
Concept explainers
Interpretation:
The wrong point in the given Lewis structures is to be stated, and the correct Lewis structure of the molecule is to be drawn.
Concept Introduction:
Lewis structure is a representation of the bonding and non-bonding electron pairs present in the outermost shell of all atoms present in the molecule.
The number of bonds formed by an atom in the molecule is determined by the valence electrons pairs.

Answer to Problem 50QP
Solution:
a)
The double bond is present between the carbon and nitrogen atoms.
The correct Lewis structure is as follows:
b)
The double bond is present between the carbon and hydrogen atoms.
The correct Lewis structure is as follows:
c)
A single bond is present between the
The correct Lewis structure is as follows:
d)
The lone pair of electrons on boron.
The correct Lewis structure is as follows:
e)
The double bond between the oxygen and fluorine atoms.
The correct Lewis structure is as follows:
f)
The single bond between the carbon and oxygen atoms.
The correct Lewis structure is as follows:
g)
The lone pair of electrons of the nitrogen atom is missing.
The correct Lewis structure is as follows:
Explanation of Solution
a)
The given Lewis structure is as follows:
The electronic configurations of hydrogen, carbon, and nitrogen in
Carbon has four electrons in its outermost shell and requires four electrons to complete its outermost shell of electrons, while nitrogen requires three electrons to complete its octet and hydrogen requires one electron to obtain its fully-filled electronic configuration. Therefore, the Lewis structure of
The correct Lewis structure of
Hence, the given Lewis structure of
b)
The given Lewis structure is as follows:
The electronic configurations of carbon and hydrogen in
The carbon atom contains four electrons in its outermost shell and the hydrogen atom contains one valence electron in its
The correct Lewis structure of
Hence, the given Lewis structure of
c)
The given Lewis structure is as follows:
The electronic configurations of tin and oxygen in
A carbon atom has a tendency to form four bonds because of the presence of four valence electrons in its outermost shell, while oxygen has a tendency to form two bonds due to the presence of two electrons in its outermost shell. The Lewis structure of
The correct Lewis structure of
Hence, the given Lewis structure of
d)
The given Lewis structure is as follows:
The electronic configurations of boron and fluorine in
The boron atom contains three electrons in its outermost shell and the fluorine atom contains five electrons in its
The Lewis structure of
Hence, the given Lewis structure of
e)
The given Lewis structure is as follows:
The electronic configurations of hydrogen, oxygen, and fluorine in
Hydrogen has a tendency to form one bond because of the presence of one electron in its outermost shell, fluorine has a tendency to form one bond because of the presence of five electrons in its
The correct Lewis structure of
Hence, the given Lewis structure of
f)
The given Lewis structure is as follows:
The electronic configurations of fluorine, carbon, oxygen, and hydrogen in
The fluorine atom has a tendency to form one bond because of the presence of five valence electrons in its
Hence, the given Lewis structure of
g)
The given Lewis structure is,
The electronic configurations of nitrogen and chlorine in
The nitrogen atom contains three valence electrons in its
The correct Lewis structure of
Hence, the given Lewis structure of
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Chapter 8 Solutions
Chemistry
- Determine whether each of the following molecules is a hemiacetal, acetal, or neither and select the appropriate box in the table. CH3O OH OH OH hemiacetal acetal neither hemiacetal acetal neither Xarrow_forwardWhat is the missing reactant R in this organic reaction? N N དལ་ད་་ + R • Draw the structure of R in the drawing area below. • Be sure to use wedge and dash bonds if it's necessary to draw one particular enantiomer. Click and drag to start drawing a structure. ㄖˋarrow_forwardDraw the condensed structure of 4-hydroxy-3-methylbutanal. Click anywhere to draw the first atom of your structure.arrow_forward
