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In Problems 21–30 find the general solution of the given system.
29.
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Chapter 8 Solutions
A First Course in Differential Equations with Modeling Applications (MindTap Course List)
- Problem 2. What solution of the linear system of differential equations x = x1 – 3.x2 x2 = 3x1 + x2 satisfies the initial conditions X1(0) = 4, X2(0) = 7?arrow_forwardProblem 2. Consider the equation: x?y"(x) – xy' +y = 0. Given that yı(x) = x is a solution of this equation. Use the method of reduction of order, find the second solution y2(x) of the equation so that y1 and y2 are linearly independent. (Hint: y2(x) should be given in the form y2(x) = u(x)y1(x). Substitute it into the equation to find u(x).) %3Darrow_forward9arrow_forward
- 1. Find the solution to the initial value problem 4x3 + 1 2у — 6 y(1) = 2. A. y = 3 – Vxª + x – 1 B. y = 2+ Vx³ + x – 2 C. y = 1+ Vx4 + x – 1 D. y = 4 – V4x³ + x – 1 E. y = V4³ + x – 1arrow_forward9. P = 15 -4 -7 2e31 – 8e- -4e31 + 2e- ž(1) = | 3e3t – 20e- -6e31 + 5et Show that x1 (t) is a solution to the system x = Px by evaluating derivatives and the matrix product -4 ž(1) = | 15 -7 Enter your answers in terms of the variable t. Show that x2(t) is a solution to the system x' = Px by evaluating derivatives and the matrix product 9. 3(1) = | 15 -4 X2(t) -7 Enter your answers in terms of the variable t.arrow_forwardFind the particular solution of z²y - y ; y (3) = –1 y+1 - a - y + In | y |= 7 - - a - y + In | y | = – 7 3 + a - y1- In | y |= 7 x - y – In | y |=- 7arrow_forward
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