(a) Interpretation: To draw the given structure corresponding to each name. Concept introduction: Alkyl halides are organic molecules that contains a halogen atom X bonded to sp 3 hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Question

Want to see more full solutions like this?

Answer 1

Question

Chapter 7, Problem 7.45P

Interpretation Introduction

(a)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is isopropyl bromide

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 1

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 2

The bromide is in the middle carbon make it into a isopropyl.

Conclusion

Thus given the structure name is isopropyl bromide

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 3

Interpretation Introduction

(b)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is 3-bromo-4-ethylheptane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 4

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 5

Starting from first carbon the bromide is in the third carbon and ethyl is in fourth carbon, and there are total of seven carbon so 3-bromo-4-ethylheptane.

Conclusion

Thus given the structure name is 3-bromo-4-ethylheptane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 6

Interpretation Introduction

(c)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is 1, 1-dichloro-2-methylcyclohexane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 7

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 8

Starting from first carbon the two chlorine is in the first carbon and methyl is in second carbon, and there are total of six carbon and ring so 1, 1-dichloro-2-methylcyclohexane.

Conclusion

Thus Given the structure name is 1, 1-dichloro-2-methylcyclohexane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 9

Interpretation Introduction

(d)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is trans-1-chloro-3-iodocyclobutane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 10

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 11

Starting from first carbon the chlorine is in the first carbon and methyl is in third carbon, and there are total of four carbon and ring so trans-1-chloro-3-iodocyclobutane.

Conclusion

Thus Given the structure name is trans-1-chloro-3-iodocyclobutane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 12

Interpretation Introduction

(e)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is 1-bromo-4-ethyl-3-fluorooctane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 13

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 14

Starting from first carbon the bromide is in the first carbon and methyl is in fourth carbon, and there are total of eight carbon so 1-bromo-4-ethyl-3-fluorooctane.

Conclusion

Thus Given the structure name is 1-bromo-4-ethyl-3-fluorooctane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 15

Interpretation Introduction

(f)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is (3S)-3-iodo-2-methylnonane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 16

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 17

Starting from first carbon the iodo is in the third carbon and methyl is in second carbon, and there are total of nine carbon so (3S)-3-iodo-2-methylnonane.

Conclusion

Thus Given the structure name is (3S)-3-iodo-2-methylnonane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 18

Interpretation Introduction

(g)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is (1 R, 2R)-trans-1-bromo-2-chlorocyclohexane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 19

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 20

Starting from first carbon the chloro and bromo is in the first carbon and there are total of six carbon so (1 R, 2R)-trans-1-bromo-2-chlorocyclohexane.

Conclusion

Thus Given the structure name is (1 R, 2R)-trans-1-bromo-2-chlorocyclohexane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 21

Interpretation Introduction

(h)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is (5R)-4, 4, 5-trichloro-3, 3-dimethyldecane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 22

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 23

Starting from first carbon the chloro is in the fourth and fifth carbon and there are total of ten carbons so (5R)-4, 4, 5-trichloro-3, 3-dimethyldecane.

Conclusion

Thus Given the structure name is (5R)-4, 4, 5-trichloro-3, 3-dimethyldecane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 24

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

Calculate the pH and the pOH of each of the following solutions at 25 °C for which the substances ionize completely: (a) 0.200 M HCl

Calculate the pH and the pOH of each of the following solutions at 25 °C for which the substances ionize completely: (a) 0.000259 M HClO4

What is the pH of a 1.0 L buffer made with 0.300 mol of HF (Ka = 6.8 × 10⁻⁴) and 0.200 mol of NaF to which 0.160 mol of NaOH were added?

Answer 2

Question

Chapter 7, Problem 7.45P

Interpretation Introduction

(a)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is isopropyl bromide

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 1

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 2

The bromide is in the middle carbon make it into a isopropyl.

Conclusion

Thus given the structure name is isopropyl bromide

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 3

Interpretation Introduction

(b)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is 3-bromo-4-ethylheptane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 4

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 5

Starting from first carbon the bromide is in the third carbon and ethyl is in fourth carbon, and there are total of seven carbon so 3-bromo-4-ethylheptane.

Conclusion

Thus given the structure name is 3-bromo-4-ethylheptane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 6

Interpretation Introduction

(c)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is 1, 1-dichloro-2-methylcyclohexane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 7

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 8

Starting from first carbon the two chlorine is in the first carbon and methyl is in second carbon, and there are total of six carbon and ring so 1, 1-dichloro-2-methylcyclohexane.

