(a) Interpretation: The moles of solute present in 1.75 L of 0.215 M solution are to be calculated. Concept introduction: A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume ( % w / v ) , percent volume by volume ( % v / v ) and molarity ( M ) . When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight ( % w / w ) .

Question

The reaction of solid dimethylhydrazine, (CH3)2N2H2, and liquefied dinitrogen tetroxide, N2O4, has been investigated for use as rocket fuel. The reaction produces the gases carbon dioxide (CO2), nitrogen (N2), and water vapor (H2O), which are ejected in the exhaust gases. In a controlled experiment, solid dimethylhydrazine was reacted with excess dinitrogen tetroxide, and the gases were collected in a closed balloon until a pressure of 2.50 atm and a temperature of 400.0 K were reached.(a) What are the partial pressures of CO2, N2, and H2O?(b) When the CO2 is removed by chemical reaction, what are the partial pressures of the remaining gases?

Answer 1

Question

Chapter 7, Problem 7.24E

Interpretation Introduction

(a)

Interpretation:

The moles of solute present in 1.75 L of 0.215 M solution are to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(b)

Interpretation:

The moles of solute present in 250. mL of 0.300 M solution are to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(c)

Interpretation:

The volume in mL of 0.350 M solution containing 0.200 mol of solute is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

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The reaction of solid dimethylhydrazine, (CH3)2N2H2, and liquefied dinitrogen tetroxide, N2O4, has been investigated for use as rocket fuel. The reaction produces the gases carbon dioxide (CO2), nitrogen (N2), and water vapor (H2O), which are ejected in the exhaust gases. In a controlled experiment, solid dimethylhydrazine was reacted with excess dinitrogen tetroxide, and the gases were collected in a closed balloon until a pressure of 2.50 atm and a temperature of 400.0 K were reached.(a) What are the partial pressures of CO2, N2, and H2O?(b) When the CO2 is removed by chemical reaction, what are the partial pressures of the remaining gases?

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How does the square root mean square velocity of gas molecules vary with temperature? Illustrate this relationship by plotting the square root mean square velocity of N2 molecules as a function of temperature from T=100 K to T=300 K.

Answer 2

Question

Chapter 7, Problem 7.24E

Interpretation Introduction

(a)

Interpretation:

The moles of solute present in 1.75 L of 0.215 M solution are to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(b)

Interpretation:

The moles of solute present in 250. mL of 0.300 M solution are to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(c)

Interpretation:

The volume in mL of 0.350 M solution containing 0.200 mol of solute is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

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Answer 3

Question

Chapter 7, Problem 7.24E

Interpretation Introduction

(a)

Interpretation:

The moles of solute present in 1.75 L of 0.215 M solution are to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(b)

Interpretation:

The moles of solute present in 250. mL of 0.300 M solution are to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(c)

Interpretation:

The volume in mL of 0.350 M solution containing 0.200 mol of solute is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

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Answer 4

Question

Chapter 7, Problem 7.24E

Interpretation Introduction

(a)

Interpretation:

The moles of solute present in 1.75 L of 0.215 M solution are to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(b)

Interpretation:

The moles of solute present in 250. mL of 0.300 M solution are to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(c)

Interpretation:

The volume in mL of 0.350 M solution containing 0.200 mol of solute is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

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Answer 5

Chapter 7, Problem 7.24E

Interpretation Introduction

(a)

Interpretation:

The moles of solute present in 1.75 L of 0.215 M solution are to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(b)

Interpretation:

The moles of solute present in 250. mL of 0.300 M solution are to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Interpretation Introduction

(c)

Interpretation:

The volume in mL of 0.350 M solution containing 0.200 mol of solute is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer 6

Chapter 7, Problem 7.24E

Interpretation Introduction

(a)

Interpretation:

The moles of solute present in 1.75 L of 0.215 M solution are to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer 7

Chapter 7, Problem 7.24E

Interpretation Introduction

(a)

Interpretation:

The moles of solute present in 1.75 L of 0.215 M solution are to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer 8

Interpretation Introduction

(b)

Interpretation:

The moles of solute present in 250. mL of 0.300 M solution are to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer 9

Interpretation Introduction

(b)

Interpretation:

The moles of solute present in 250. mL of 0.300 M solution are to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer 10

Interpretation Introduction

(c)

Interpretation:

The volume in mL of 0.350 M solution containing 0.200 mol of solute is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer 11

Interpretation Introduction

(c)

Interpretation:

The volume in mL of 0.350 M solution containing 0.200 mol of solute is to be calculated.

Concept introduction:

A solution is prepared by mixing proper amount of solute and solvent. The concentration of solution when measured on the basis of solution volume, is expressed in terms of percent weight by volume (% w/v), percent volume by volume (% v/v) and molarity (M). When concentration is measured on the basis of mass of solvent, it is expressed in terms of percent weight by weight (% w/w).

Answer 12

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Answer 23

Ch. 7 - Many solutions are found in the home. Some are...Ch. 7 - Prob. 7.2E Ch. 7 - Classify the following as being a solution or not...Ch. 7 - Classify the following as being a solution or not...Ch. 7 - Use the term soluble, insoluble, or immiscible to...Ch. 7 - Use the term soluble, insoluble, or immiscible to...Ch. 7 - Define the term miscible. It is not defined in the...Ch. 7 - Classify the following solutions as unsaturated,...Ch. 7 - Prob. 7.9E Ch. 7 - Prob. 7.10E

Solution Summary: The author explains the formula to calculate molarity and volume of a solution by mixing proper amount of solute and solvent.

Chapter 7 Solutions