- Using the bond energy values, calculate the energy that must be supplied or is released upon the polymerization of 755 monomers. If energy must be supplied, provide a positive number; if energy is released, provide a negative number. Hint: Avogadro’s number is 6.02 × 1023.arrow_forward-AG|F=2E|V 3. Before proceeding with this problem you may want to glance at p. 466 of your textbook where various oxo-phosphorus derivatives and their oxidation states are summarized. Shown below are Latimer diagrams for phosphorus at pH values at 0 and 14: Acidic solution -0.93 +0.38 -0.51 -0.06 H3PO4 →H4P206 H3PO3 H3PO2 → P→ PH3 -0.28 -0.50 → -0.50 Basic solution 3-1.12 -1.57 -2.05 -0.89 PO HPO →→H2PO2 P PH3 -1.73 a) Under acidic conditions, H3PO4 can be reduced into H3PO3 directly (-0.28V), or via the formation and reduction of H4P2O6 (-0.93/+0.38V). Calculate the values of AG's for both processes; comment. (3 points) 0.5 PH, 0.0 -0.5- 2 3 9 3 -1.5 -2.0 Pa H,PO H,PO H,PO -3 -1 0 2 4 Oxidation state, N 2 b) Frost diagram for phosphorus under acidic conditions is shown. Identify possible disproportionation and comproportionation processes; write out chemical equations describing them. (2 points) c) Elemental phosphorus tends to disproportionate under basic conditions. Use data in…arrow_forwardThese two reactions appear to start with the same starting materials but result in different products. How do the chemicals know which product to form? Are both products formed, or is there some information missing that will direct them a particular way?arrow_forward
- What would be the best choices for the missing reagents 1 and 3 in this synthesis? 1. PPh3 3 1 2 2. n-BuLi • Draw the missing reagents in the drawing area below. You can draw them in any arrangement you like. • Do not draw the missing reagent 2. If you draw 1 correctly, we'll know what it is. • Note: if one of your reagents needs to contain a halogen, use bromine. Explanation Check Click and drag to start drawing a structure. 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Priva ×arrow_forwardPredict the products of this organic reaction: Explanation Check IN NaBH3CN H+ ? Click and drag to start drawing a structure. D 5 C +arrow_forwardPredict the products of this organic reaction: H3O+ + ? • Draw all the reasonable products in the drawing area below. If there are no products, because no reaction will occur, check the box under the drawing area. • Include both major and minor products, if some of the products will be more common than others. • Be sure to use wedge and dash bonds if you need to distinguish between enantiomers. No reaction. Click and drag to start drawing a structure. dmarrow_forward
- Iarrow_forwardDraw the anti-Markovnikov product of the hydration of this alkene. this problem. Note for advanced students: draw only one product, and don't worry about showing any stereochemistry. Drawing dash and wedge bonds has been disabled for esc esc ☐ Explanation Check F1 1 2 F2 # 3 F3 + $ 14 × 1. BH THE BH3 2. H O NaOH '2 2' Click and drag to start drawing a structure. F4 Q W E R A S D % 905 LL F5 F6 F7 © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility < & 6 7 27 8 T Y U G H I F8 F9 F10 F11 F12 9 0 J K L P + // command option Z X C V B N M H H rol option commandarrow_forwardAG/F-2° V 3. Before proceeding with this problem you may want to glance at p. 466 of your textbook where various oxo-phosphorus derivatives and their oxidation states are summarized. Shown below are Latimer diagrams for phosphorus at pH values at 0 and 14: -0.93 +0.38 -0.50 -0.51 -0.06 H3PO4 →H4P206 →H3PO3 →→H3PO₂ → P → PH3 Acidic solution Basic solution -0.28 -0.50 3--1.12 -1.57 -2.05 -0.89 PO HPO H₂PO₂ →P → PH3 -1.73 a) Under acidic conditions, H3PO4 can be reduced into H3PO3 directly (-0.28V), or via the formation and reduction of H4P206 (-0.93/+0.38V). Calculate the values of AG's for both processes; comment. (3 points) 0.5 PH P 0.0 -0.5 -1.0- -1.5- -2.0 H.PO, -2.3+ -3 -2 -1 1 2 3 2 H,PO, b) Frost diagram for phosphorus under acidic conditions is shown. Identify possible disproportionation and comproportionation processes; write out chemical equations describing them. (2 points) H,PO 4 S Oxidation stale, Narrow_forward
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