Conclusion

Thus Given the structure name is 1, 1-dichloro-2-methylcyclohexane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 9

Interpretation Introduction

(d)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is trans-1-chloro-3-iodocyclobutane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 10

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 11

Starting from first carbon the chlorine is in the first carbon and methyl is in third carbon, and there are total of four carbon and ring so trans-1-chloro-3-iodocyclobutane.

Conclusion

Thus Given the structure name is trans-1-chloro-3-iodocyclobutane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 12

Interpretation Introduction

(e)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is 1-bromo-4-ethyl-3-fluorooctane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 13

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 14

Starting from first carbon the bromide is in the first carbon and methyl is in fourth carbon, and there are total of eight carbon so 1-bromo-4-ethyl-3-fluorooctane.

Conclusion

Thus Given the structure name is 1-bromo-4-ethyl-3-fluorooctane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 15

Interpretation Introduction

(f)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is (3S)-3-iodo-2-methylnonane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 16

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 17

Starting from first carbon the iodo is in the third carbon and methyl is in second carbon, and there are total of nine carbon so (3S)-3-iodo-2-methylnonane.

Conclusion

Thus Given the structure name is (3S)-3-iodo-2-methylnonane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 18

Interpretation Introduction

(g)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is (1 R, 2R)-trans-1-bromo-2-chlorocyclohexane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 19

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 20

Starting from first carbon the chloro and bromo is in the first carbon and there are total of six carbon so (1 R, 2R)-trans-1-bromo-2-chlorocyclohexane.

Conclusion

Thus Given the structure name is (1 R, 2R)-trans-1-bromo-2-chlorocyclohexane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 21

Interpretation Introduction

(h)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is (5R)-4, 4, 5-trichloro-3, 3-dimethyldecane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 22

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 23

Starting from first carbon the chloro is in the fourth and fifth carbon and there are total of ten carbons so (5R)-4, 4, 5-trichloro-3, 3-dimethyldecane.

Conclusion

Thus Given the structure name is (5R)-4, 4, 5-trichloro-3, 3-dimethyldecane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 24

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 7, Problem 7.45P

Interpretation Introduction

(a)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is isopropyl bromide

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 1

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 2

The bromide is in the middle carbon make it into a isopropyl.

Conclusion

Thus given the structure name is isopropyl bromide

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 3

Interpretation Introduction

(b)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is 3-bromo-4-ethylheptane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 4

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 5

Starting from first carbon the bromide is in the third carbon and ethyl is in fourth carbon, and there are total of seven carbon so 3-bromo-4-ethylheptane.

Conclusion

Thus given the structure name is 3-bromo-4-ethylheptane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 6

Interpretation Introduction

(c)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is 1, 1-dichloro-2-methylcyclohexane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 7

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 8

Starting from first carbon the two chlorine is in the first carbon and methyl is in second carbon, and there are total of six carbon and ring so 1, 1-dichloro-2-methylcyclohexane.

Conclusion

Thus Given the structure name is 1, 1-dichloro-2-methylcyclohexane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 9

Interpretation Introduction

(d)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is trans-1-chloro-3-iodocyclobutane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 10

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 11

Starting from first carbon the chlorine is in the first carbon and methyl is in third carbon, and there are total of four carbon and ring so trans-1-chloro-3-iodocyclobutane.

Conclusion

Thus Given the structure name is trans-1-chloro-3-iodocyclobutane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 12

Interpretation Introduction

(e)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is 1-bromo-4-ethyl-3-fluorooctane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 13

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 14

Starting from first carbon the bromide is in the first carbon and methyl is in fourth carbon, and there are total of eight carbon so 1-bromo-4-ethyl-3-fluorooctane.

Conclusion

Thus Given the structure name is 1-bromo-4-ethyl-3-fluorooctane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 15

Interpretation Introduction

(f)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is (3S)-3-iodo-2-methylnonane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 16

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 17

Starting from first carbon the iodo is in the third carbon and methyl is in second carbon, and there are total of nine carbon so (3S)-3-iodo-2-methylnonane.

Conclusion

Thus Given the structure name is (3S)-3-iodo-2-methylnonane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 18

Interpretation Introduction

(g)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is (1 R, 2R)-trans-1-bromo-2-chlorocyclohexane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 19

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 20

Starting from first carbon the chloro and bromo is in the first carbon and there are total of six carbon so (1 R, 2R)-trans-1-bromo-2-chlorocyclohexane.

Conclusion

Thus Given the structure name is (1 R, 2R)-trans-1-bromo-2-chlorocyclohexane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 21

Interpretation Introduction

(h)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is (5R)-4, 4, 5-trichloro-3, 3-dimethyldecane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 22

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 23

Starting from first carbon the chloro is in the fourth and fifth carbon and there are total of ten carbons so (5R)-4, 4, 5-trichloro-3, 3-dimethyldecane.

