
Concept explainers
Uses
Hypothesis Testing with Two Samples Hypothesis testing enables you to determine whether differences in samples indicate actual differences in populations or are merely due to sampling error. For instance, a study conducted on about 1400 American children in a variety of settings compared the behavior of the children who attended day care with the behavior of those who stayed home. Aggressive behavior such as stealing toys, pushing other children, and starting fights was measured in both groups. The study showed that children who attended day care for more than 30 hours per week were about three times more likely to be aggressive than those who stayed home. Although the aggressive behavior observed in the study was well within the normal
Abuses
Confounding Variables The U.S. study found that the results were the same regardless of quality of the day care center and income of the family. However, the overall quality of care experienced by most of the children studied could be the problem—a survey of American day care centers that measured aspects such as number and expertise of caregivers found that only 10 percent of American day care centers provided high-quality care.
A similar study of preschoolers and aggressive behavior in Norway, where day care centers are subject to strict standards and the ratio of adult caregivers to children is high, found that the link between day care attendance and aggressive behavior was minimal. Another Norwegian study included an additional variable, differences between siblings, and found no relationship between day care attendance and behavior problems. These additional variables that are often out of the researcher’s control are known as confounding variables.
Study Funding A series of studies was conducted on various methods for reducing the number of cigarettes that smokers smoke. The study compared smokers who were simply told to smoke less and those who tried methods such as nicotine replacement therapy, electronic cigarettes, and using reduced tar, carbon, or nicotine cigarettes. Some methods were shown to be effective in reducing the number of cigarettes smoked.
Some of the studies were funded by the tobacco industry, which could profit from promoting strategies other than quitting as beneficial to smokers’ health. When dealing with statistics, it is always good to know who is paying for a study, and whether the researchers are unbiased.
1. Confounding Variables A pharmaceutical company has applied for approval to market a new arthritis medication. The research involved a test group that was given the medication and another test group that was given a placebo. Describe some possible confounding variables that could influence the results of the study.

To describe: The possible confounding variables that could influence the results of the study.
Answer to Problem 1UA
The possible confounding variables that could influence the results of the study are age and medical report.
Explanation of Solution
Given info:
The study based on the pharmaceutical company has applied for the approval to market a new arthritis medication.
Justification:
Confounding variable:
Confounding variable is a third variable that is associated with explanatory and response variables. In other words, confounding variable influences the response variable.
Here, the possible confounding variables that could influence the results of the study are age and medical report.
Want to see more full solutions like this?
Chapter 8 Solutions
Elementary Statistics: Picturing the World (7th Edition)
- This is the information about the actors who won the Best Actor Oscar: Best actors 44 41 62 52 41 34 34 52 41 37 38 34 32 40 43 56 41 39 49 57 35 30 39 41 44 41 38 42 52 51 49 35 47 31 47 37 57 42 45 42 44 62 43 42 48 49 56 38 60 30 40 42 36 76 39 53 45 36 62 43 51 32 42 54 52 37 38 32 45 60 46 40 36 47 29 43 a. What is the variable? What type? b. Construct an interval-frequency table, with columns containing: class mark, absolute frequency, relative frequency, cumulative frequency, cumulative relative frequency, and percentage frequency.arrow_forwardans c plsarrow_forwardCritically analyze the following graph and, based on statistical information, indicate the type of error it presents IN NO MORE THAN 3 LINES SCOTCEN POLL OF POLLS SHOULD SCOTLAND BE INDEPENDENT? NO 52% YES 58% LIVE CAW NAS & 28.30 HAS KILLED MORE THAN 2,600 IN WEST AFRICA, WORLD HEALTH ORG. BROOKEBCNNarrow_forward
