Chapter 8.3, Problem 1CYU

To determine

To calculate:To complete the below table and find four solutions for the below equation and to write the solutions as ordered pair −

  $y=x+7$

$x$	$y=x+7$	$y$
$-1$
$0$
$1$
$2$

Answer to Problem 1CYU

The completed table is :

$x$	$y=x+7$	$y$
$-1$	$y=-1+7$	$6$
$0$	$y=0+7$	$7$
$1$	$y=1+7$	$8$
$2$	$y=2+7$	$9$

The four solutions as ordered pairs are $\left(-1,6\right)$ , $\left(0,7\right)$ , $\left(1,8\right)$ and $\left(2,9\right)$ .

Explanation of Solution

Given information:

Equation is $y=x+7$

Formula Used:

To solve an equation with multiple variables, we need to consider some random values for one of the variables and solve for the other one to find the ordered pair.

Calculation:

Given equation is $y=x+7$

Using the above explanation, we have -

Let the value of $x$ be $-1$ , substituting the value of $x$ in the above equation, we have:

  $y=-1+7$

Solving the above equation, we have :

  $y=6$

Thus, the first ordered pair is $\left(-1,6\right)$ .

Using the same approach to find the other ordered pairs −

Let the value of $x$ be $0$ , substituting the value of $x$ in the above equation, we have:

  $y=0+7$

Solving the above equation, we have :

  $y=7$

Thus, the second ordered pair is $\left(0,7\right)$ .

Let the value of $x$ be $1$ , substituting the value of $x$ in the above equation, we have:

  $y=1+7$

Solving the above equation, we have :

  $y=8$

Thus, the third ordered pair is $\left(1,8\right)$ .

Let the value of $x$ be $2$ , substituting the value of $x$ in the above equation, we have:

  $y=2+7$

Solving the above equation, we have :

  $y=9$

Thus, the fourth ordered pair is $\left(2,9\right)$ .

The completed table is :

$x$	$y=x+7$	$y$
$-1$	$y=-1+7$	$6$
$0$	$y=0+7$	$7$
$1$	$y=1+7$	$8$
$2$	$y=2+7$	$9$

Thus, the four ordered pairs are $\left(-1,6\right)$ , $\left(0,7\right)$ , $\left(1,8\right)$ and $\left(2,9\right)$ .