Conclusion

Thus Given the structure name is (5R)-4, 4, 5-trichloro-3, 3-dimethyldecane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 24

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 7, Problem 7.45P

Interpretation Introduction

(a)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is isopropyl bromide

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 1

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 2

The bromide is in the middle carbon make it into a isopropyl.

Conclusion

Thus given the structure name is isopropyl bromide

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 3

Interpretation Introduction

(b)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is 3-bromo-4-ethylheptane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 4

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 5

Starting from first carbon the bromide is in the third carbon and ethyl is in fourth carbon, and there are total of seven carbon so 3-bromo-4-ethylheptane.

Conclusion

Thus given the structure name is 3-bromo-4-ethylheptane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 6

Interpretation Introduction

(c)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is 1, 1-dichloro-2-methylcyclohexane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 7

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 8

Starting from first carbon the two chlorine is in the first carbon and methyl is in second carbon, and there are total of six carbon and ring so 1, 1-dichloro-2-methylcyclohexane.

Conclusion

Thus Given the structure name is 1, 1-dichloro-2-methylcyclohexane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 9

Interpretation Introduction

(d)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is trans-1-chloro-3-iodocyclobutane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 10

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 11

Starting from first carbon the chlorine is in the first carbon and methyl is in third carbon, and there are total of four carbon and ring so trans-1-chloro-3-iodocyclobutane.

Conclusion

Thus Given the structure name is trans-1-chloro-3-iodocyclobutane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 12

Interpretation Introduction

(e)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is 1-bromo-4-ethyl-3-fluorooctane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 13

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 14

Starting from first carbon the bromide is in the first carbon and methyl is in fourth carbon, and there are total of eight carbon so 1-bromo-4-ethyl-3-fluorooctane.

Conclusion

Thus Given the structure name is 1-bromo-4-ethyl-3-fluorooctane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 15

Interpretation Introduction

(f)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is (3S)-3-iodo-2-methylnonane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 16

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 17

Starting from first carbon the iodo is in the third carbon and methyl is in second carbon, and there are total of nine carbon so (3S)-3-iodo-2-methylnonane.

Conclusion

Thus Given the structure name is (3S)-3-iodo-2-methylnonane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 18

Interpretation Introduction

(g)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is (1 R, 2R)-trans-1-bromo-2-chlorocyclohexane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 19

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 20

Starting from first carbon the chloro and bromo is in the first carbon and there are total of six carbon so (1 R, 2R)-trans-1-bromo-2-chlorocyclohexane.

Conclusion

Thus Given the structure name is (1 R, 2R)-trans-1-bromo-2-chlorocyclohexane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 21

Interpretation Introduction

(h)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is (5R)-4, 4, 5-trichloro-3, 3-dimethyldecane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 22

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 23

Starting from first carbon the chloro is in the fourth and fifth carbon and there are total of ten carbons so (5R)-4, 4, 5-trichloro-3, 3-dimethyldecane.

Conclusion

Thus Given the structure name is (5R)-4, 4, 5-trichloro-3, 3-dimethyldecane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 24

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 7, Problem 7.45P

Interpretation Introduction

(a)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is isopropyl bromide

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 1

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 2

The bromide is in the middle carbon make it into a isopropyl.

Conclusion

Thus given the structure name is isopropyl bromide

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 3

Interpretation Introduction

(b)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is 3-bromo-4-ethylheptane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 4

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 5

Starting from first carbon the bromide is in the third carbon and ethyl is in fourth carbon, and there are total of seven carbon so 3-bromo-4-ethylheptane.

Conclusion

Thus given the structure name is 3-bromo-4-ethylheptane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 6

Interpretation Introduction

(c)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is 1, 1-dichloro-2-methylcyclohexane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 7

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 8

Starting from first carbon the two chlorine is in the first carbon and methyl is in second carbon, and there are total of six carbon and ring so 1, 1-dichloro-2-methylcyclohexane.

Conclusion

Thus Given the structure name is 1, 1-dichloro-2-methylcyclohexane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 9

Interpretation Introduction

(d)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is trans-1-chloro-3-iodocyclobutane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 10

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 11

Starting from first carbon the chlorine is in the first carbon and methyl is in third carbon, and there are total of four carbon and ring so trans-1-chloro-3-iodocyclobutane.

Conclusion

Thus Given the structure name is trans-1-chloro-3-iodocyclobutane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 12

Interpretation Introduction

(e)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is 1-bromo-4-ethyl-3-fluorooctane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 13

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 14

Starting from first carbon the bromide is in the first carbon and methyl is in fourth carbon, and there are total of eight carbon so 1-bromo-4-ethyl-3-fluorooctane.

Conclusion

Thus Given the structure name is 1-bromo-4-ethyl-3-fluorooctane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 15

Interpretation Introduction

(f)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is (3S)-3-iodo-2-methylnonane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 16

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 17

Starting from first carbon the iodo is in the third carbon and methyl is in second carbon, and there are total of nine carbon so (3S)-3-iodo-2-methylnonane.

Conclusion

Thus Given the structure name is (3S)-3-iodo-2-methylnonane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 18

Interpretation Introduction

(g)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is (1 R, 2R)-trans-1-bromo-2-chlorocyclohexane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 19

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 20

Starting from first carbon the chloro and bromo is in the first carbon and there are total of six carbon so (1 R, 2R)-trans-1-bromo-2-chlorocyclohexane.

Conclusion

Thus Given the structure name is (1 R, 2R)-trans-1-bromo-2-chlorocyclohexane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 21

Interpretation Introduction

(h)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is (5R)-4, 4, 5-trichloro-3, 3-dimethyldecane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 22

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 23

Starting from first carbon the chloro is in the fourth and fifth carbon and there are total of ten carbons so (5R)-4, 4, 5-trichloro-3, 3-dimethyldecane.

Conclusion

Thus Given the structure name is (5R)-4, 4, 5-trichloro-3, 3-dimethyldecane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 24

Answer 6

Chapter 7, Problem 7.45P

Interpretation Introduction

(a)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is isopropyl bromide

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 1

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 2

The bromide is in the middle carbon make it into a isopropyl.

Conclusion

Thus given the structure name is isopropyl bromide

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 3

Answer 7

Chapter 7, Problem 7.45P

Interpretation Introduction

(a)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Answer 8

Expert Solution

Answer to Problem 7.45P

Given the structure name is isopropyl bromide

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 1

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 2

The bromide is in the middle carbon make it into a isopropyl.

Answer 13

Conclusion

Thus given the structure name is isopropyl bromide

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 3

Answer 14

Interpretation Introduction

(b)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is 3-bromo-4-ethylheptane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 4

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 5

Starting from first carbon the bromide is in the third carbon and ethyl is in fourth carbon, and there are total of seven carbon so 3-bromo-4-ethylheptane.

Conclusion

Thus given the structure name is 3-bromo-4-ethylheptane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 6

Answer 15

Interpretation Introduction

(b)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Answer 16

Expert Solution

Answer to Problem 7.45P

Given the structure name is 3-bromo-4-ethylheptane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 4

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Expert Solution

Answer 20

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 5

Starting from first carbon the bromide is in the third carbon and ethyl is in fourth carbon, and there are total of seven carbon so 3-bromo-4-ethylheptane.

Answer 21

Conclusion

Thus given the structure name is 3-bromo-4-ethylheptane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 6

Answer 22

Interpretation Introduction

(c)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is 1, 1-dichloro-2-methylcyclohexane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 7

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 8

Starting from first carbon the two chlorine is in the first carbon and methyl is in second carbon, and there are total of six carbon and ring so 1, 1-dichloro-2-methylcyclohexane.

Conclusion

Thus Given the structure name is 1, 1-dichloro-2-methylcyclohexane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 9

Answer 23

Interpretation Introduction

(c)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Answer 24

Expert Solution

Answer to Problem 7.45P

Given the structure name is 1, 1-dichloro-2-methylcyclohexane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 7

Answer 25

Expert Solution

Answer 26

Expert Solution

Answer 27

Expert Solution

Answer 28

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 8

Starting from first carbon the two chlorine is in the first carbon and methyl is in second carbon, and there are total of six carbon and ring so 1, 1-dichloro-2-methylcyclohexane.

Answer 29

Conclusion

Thus Given the structure name is 1, 1-dichloro-2-methylcyclohexane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 9

Answer 30

Interpretation Introduction

(d)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is trans-1-chloro-3-iodocyclobutane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 10

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 11

Starting from first carbon the chlorine is in the first carbon and methyl is in third carbon, and there are total of four carbon and ring so trans-1-chloro-3-iodocyclobutane.

