
(a)
Interpretation:
The enthalpy for the formation of hydrogen chloride is whether exothermic or endothermic is to be determined.
Concept Introduction:
Enthalpy
The value of heat formed in a reaction
If the value obtained for
(b)
Interpretation:
At equilibrium the formation of hydrogen chloride is whether reaction or product favored is to be determined.
Concept Introduction:
Equilibrium constant: It is the ratio of products to reactants has a constant value when the reaction is in equilibrium at a certain temperature. And it is represented by the letter K.
For a reaction,
The equilibrium constant is,
where,
a, b, c and d are the
If
(c)
Interpretation:
The effect on the equilibrium of each given changes in formation of hydrogen chloride is to be determined.
Concept Introduction:
Enthalpy
If the value obtained for
Le Chatelier’s principle: If an equilibrium is disturbed by changing conditions, the system will moves the equilibrium to reverse the change.
Factor’s that effect chemical equilibria:
- Concentration – Equilibrium will be affected by changing the concentration of reactant or product. If we increase the concentration of reactant system will try to reverse the change by favoring forward reaction and thus increase the concentration of products. Likewise adding products increase yield of reactants.
- Temperature – When the temperature increases equilibrium will shift in the endothermic direction, in the direction that absorbs heat. When the temperature decreases equilibrium will shift in the exothermic direction, in the direction that releases heat.
- Pressure – If the reaction consists of only liquid and solid reactants and products, pressure has no effect in the equilibrium.
In gas reactions if the number of moles has no change then there will be no effect by pressure on equilibrium.
If pressure increases then equilibrium will shift to the direction having less number of molecules and if pressure decreases system will shift to the direction having more number of molecules.

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Chapter 7 Solutions
FUND.OF GEN CHEM CHAP 1-13 W/ACCESS
- You have isolated a protein and determined that the native molecular weight of the holoenzyme is 160 kD using size exclusion chromatography. Analysis of this protein using SDS-PAGE revealed 2 bands, one at 100 kD and one at 30 kD. Describe the architecture of the polypeptide component of this enzyme.arrow_forwardIn a cell free preparation of beta-lactamase, penicillin is hydrolyzed in a D2O enriched assay. After one round of catalysis, where would you anticipate finding Deuterium? please help thank youarrow_forwardTo map the active site of -lactamase, the enzyme was hydrolyzed with trypsin to yield a hexapeptide (P1) with the following amino acids. Glu, Lys, Leu, Phe, Met, and Ser. Treatment of P1 with phenyl isothiocyanate yielded a PTH derivative of phenylalanine and a peptide (P2). Treatment of P1 with cyanogenbromide gave an acidic tetrapeptide (P3) and a dipeptide (P4).Treatment of P2 with 1-fluoro-2,4-dinitrobenzene, followed by complete hydrolysis, yields N-2,4-dinitrophenyl-Glu. P1, P2, and P3 contain the active site serine. question: the b-lactamase hydrolyzes the lactam-ring in antibiotics like penicillin. Describe the mechanism, of hydrolysis, insuring to include the involvement of S, D, and K in the reaction sequence. Please help!arrow_forward
- Three of these amino acids participate in the proteolytic hydrolysis of polypeptides. Show the charge-relay network generated by the serine proteases and identify the nucleophilic species that initiates the hydrolysis. please help!arrow_forwardYou have isolated a protein and determined that the native molecular weight of the holoenzyme is 160 kD using size exclusion chromatography. Analysis of this protein using SDS-PAGE revealed 2 bands, one at 100 kD and one at 30 kD. 1. Describe the architecture of the polypeptide component of this enzyme. 2. The enzyme was found to be 0.829% NAD (by weight). What further can be said regarding the architecture? can you please help me with question number 2arrow_forwardTo map the active site of -lactamase, the enzyme was hydrolyzed with trypsin to yield a hexapeptide (P1) with the following amino acids. Glu, Lys, Leu, Phe, Met, and Ser. Treatment of P1 with phenyl isothiocyanate yielded a PTH derivative of phenylalanine and a peptide (P2). Treatment of P1 with cyanogenbromide gave an acidic tetrapeptide (P3) and a dipeptide (P4).Treatment of P2 with 1-fluoro-2,4-dinitrobenzene, followed by complete hydrolysis, yields N-2,4-dinitrophenyl-Glu. P1, P2, and P3 contain the active site serine. Question: although S, K, and D are involved in the catalysis, the E in this hexapeptide does not participate in the hydrolysis of the b-lactam ring. Why is that?arrow_forward
- To map the active site of beta-lactamase, the enzyme was hydrolyzed with trypsin to yield a hexapeptide (P1) with the following amino acids. Glu, Lys, Leu, Phe, Met, and Ser. a) Using the experimental results described below deduce the primary sequence of the active site hexapeptide. Treatment of P1 with phenyl isothiocyanate yielded a PTH derivative of phenylalanine and a peptide (P2). Treatment of P1 with cyanogenbromide gave an acidic tetrapeptide (P3) and a dipeptide (P4).Treatment of P2 with 1-fluoro-2,4-dinitrobenzene, followed by complete hydrolysis, yields N-2,4-dinitrophenyl-Glu. P1, P2, and P3 contain the active site serine. please help!arrow_forwardThe beta-lactamase hydrolyzes the lactam-ring in penicillin. Describe the mechanism of hydrolysis, insuring to include the involvement of S, D, & K in the reaction sequence. Please helparrow_forwardTo map the active site of beta-lactamase, the enzyme was hydrolyzed with trypsin to yield a hexapeptide (P1) with the following amino acids. Glu, Lys, Leu, Phe, Met, and Ser. Treatment of P1 with phenyl isothiocyanate yielded a PTH derivative of phenylalanine and a peptide (P2). Treatment of P1 with cyanogenbromide gave an acidic tetrapeptide (P3) and a dipeptide (P4).Treatment of P2 with 1-fluoro-2,4-dinitrobenzene, followed by complete hydrolysis, yields N-2,4-dinitrophenyl-Glu. P1, P2, and P3 contain the active site serine. Why doesn't D in this hexapeptide not participate in the hydrolysis of the beta-lactam ring even though S, K, and D are involved in the catalyst?arrow_forward
- To map the active site of -lactamase, the enzyme was hydrolyzed with trypsin to yield a hexapeptide (P1) with the following amino acids. Glu, Lys, Leu, Phe, Met, and Ser. Treatment of P1 with phenyl isothiocyanate yielded a PTH derivative of phenylalanine and a peptide (P2). Treatment of P1 with cyanogenbromide gave an acidic tetrapeptide (P3) and a dipeptide (P4).Treatment of P2 with 1-fluoro-2,4-dinitrobenzene, followed by complete hydrolysis, yields N-2,4-dinitrophenyl-Glu. P1, P2, and P3 contain the active site serine. Using the experimental results described above derive the primary sequence of the active site hexapeptide. Please help!arrow_forwardWhich type of enzyme catalyses the following reaction? oxidoreductase, transferase, hydrolase, lyase, isomerase, or ligase.arrow_forward+NH+ CO₂ +P H₂N + ATP H₂N NH₂ +ADParrow_forward
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