- Critically analyze the following graph and, based on statistical information, indicate the type of error it presents IN NO MORE THAN 3 LINES PRESIDENTIAL PREFERENCES RODOLFO CARTER 3% (+2pts) EVELYN MATTHEI 22% (+6pts) With the exception of President Boric, could you tell me who you would like to be the next president of Chile? CAMILA VALLEJO 4% (+2pts) JOSÉ ANTONIO KAST 19% (+5pts) MICHELLE BACHELET 6% (+1pts)arrow_forwardCritically analyze the following graph and, based on statistical information, indicate the type of error it presents IN NO MORE THAN 3 LINES 13% APPROVE 4% DOESN'T KNOW DOESN'T RESPOND 5% NEITHER APPROVES NOR DISAPPROVES 78% DISAPPROVES SURVEY PRESIDENTIAL APPROVAL DROPS TO 13%arrow_forwardPlease help with this following question I'm not too sure if question (a) and (b) are correct and not sure how to calculate (c) The csv data is below "","New","Current" "1","67",66 "2","77",73 "3","76",73 "4","76",76 "5","77",79 "6","84",76 "7","71",78 "8","84",72 "9","73",76 "10","71",73 "11","72",77 "12","70",72 "13","75",72 "14","84",71 "15","77",73 "16","65",72 "17","69",73 "18","71",73 "19","79",71 "20","75",78 "21","76",69 "22","73",74 "23","76",71 "24","64",74 "25","81",78 "26","79",76 "27","70",77 "28","79",71 "29","84",73 "30","79",69 "31","69",72 "32","81",76 "33","77",70 "34","77",71 "35","71",69 "36","67",72 "37","70",76 "38","77",73 "39","82",73 "40","72",73arrow_forward
- Please help me answer the following question(c) A previous study found that 15% of nurses reported participating in mental health support programs.From the 96% found in (b) , can you conclude that proportion of nurses reported participating in mental health support programs p(current), has changed from the previous study?(Yes/No) because the confidence interval in (b) (captures/does not capture) 15%.(d) Refer to your answer in (b) : The Alberta Nurses Association expects that not more than 23 % of nurses will participate in the survey on mental health support programs. Given the result in part (b) can we conclude that this expectation is reasonable?(Yes/No) because the (upper bound/lower bound) of the 96% confidence interval is (less than/not less than/greater than) 23%. The Alberta Nursing Association conducts an annual survey to estimate the proportion of nurses who participate in mental health support programs. The most recent application of this survey involved a random sample of…arrow_forwardPlease help me solve this questionThis is what was in the csv file:"","Diabetic","Heart Disease""1",32644,30646"2",789,1670"3",12802,36274"4",2177,5011"5",1910,3300"6",3320,4256"7",61425,39053"8",19768,28635"9",19502,39546"10",5642,12182"11",107864,152098"12",29918,60433"13",2397,3550"14",41559,34705"15",49169,57948"16",72853,83100"17",2155,2873"18",140220,134517"19",28181,26212"20",18850,38637"21",69564,68582"22",13897,12613"23",6868,9138"24",9735,4767"25",12102,13447"26",36571,50010"27",44665,55141"28",26620,33970"29",25525,29766"30",14167,20206Q(b) From this, the relationship between these two variables is (non-existent/positive/negative) . I can categorize this relationship as being (strong/weak/moderate).Q(c) Drop down is (+/-)Q(d) Drop downs in order are __% of the (average/median/variation/standard deviation) in the (the number of people diagnosed with heart disease/the number of people diagnosed with diabetes)−variable can be explained by its (linear relationship/relationship)…arrow_forwardPlease help me answer the following question The drop down for question (e, f, and g) is (YES/NO) Based on the P-value above, the assumption of equal variances among the four machines (Is Met/Is Not Met) Based on the data, the average fill for machine 3 is (statistically lower than/statistically higher than/the same as/not statistically different than/statistically different than/Hard to say then when comparing to/Refuse to say when comparing to) machine 1.arrow_forward
- Business Discussarrow_forward1 for all k, and set o (ii) Let X1, X2, that P(Xkb) = x > 0. Xn be independent random variables with mean 0, suppose = and Var Xk. Then, for 0x) ≤2 exp-tx+121 Στ k=1arrow_forwardLemma 1.1 Suppose that g is a non-negative, non-decreasing function such that E g(X) 0. Then, E g(|X|) P(|X|> x) ≤ g(x)arrow_forward
- College Algebra (MindTap Course List)AlgebraISBN:9781305652231Author:R. David Gustafson, Jeff HughesPublisher:Cengage LearningGlencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw HillHolt Mcdougal Larson Pre-algebra: Student Edition...AlgebraISBN:9780547587776Author:HOLT MCDOUGALPublisher:HOLT MCDOUGAL