Conclusion

Thus Given the structure name is trans-1-chloro-3-iodocyclobutane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 12

Answer 31

Interpretation Introduction

(d)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Answer 32

Expert Solution

Answer to Problem 7.45P

Given the structure name is trans-1-chloro-3-iodocyclobutane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 10

Answer 33

Expert Solution

Answer 34

Expert Solution

Answer 35

Expert Solution

Answer 36

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 11

Starting from first carbon the chlorine is in the first carbon and methyl is in third carbon, and there are total of four carbon and ring so trans-1-chloro-3-iodocyclobutane.

Answer 37

Conclusion

Thus Given the structure name is trans-1-chloro-3-iodocyclobutane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 12

Answer 38

Interpretation Introduction

(e)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is 1-bromo-4-ethyl-3-fluorooctane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 13

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 14

Starting from first carbon the bromide is in the first carbon and methyl is in fourth carbon, and there are total of eight carbon so 1-bromo-4-ethyl-3-fluorooctane.

Conclusion

Thus Given the structure name is 1-bromo-4-ethyl-3-fluorooctane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 15

Answer 39

Interpretation Introduction

(e)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Answer 40

Expert Solution

Answer to Problem 7.45P

Given the structure name is 1-bromo-4-ethyl-3-fluorooctane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 13

Answer 41

Expert Solution

Answer 42

Expert Solution

Answer 43

Expert Solution

Answer 44

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 14

Starting from first carbon the bromide is in the first carbon and methyl is in fourth carbon, and there are total of eight carbon so 1-bromo-4-ethyl-3-fluorooctane.

Answer 45

Conclusion

Thus Given the structure name is 1-bromo-4-ethyl-3-fluorooctane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 15

Answer 46

Interpretation Introduction

(f)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is (3S)-3-iodo-2-methylnonane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 16

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 17

Starting from first carbon the iodo is in the third carbon and methyl is in second carbon, and there are total of nine carbon so (3S)-3-iodo-2-methylnonane.

Conclusion

Thus Given the structure name is (3S)-3-iodo-2-methylnonane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 18

Answer 47

Interpretation Introduction

(f)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Answer 48

Expert Solution

Answer to Problem 7.45P

Given the structure name is (3S)-3-iodo-2-methylnonane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 16

Answer 49

Expert Solution

Answer 50

Expert Solution

Answer 51

Expert Solution

Answer 52

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 17

Starting from first carbon the iodo is in the third carbon and methyl is in second carbon, and there are total of nine carbon so (3S)-3-iodo-2-methylnonane.

Answer 53

Conclusion

Thus Given the structure name is (3S)-3-iodo-2-methylnonane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 18

Answer 54

Interpretation Introduction

(g)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is (1 R, 2R)-trans-1-bromo-2-chlorocyclohexane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 19

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 20

Starting from first carbon the chloro and bromo is in the first carbon and there are total of six carbon so (1 R, 2R)-trans-1-bromo-2-chlorocyclohexane.

Conclusion

Thus Given the structure name is (1 R, 2R)-trans-1-bromo-2-chlorocyclohexane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 21

Answer 55

Interpretation Introduction

(g)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Answer 56

Expert Solution

Answer to Problem 7.45P

Given the structure name is (1 R, 2R)-trans-1-bromo-2-chlorocyclohexane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 19

Answer 57

Expert Solution

Answer 58

Expert Solution

Answer 59

Expert Solution

Answer 60

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 20

Starting from first carbon the chloro and bromo is in the first carbon and there are total of six carbon so (1 R, 2R)-trans-1-bromo-2-chlorocyclohexane.

Answer 61

Conclusion

Thus Given the structure name is (1 R, 2R)-trans-1-bromo-2-chlorocyclohexane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 21

Answer 62

Interpretation Introduction

(h)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Expert Solution

Answer to Problem 7.45P

Given the structure name is (5R)-4, 4, 5-trichloro-3, 3-dimethyldecane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 22

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 23

Starting from first carbon the chloro is in the fourth and fifth carbon and there are total of ten carbons so (5R)-4, 4, 5-trichloro-3, 3-dimethyldecane.

Conclusion

Thus Given the structure name is (5R)-4, 4, 5-trichloro-3, 3-dimethyldecane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 24

Answer 63

Interpretation Introduction

(h)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Answer 64

Expert Solution

Answer to Problem 7.45P

Given the structure name is (5R)-4, 4, 5-trichloro-3, 3-dimethyldecane

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 22

Answer 65

Expert Solution

Answer 66

Expert Solution

Answer 67

Expert Solution

Answer 68

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Organic Chemistry, Chapter 7, Problem 7.45P , additional homework tip 23

Starting from first carbon the chloro is in the fourth and fifth carbon and there are total of ten carbons so (5R)-4, 4, 5-trichloro-3, 3-dimethyldecane.