Concept explainers
(a)
Interpretation:
The electron-rich sites and electron-poor sites in the given elementary steps are to be identified.
Concept introduction:
An atom with partial or full negative charge is an electron-rich site whereas an atom with partial or full positive charge is an electron-poor site. In an elementary step, electrons tend to flow from an electron-rich site to an electron-poor site.
(b)
Interpretation:
In each of the given elementary steps, the appropriate curved arrows are to be drawn.
Concept introduction:
The curved arrow can be drawn from an electron-rich site to an electron-poor site to show the flow of electrons from the electron-rich site to the electron-poor site. The first curved arrow is drawn from the lone pair of the negatively charged atom of the electron-rich site to the less electronegative atom of the electron-poor site. The second curved arrow is drawn from the region between the less electronegative atom and more electronegative atom towards the more electronegative atom, indicating the breaking of the bond.
(c)
Interpretation:
The names of each elementary step are to be identified.
Concept introduction:
In the bimolecular substitution reaction
In nucleophilic addition step, the nucleophile adds to the polar
In the nucleophilic elimination step, the more electronegative atom bears full negative charge or partial negative charge. This electronegative atom forms a
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Organic Chemistry: Principles And Mechanisms: Study Guide/solutions Manual (second)
- Complete the mechanism for these Lewis acid-base reactions. Draw mechanistic arrows and partial charges where appropriate. Reaction A: CH₂NH₂ + HCl = 3 Reaction B: CH₂NH₂ + H₂O = 3 Reaction C: CH₂NH¯ + H₂O = 3 + Reaction D: CH₂NH 3 + H₂O 2 When each of these reactions has come to an equilibrium (where the relative amounts of each chemical species remains unchanged but the forward and reverse reactions are still occurring), predict whether each reaction will have more reactant or more product. Explain your predictions using your knowledge of atomic and molecular structures and electronegativity.arrow_forwardAlcohols are acidic in nature. Therefore, a strong base can abstract the acidic hydrogen atom of the alcohol in a process known as deprotonation. The alcohol forms an alkoxide ion by losing the proton attached to the oxygen atom of the hydroxyl ( -OH) group. The alkoxide formed can act as a base or a nucleophile depending on the substrate and reaction conditions. However, not all bases can abstract the acidic proton of alcohols and not all alcohols easily lose the proton. Deprotonation depends on the strength of the base and the acidity of the alcohol. Strong bases, such as NaNH2, can easily abstract a proton from almost all alcohols. Likewise, more acidic alcohols lose a proton more easily. Determine which of the following reactions would undergo deprotonation based on the strength of the base and the acidity of the alcohol. Check all that apply. ► View Available Hint(s) CH3CH,OH + NH3 →CH,CH,O-NH CH3 CH3 H3C-C-H+NH3 → H3 C-C-H OH O-NH CH3CH2OH + NaNH, → CH3CH,O-Na* + NH3 CHC12 Cl₂…arrow_forwardThe following is an example of a Fischer esterification reaction, sists of the six elementary steps shown. For each step (i-vi), (a) identify ali electron-rich sites and all electron-poor sites, (b) draw in the appropriate curved arrows to show the bond formation and bond breaking that occur, and (c) name the elementary step. CH, CH HO CH3 HO, HO CH3 (ii) CH, он он но CH H3C CH (ii) CH CH, OH но CH CH CH (rv) CH, CH. OH CH3 но H CH, H,CH CH H,C CH2 (v) CH3 CHs H,C CH2 (vi) CH, CH, H20 H-84, CHarrow_forward
- How might nucleophilic catalysis work?Draw out a possible mechanism.arrow_forwardIdentify the most acid proton on each molecule and explain your reasoning using ARIO. Pick a base that could deprotonate that proton, draw the mechanism (arrows) and products and estimate the pkas он HO. он OHCIarrow_forwardDraw a mechanism for this reaction. H₂C- CH3 -0- Interactive 3D display mode -CH3 H₂C CH₁₂ H₂C-O i Edit the reaction by drawing all steps in the appropriate boxes and connecting them with reaction arrows. Add charges where needed. Electron flow arrows should start on an atom or a bond and should end on an atom, bond, or location where a new bond should be created.arrow_forward
- Determine the mechanism and product for the given reaction by adding atoms, bonds, nonbonding electron pairs, and curved arrows. Acid and water are added in the second step. CH₂CH₂MgBr 2 Step 1: Add curved arrows. * MB Br → product Et₂ O Step 2: Aqueous workup. Complete the intermediate, then add curved arrows for the workup step. H : CLT: Mg Brarrow_forwardCOMPLETE THE MECHANISMarrow_forward(Please step by step solutions) Can you do the mechanism?arrow_forward
- Draw a detailed, step-wise mechanism for the reaction shown below. SHOW ALL BOND-FORMING AND BOND-BREAKING STEPS. SHOW ALL INTERMEDIATES. 1) NaOH 2) H3O* H3C H3C HOarrow_forwardFor the following reaction: 2) Draw both the organic and inorganic intermediate species. Include nonbonding electrons and charges, where applicable. 1) Add curved arrows for the first step. СHз Н H Нзс н н :ci: Нас- -CHз H нarrow_forwardAn acid anhydride can be formed under equilibrium conditions by reacting an ester with a carboxylic acid, as shown below. Reasonable yield is achieved if the equilibrium can be shifted by exploiting Le Châtelier's principle. -R" HO + + R ОН R' `OR" R `R' (a) Provide a complete, detailed mechanism for this reaction. (b) In general, the above equilibrium favors the reactants. However, if the ester that is used is the one shown here, then the equilibrium favors the products. Explain why. R' O.arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage LearningOrganic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning