
Concept explainers
To find: the constant rate of change and determine whether a proportional linear relationship exists between the two quantities.

Answer to Problem 2CYU
Hence, rate of change is 1$/pounds.
The linear relationship is proportional.
Explanation of Solution
Given:
Consider three points from the graph that shows relationship between number of pounds and total sales in dollars: (1,2) and (2,4)
Calculation:
In order to find constant rate of change, take any two points and use the formula for rate of change.
It means rate of change is change in height of plants with respect to change in number of weeks.
So, consider two points as: (1,2),(2,4)
Thus, constant rate of change is:
Hence, rate of change is 1$/pounds. . It means coffee is selling at the rate of $1 per pound.
Linear relationships are called proportional if the ration of each non zero y -value compared to corresponding x -value is the same.
Now, it means that calculate ratio
For the point (1,2) the ratio is:
And, for the point (2,4) the ratio is:
Hence, ratio
Thus, the linear relationship is proportional
Conclusion:
Therefore, rate of change is 1$/pounds. It means coffee is selling at the rate of $1 per pound.The linear relationship is proportional.
Chapter 8 Solutions
Pre-Algebra Student Edition
Additional Math Textbook Solutions
Algebra and Trigonometry (6th Edition)
Elementary Statistics
Thinking Mathematically (6th Edition)
A First Course in Probability (10th Edition)
Basic Business Statistics, Student Value Edition
University Calculus: Early Transcendentals (4th Edition)
- Solve the following equation forx. leave answer in Simplified radical form. 5x²-4x-3=6arrow_forwardMATCHING LIST Question 6 Listen Use the given equations and their discriminants to match them to the type and number of solutions. 00 ed two irrational solutions a. x²+10x-2=-24 two rational solutions b. 8x²+11x-3=7 one rational solution c. 3x²+2x+7=2 two non-real solutions d. x²+12x+45 = 9 DELL FLOWER CHILD 10/20 All Changes S $681 22991arrow_forward88 MULTIPLE CHOICE Question 7 Listen The following irrational expression is given in unsimplified form with four op- tions in simplified form. Select the correct simplified form. Select only one option. A 2±3√√2 B 4±√3 2±√ √3 D 1±√√3 DELL FLOWER CHILD 11/200 4 ± √48 4 ✓ All Changes Saved 165arrow_forward
- Use the graph of y = f(x) to answer the following. 3- 2 -4 -2 -1 1 2 3 4 -1 2 m -3- + (d) Find all x for which f(x) = -2. If there is more than one value, separate them with commas or write your answer in interval notation, if necessary. Select "None", if applicable. Value(s) of x for which f(x)=-2: | (0,0) (0,0) (0,0) (0,0) 0,0... -00 None (h) Determine the range of f. The range is (0,0) Garrow_forwardWhat is g(f(4))arrow_forward10) Multiply (8m + 3)² A) 8m²+11m+6 B) m² + 48m+9 C) 64m²+48m+9 D) 16m²+11m+6arrow_forward
- Let R be field and X= R³/s Vector space over R M=(a,b,c)labic, e Rra+b= 3- <3 Show that Ms and why with proof. 1) is convexset and affine set of botost ii) is blanced set and symmetirs set of x iii) is hy per space and hyper plane ofx or hot iii) find f:MR st kerf = M 18/103 and finnd fiM→R/{0} st M= {xEX, f(t) = x, texiαER? jiii) show that Mis Maxsubspace or not and Mis a max. affine set or not.arrow_forwardFind The partial fraction decomposition for each The following 2× B) (x+3) a 3 6 X-3x+2x-6arrow_forward1) Find the partial feraction decomposition for each of 5- X 2 2x+x-1 The following: 3 B) 3 X + 3xarrow_forward
- Algebra and Trigonometry (6th Edition)AlgebraISBN:9780134463216Author:Robert F. BlitzerPublisher:PEARSONContemporary Abstract AlgebraAlgebraISBN:9781305657960Author:Joseph GallianPublisher:Cengage LearningLinear Algebra: A Modern IntroductionAlgebraISBN:9781285463247Author:David PoolePublisher:Cengage Learning
- Algebra And Trigonometry (11th Edition)AlgebraISBN:9780135163078Author:Michael SullivanPublisher:PEARSONIntroduction to Linear Algebra, Fifth EditionAlgebraISBN:9780980232776Author:Gilbert StrangPublisher:Wellesley-Cambridge PressCollege Algebra (Collegiate Math)AlgebraISBN:9780077836344Author:Julie Miller, Donna GerkenPublisher:McGraw-Hill Education





