The transition state of the reaction between tert-butyl chloride and sodium hydroxide is needed be drawn. Concept introduction: Tertiary substrates and strong bases favor bimolecular reaction. Sodium ethoxide can act as a bulky strong nucleophile as well as a strong base. S N 2 and E2 are two bimolecular reactions. They are concerted (one step) reactions. In S N 2 reaction, nucleophile cannot approach a tertiary alkyl halide because of the high steric hindrance. In E2 reaction, strong base can abstract the β-proton of a tertiary alkyl halide. Transition state is a state in between the reactant and product. In the transition state of E2 reaction: the abstraction of β-proton by the base , removal of leaving group (halo-group) and formation of double bond are taking place. To draw: the transition state of the reaction between tert-butyl chloride and sodium hydroxide.

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Answer 1

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Chapter 8, Problem 70PP

Interpretation Introduction

Interpretation:

The transition state of the reaction between tert-butyl chloride and sodium hydroxide is needed be drawn.

Concept introduction:

Tertiary substrates and strong bases favor bimolecular reaction. Sodium ethoxide can act as a bulky strong nucleophile as well as a strong base. S_N² and E2 are two bimolecular reactions. They are concerted (one step) reactions.

In S_N²reaction, nucleophile cannot approach a tertiary alkyl halide because of the high steric hindrance.

In E2 reaction, strong base can abstract the β-proton of a tertiary alkyl halide.

Transition state is a state in between the reactant and product.

In the transition state of E2 reaction: the abstraction of β-proton by the base, removal of leaving group (halo-group) and formation of double bond are taking place.

To draw: the transition state of the reaction between tert-butyl chloride and sodium hydroxide.

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Answer 2

Question

Chapter 8, Problem 70PP

Interpretation Introduction

Interpretation:

The transition state of the reaction between tert-butyl chloride and sodium hydroxide is needed be drawn.

Concept introduction:

Tertiary substrates and strong bases favor bimolecular reaction. Sodium ethoxide can act as a bulky strong nucleophile as well as a strong base. S_N² and E2 are two bimolecular reactions. They are concerted (one step) reactions.

In S_N²reaction, nucleophile cannot approach a tertiary alkyl halide because of the high steric hindrance.

In E2 reaction, strong base can abstract the β-proton of a tertiary alkyl halide.

Transition state is a state in between the reactant and product.

In the transition state of E2 reaction: the abstraction of β-proton by the base, removal of leaving group (halo-group) and formation of double bond are taking place.

To draw: the transition state of the reaction between tert-butyl chloride and sodium hydroxide.

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Answer 3

Question

Chapter 8, Problem 70PP

Interpretation Introduction

Interpretation:

The transition state of the reaction between tert-butyl chloride and sodium hydroxide is needed be drawn.

Concept introduction:

Tertiary substrates and strong bases favor bimolecular reaction. Sodium ethoxide can act as a bulky strong nucleophile as well as a strong base. S_N² and E2 are two bimolecular reactions. They are concerted (one step) reactions.

In S_N²reaction, nucleophile cannot approach a tertiary alkyl halide because of the high steric hindrance.

In E2 reaction, strong base can abstract the β-proton of a tertiary alkyl halide.

Transition state is a state in between the reactant and product.

In the transition state of E2 reaction: the abstraction of β-proton by the base, removal of leaving group (halo-group) and formation of double bond are taking place.

To draw: the transition state of the reaction between tert-butyl chloride and sodium hydroxide.

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Answer 4

Question

Chapter 8, Problem 70PP

Interpretation Introduction

Interpretation:

The transition state of the reaction between tert-butyl chloride and sodium hydroxide is needed be drawn.

Concept introduction:

Tertiary substrates and strong bases favor bimolecular reaction. Sodium ethoxide can act as a bulky strong nucleophile as well as a strong base. S_N² and E2 are two bimolecular reactions. They are concerted (one step) reactions.

In S_N²reaction, nucleophile cannot approach a tertiary alkyl halide because of the high steric hindrance.

In E2 reaction, strong base can abstract the β-proton of a tertiary alkyl halide.

Transition state is a state in between the reactant and product.

In the transition state of E2 reaction: the abstraction of β-proton by the base, removal of leaving group (halo-group) and formation of double bond are taking place.

To draw: the transition state of the reaction between tert-butyl chloride and sodium hydroxide.

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Answer 5

Chapter 8, Problem 70PP

Interpretation Introduction

Interpretation:

The transition state of the reaction between tert-butyl chloride and sodium hydroxide is needed be drawn.

Concept introduction:

Tertiary substrates and strong bases favor bimolecular reaction. Sodium ethoxide can act as a bulky strong nucleophile as well as a strong base. S_N² and E2 are two bimolecular reactions. They are concerted (one step) reactions.

In S_N²reaction, nucleophile cannot approach a tertiary alkyl halide because of the high steric hindrance.

In E2 reaction, strong base can abstract the β-proton of a tertiary alkyl halide.

Transition state is a state in between the reactant and product.

In the transition state of E2 reaction: the abstraction of β-proton by the base, removal of leaving group (halo-group) and formation of double bond are taking place.

To draw: the transition state of the reaction between tert-butyl chloride and sodium hydroxide.

Answer 6

Chapter 8, Problem 70PP

Interpretation Introduction

Interpretation:

The transition state of the reaction between tert-butyl chloride and sodium hydroxide is needed be drawn.

Concept introduction:

Tertiary substrates and strong bases favor bimolecular reaction. Sodium ethoxide can act as a bulky strong nucleophile as well as a strong base. S_N² and E2 are two bimolecular reactions. They are concerted (one step) reactions.

In S_N²reaction, nucleophile cannot approach a tertiary alkyl halide because of the high steric hindrance.

In E2 reaction, strong base can abstract the β-proton of a tertiary alkyl halide.

Transition state is a state in between the reactant and product.

In the transition state of E2 reaction: the abstraction of β-proton by the base, removal of leaving group (halo-group) and formation of double bond are taking place.

To draw: the transition state of the reaction between tert-butyl chloride and sodium hydroxide.

Answer 7

Chapter 8, Problem 70PP

Interpretation Introduction

Interpretation:

The transition state of the reaction between tert-butyl chloride and sodium hydroxide is needed be drawn.

Concept introduction:

Tertiary substrates and strong bases favor bimolecular reaction. Sodium ethoxide can act as a bulky strong nucleophile as well as a strong base. S_N² and E2 are two bimolecular reactions. They are concerted (one step) reactions.

In S_N²reaction, nucleophile cannot approach a tertiary alkyl halide because of the high steric hindrance.

In E2 reaction, strong base can abstract the β-proton of a tertiary alkyl halide.

Transition state is a state in between the reactant and product.

In the transition state of E2 reaction: the abstraction of β-proton by the base, removal of leaving group (halo-group) and formation of double bond are taking place.

To draw: the transition state of the reaction between tert-butyl chloride and sodium hydroxide.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 8.3 - Prob. 1LTS Ch. 8.3 - Prob. 1PTS Ch. 8.3 - Prob. 2ATS Ch. 8.3 - Prob. 3ATS Ch. 8.3 - Prob. 4CC Ch. 8.4 - Prob. 2LTS Ch. 8.4 - Prob. 5PTS Ch. 8.4 - Prob. 6ATS Ch. 8.5 - Prob. 3LTS Ch. 8.5 - Prob. 7PTS

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