Chapter 8.10, Problem 20PPS

To determine

The solution of the $x+y=2$ and $x=-3$ by using the substitution method

Answer to Problem 20PPS

The solution of $x+y=2$ and $x=-3$ is $x=-3$ and $y=5$ .

Explanation of Solution

Given:

The two eqn are as:

  $\begin{array}{l}x+y=2\\ x=-3\end{array}$

Calculation:

The two eqns. are described as:

  $x+y=2$....... (1)

  $x=-3$....... (2)

Put the value of the $x=-3$ in eq. (1):

  $\begin{array}{l}x+y=2\\ -3+y=2\\ y=5\end{array}$

So, the value of $x=-3$ and $y=5$ .

Conclusion:

Hence, the solution of the eqns. is $x=-3$ and $y=5$ .