(a)
Interpretation:
For each step of the given unimolecular elimination
Concept introduction:
An atom with partial or full negative charge is called an electron-rich site whereas an atom with partial or full positive charge is called an electron-poor site. An electron-rich atom has a lone pair of electrons whereas an electron-poor atom lacks an octet. In an elementary step, electrons tend to flow from an electron-rich site to an electron-poor site.
(b)
Interpretation:
Appropriate curved arrows are to be drawn to show the bond formation and bond breaking that occur in each step of the given unimolecular elimination
Concept introduction:
In an elementary step, electrons tend to flow from an electron-rich site to an electron-poor site. In the first step of unimolecular elimination
(c)
Interpretation:
Each step of the given unimolecular elimination
Concept introduction:
An elementary step in which a proton is transferred from an electron-poor site to an electron-rich site and one bond is broken and another is formed simultaneously is called the proton transfer step. An elementary step in which only single bond is broken is called the heterolysis step.
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Chapter 7 Solutions
ORG CHEM W/ EBOOK & SW5 + STUDY GUIDE
- Write the calculate the reaction quotient for the following system, if the partial pressure of all reactantsand products is 0.15 atm: NOCl (g) ⇌ NO (g) + Cl2 (g) H = 20.5 kcalarrow_forwardComplete the spectroscopy with structurearrow_forwardcould you answer the questions and draw the complete mechanismarrow_forward
- Complete the spectroscopy with structurearrow_forwardCalculate the reaction quotient for the reaction:NaOH (s) ⇌ Na+ (aq)+ OH- (aq) + 44.4 kJ [Na+] = 4.22 M [OH-] = 6.41 Marrow_forwardGiven the following concentrations for a system, calculate the value for the reaction quotient: Cl2(g)+ CS2(g) ⇌ CCl4(g)+ S2Cl2(g) Cl2 = 31.1 atm CS2 = 91.2 atm CCl4 = 2.12 atm S2Cl2 = 10.4 atmarrow_forward
- Match each chemical or item with the proper disposal or cleanup mwthod, Not all disposal and cleanup methods will be labeled. Metal sheets C, calcium, choroide solutions part A, damp metal pieces Part B, volumetric flask part A. a.Return to correct lables”drying out breaker. Place used items in the drawer.: Rinse with deionized water, dry as best you can, return to instructor. Return used material to the instructor.: Pour down the sink with planty of running water.: f.Pour into aqueous waste container. g.Places used items in garbage.arrow_forwardWrite the equilibrium constant expression for the following reaction: HNO2(aq) + H2O(l) ⇌ H3O+(aq) + NO2-(aq)arrow_forwardWrite the reaction quotient for: Pb2+(aq) + 2 Cl- (aq) ⇌ PbCl2(s)arrow_forward
- Write the equilibrium constant expression for the following system at equilibrium: I2 (g) ⇌ 2 I (g)arrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forwardWe learned four factors (ARIO) for comparing the relative acidity of compounds. When two of these factors are in competition, the order of priority is the order in which these factors were covered ("atom" being the most important factor and "orbital" being the least important). However, we also mentioned that there are exceptions to this order of priority. Compare the two compounds and identify the exception. OH PK-4.75 SH PK-10.6 5. "Resonance" is more important than "atom" because the conjugate base of first compound is more stable than the second. "Atom" is more important than "resonance" because the conjugate base of first compound is more stable than the second. "Resonance" is more important than "atom" because the conjugate base of second compound is more stable than the first. "Atom" is more important than "resonance" because the conjugate base of second compound is more stable than the first.arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage LearningEBK A SMALL SCALE APPROACH TO ORGANIC LChemistryISBN:9781305446021Author:LampmanPublisher:CENGAGE LEARNING - CONSIGNMENT
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