1.55 percent body fat for each of the 99% confidence interval.

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