Concept explainers
(a)
To explain: an equation relating the weight and the cost of the cheese.
(a)
Answer to Problem 8PPS
The equation is:
Explanation of Solution
Given:
Cost of 2 pounds is $8.40
Calculation:
Step 1: The number of pounds is denoted as x and cost of cheese is y
Now, if there is direct variation then there is some constant variable k such that it satisfies the equation:
So, put the value of
Divide the equation by 8.
Step 2: use k to write an equation.
Conclusion:
Therefore, the equation is:
(b)
To find:the cost of 3.5 pounds of cheese.
(b)
Answer to Problem 8PPS
The cost of 3.5 pounds of cheeseis
Explanation of Solution
Calculation:
Now, in order to calculate the cost of cheese
Conclusion:
Therefore, the cost of 3.5 pounds of cheeseis
Chapter 8 Solutions
Pre-Algebra Student Edition
Additional Math Textbook Solutions
College Algebra (5th Edition)
Graphical Approach To College Algebra
College Algebra with Modeling & Visualization (6th Edition)
A Graphical Approach to College Algebra (6th Edition)
- Algebra and Trigonometry (6th Edition)AlgebraISBN:9780134463216Author:Robert F. BlitzerPublisher:PEARSONContemporary Abstract AlgebraAlgebraISBN:9781305657960Author:Joseph GallianPublisher:Cengage LearningLinear Algebra: A Modern IntroductionAlgebraISBN:9781285463247Author:David PoolePublisher:Cengage Learning
- Algebra And Trigonometry (11th Edition)AlgebraISBN:9780135163078Author:Michael SullivanPublisher:PEARSONIntroduction to Linear Algebra, Fifth EditionAlgebraISBN:9780980232776Author:Gilbert StrangPublisher:Wellesley-Cambridge PressCollege Algebra (Collegiate Math)AlgebraISBN:9780077836344Author:Julie Miller, Donna GerkenPublisher:McGraw-Hill Education