Concept explainers
To write: the first five terms of the sequence defined recursively and write the pattern for nth term.

Answer to Problem 59E
The first five terms are
6,8,10,12,14 .
The pattern for nth term is an=2n+4 .
Explanation of Solution
Given information:
Given sequence
a1=6,ak+1=ak+2
Calculation:
Since the first term of the sequence is a1=6 therefore, the subsequent terms can be computed from the recursive formula, ak+1=ak+2 as follows,
a2=a1+2=6+2=8a3=a2+2=8+2=10a4=a3+3=10+2=12a5=a4+2=12+2=14
Hence the first five terms are
6,8,10,12,14 .
Now, the pattern for nth term can be obtained as
Consider the sequence 6,8,10,12,14...
For n=1,2,3,4,5,...n
The terms are 6,8,10,12,14...an
Rewrite the terms as shown below,
6,8,10,12,14...an=2+4,4+4,6+4,8+4,10+4...an=(2×1)+4,(2×2)+4,(2×3)+4,(2×4)+2,(2×5)+4...an
Thus pattern followed is such that each term is 4 more than 2 times n . Therefore , the general term is an=2n+4 .
Chapter 8 Solutions
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