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In some nucleophilic substitutions under
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- The bicyclic heterocycles quinoline and indole undergo electrophilic aromatic substitution to give the products shown. (a) Explain why electrophilic substitution occurs on the ring without the N atom for quinoline, but occurs on the ring with the N atom in indole. (b) Explain why electrophilic substitution occurs more readily at C8 than C7 in quinoline. (c) Explain why electrophilic substitution occurs more readily at C3 rather than C2 of indole.arrow_forwardThe reaction of butan-2-ol with concentrated aqueous HBr goes with partial racemization, giving more inversion thanretention of configuration. Propose a mechanism that accounts for racemization with excess inversion.(b) Under the same conditions, an optically active sample of trans-2-bromocyclopentanol reacts with concentrated aqueous HBr to give an optically inactive product, (racemic) trans-1,2-dibromocyclopentane. Proposea mechanism to show how this reaction goes with apparently complete retention of configuration, yet withracemization. (Hint: Draw out the mechanism of the reaction of cyclopentene with Br2 in water to give thestarting material, trans-2- bromocyclopentanol. Consider how parts of this mechanism might be involved in thereaction with HBr.)arrow_forward(a) What alkene yields A and B when it is treated with Br2 in CCl4? (b) What alkene yields C and D under the same conditions?arrow_forward
- Dehydration of 1,2,2-trimethylcyclohexanol with H2SO4 affords 1-tertbutylcyclopentene as a minor product. (a) Draw a stepwise mechanism that shows how this alkene is formed. (b) Draw other alkenes formed in this dehydration. At least one must contain a five-membered ring.arrow_forwardWhen (R)-6-bromo-2,6-dimethylnonane is dissolved in CH3OH, nucleophilic substitution yields an optically inactive solution. When the isomeric halide (R)-2-bromo-2,5-dimethylnonane is dissolved in CH3OH under the same conditions, nucleophilic substitution forms an optically active solution. Draw the products formed in each reaction, and explain why the difference in optical activity is observed.arrow_forwardDehydration of 1,2,2-trimethylcyclohexanol with H2SO4 affords 1-tert-butylcyclopentene as a minor product. (a) Draw a stepwise mechanism that shows how this alkene is formed. (b) Draw other alkenes formed in this dehydration. At least one must contain a five-membered ring.arrow_forward
- Consider the tetracyclic compound with rings labeled A–D. (a) Which ring is the most reactive in electrophilic aromatic substitution? (b) Which ring is the least reactive in electrophilic aromatic substitution?arrow_forwardQ3. 2-Bromopentane, when treated with alcoholic KOH yields a mixture of three alkenes A, B and C. Identify A, B and C. Which is predominant? Q4 Which statement below about Sn1 reactions is incorrect? (A) SN1 reactions are stepwise and have intermediates. (B) The slow step in a SN1 reaction is formation of the carbocation intermediate. (C) SN1 reactions have first order kinetics which means only the alkyl halide is involved in the rate limiting step. (D) The products of a SN1 reaction will be a pair of enantiomers. (E) An aprotic solvent is best for Sn1 reactions as they tend to help stabilize carbocation intermediates.arrow_forwardWhen (ft)-6-bromo-2,6-dimethylnonane is dissolved in CH3OH, nucleophilic substitution yields an optically inactive solution. When the isomeric halide (fl)-2-bromo-2,5- dimethylnonane is dissolved in CH3OH under the same conditions, nucleophilic substitution forms an optically active solution. Draw the products formed in each reaction, and explain why the difference in optical activity is observed.arrow_forward
- The alkyl halide cis-1-bromo-4-methycyclohexane (A) undergoes a (c) substitution reaction when treated with H,0 to give a racemic mixture which is made up of product B and C. (i) What is a racemic mixture? (ii) Draw all the possible diastereoisomers of the compound below. Br Brarrow_forwardConsider the tetracyclic aromatic compound drawn below, with rings labeled as A, B, C, and D. (a) Which of the four rings is most reactive in electrophilic aromatic substitution? (b) Which of the four rings is least reactive in electrophilic aromatic substitution? (c) What are the major product(s) formed when this compound is treated with one equivalent of Br2?arrow_forwardWhen tert-butyl bromide is heated with an equal amount of ethanol in an inert solvent, one of the products is ethyl tert-butyl ether. (a) What happens to the reaction rate if the concentration of ethanol is doubled?arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning