The balanced equation for the given reaction should be given. Concept introduction: Redox reaction : The reduction and oxidation reactions are occur simultaneously with in a single reaction is known as redox reaction. Balancing of redox reaction : The unbalanced charge (electron) and atoms (ions) in the equation of redox reactions are commonly balanced by half reaction method. In this method, the given redox reaction is separated by two half reactions, one is oxidation and another one is reduction. The medium of the reaction is used to balance the Hydrogen and Oxygen ions in the half cell reactions. Balancing of redox reaction in acid medium: In the acid medium, the addition of H + ion to balance the Hydrogen and water is added to balance the Oxygen atom. Charge is balanced by addition of electron in the sides with the greater positive charge. Balancing of redox reaction in basic medium: In the basic medium, the addition of OH − ion and electron to balance the charge and Hydrogen and Oxygen atoms are balanced by addition of water in the equation.

Question

Want to see the full answer?

Answer 1

Question

Chapter 7, Problem 7.136MP

(a)

Interpretation Introduction

Interpretation:

The balanced equation for the given reaction should be given.

Concept introduction:

Redox reaction:

The reduction and oxidation reactions are occur simultaneously with in a single reaction is known as redox reaction.

Balancing of redox reaction:

The unbalanced charge (electron) and atoms (ions) in the equation of redox reactions are commonly balanced by half reaction method.

In this method, the given redox reaction is separated by two half reactions, one is oxidation and another one is reduction.

The medium of the reaction is used to balance the Hydrogen and Oxygen ions in the half cell reactions.

Balancing of redox reaction in acid medium:

In the acid medium, the addition of H+ ion to balance the Hydrogen and water is added to balance the Oxygen atom.

Charge is balanced by addition of electron in the sides with the greater positive charge.

Balancing of redox reaction in basic medium:

In the basic medium, the addition of OH− ion and electron to balance the charge and Hydrogen and Oxygen atoms are balanced by addition of water in the equation.

(b)

Interpretation Introduction

Interpretation:

The number of moles of oxide were formed, and number of moles of semimetal were in the initial 0.200 g sample should be calculated.

Concept Introduction:

Precipitation reaction:

If precipitate is formed, when two soluble salt solutions are combined together is known as precipitation reaction.

Mole:

Mole of the compound present in the solution is calculated by molarity concentration of the compound multiplied with litre volume of solution.

Mole =Molarity ×Liter

Mass:

Mass of the compound is calculated by mole of the compound is multiplied with molar mass of the compound.

Mass = Molar mass × mole

Mass percent:

The mass percent of analyte in give sample is given by below equation,

Mass % = Mass of analyteMass of sample×100

(c)

Interpretation Introduction

Interpretation:

The semimetal should be determined.

Concept Introduction:

Precipitation reaction:

If precipitate is formed, when two soluble salt solutions are combined together is known as precipitation reaction.

Mole:

Mole of the compound present in the solution is calculated by molarity concentration of the compound multiplied with litre volume of solution.

Mole =Molarity ×Liter

Mass:

Mass of the compound is calculated by mole of the compound is multiplied with molar mass of the compound.

Mass = Molar mass × mole

Mass percent:

The mass percent of analyte in give sample is given by below equation,

Mass % = Mass of analyteMass of sample×100

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Given a 1,3-dicarbonyl compound, state the (condensed) formula of the compound obtaineda) if I add hydroxylamine (NH2OH) to give an isooxazole.b) if I add thiosemicarbazide (NH2-CO-NH-NH2) to give an isothiazole.

Complete the following acid-base reactions and predict the direction of equilibrium for each. Justify your prediction by citing pK values for the acid and conjugate acid in each equilibrium. (a) (b) NHs (c) O₂N NH NH OH H₁PO₁

23.34 Show how to convert each starting material into isobutylamine in good yield. ཅ ནད ཀྱི (b) Br OEt (c) (d) (e) (f) H

Answer 2

Question

Chapter 7, Problem 7.136MP

(a)

Interpretation Introduction

Interpretation:

The balanced equation for the given reaction should be given.

Concept introduction:

Redox reaction:

The reduction and oxidation reactions are occur simultaneously with in a single reaction is known as redox reaction.

Balancing of redox reaction:

The unbalanced charge (electron) and atoms (ions) in the equation of redox reactions are commonly balanced by half reaction method.

In this method, the given redox reaction is separated by two half reactions, one is oxidation and another one is reduction.

The medium of the reaction is used to balance the Hydrogen and Oxygen ions in the half cell reactions.

Balancing of redox reaction in acid medium:

In the acid medium, the addition of H+ ion to balance the Hydrogen and water is added to balance the Oxygen atom.

Charge is balanced by addition of electron in the sides with the greater positive charge.

Balancing of redox reaction in basic medium:

In the basic medium, the addition of OH− ion and electron to balance the charge and Hydrogen and Oxygen atoms are balanced by addition of water in the equation.

(b)

Interpretation Introduction

Interpretation:

The number of moles of oxide were formed, and number of moles of semimetal were in the initial 0.200 g sample should be calculated.

Concept Introduction:

Precipitation reaction:

If precipitate is formed, when two soluble salt solutions are combined together is known as precipitation reaction.

Mole:

Mole of the compound present in the solution is calculated by molarity concentration of the compound multiplied with litre volume of solution.

Mole =Molarity ×Liter

Mass:

Mass of the compound is calculated by mole of the compound is multiplied with molar mass of the compound.

Mass = Molar mass × mole

Mass percent:

The mass percent of analyte in give sample is given by below equation,

Mass % = Mass of analyteMass of sample×100

(c)

Interpretation Introduction

Interpretation:

The semimetal should be determined.

Concept Introduction:

Precipitation reaction:

If precipitate is formed, when two soluble salt solutions are combined together is known as precipitation reaction.

Mole:

Mole of the compound present in the solution is calculated by molarity concentration of the compound multiplied with litre volume of solution.

Mole =Molarity ×Liter

Mass:

Mass of the compound is calculated by mole of the compound is multiplied with molar mass of the compound.

Mass = Molar mass × mole

Mass percent:

The mass percent of analyte in give sample is given by below equation,

Mass % = Mass of analyteMass of sample×100

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 7, Problem 7.136MP

(a)

Interpretation Introduction

Interpretation:

The balanced equation for the given reaction should be given.

Concept introduction:

Redox reaction:

The reduction and oxidation reactions are occur simultaneously with in a single reaction is known as redox reaction.

Balancing of redox reaction:

The unbalanced charge (electron) and atoms (ions) in the equation of redox reactions are commonly balanced by half reaction method.

In this method, the given redox reaction is separated by two half reactions, one is oxidation and another one is reduction.

The medium of the reaction is used to balance the Hydrogen and Oxygen ions in the half cell reactions.

Balancing of redox reaction in acid medium:

In the acid medium, the addition of H+ ion to balance the Hydrogen and water is added to balance the Oxygen atom.

Charge is balanced by addition of electron in the sides with the greater positive charge.

Balancing of redox reaction in basic medium:

In the basic medium, the addition of OH− ion and electron to balance the charge and Hydrogen and Oxygen atoms are balanced by addition of water in the equation.

(b)

Interpretation Introduction

Interpretation:

The number of moles of oxide were formed, and number of moles of semimetal were in the initial 0.200 g sample should be calculated.

Concept Introduction:

Precipitation reaction:

If precipitate is formed, when two soluble salt solutions are combined together is known as precipitation reaction.

Mole:

Mole of the compound present in the solution is calculated by molarity concentration of the compound multiplied with litre volume of solution.

Mole =Molarity ×Liter

Mass:

Mass of the compound is calculated by mole of the compound is multiplied with molar mass of the compound.

Mass = Molar mass × mole

Mass percent:

The mass percent of analyte in give sample is given by below equation,

Mass % = Mass of analyteMass of sample×100

(c)

Interpretation Introduction

Interpretation:

The semimetal should be determined.

Concept Introduction:

Precipitation reaction:

If precipitate is formed, when two soluble salt solutions are combined together is known as precipitation reaction.

Mole:

Mole of the compound present in the solution is calculated by molarity concentration of the compound multiplied with litre volume of solution.

Mole =Molarity ×Liter

Mass:

Mass of the compound is calculated by mole of the compound is multiplied with molar mass of the compound.

Mass = Molar mass × mole

Mass percent:

The mass percent of analyte in give sample is given by below equation,

Mass % = Mass of analyteMass of sample×100

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 7, Problem 7.136MP

(a)

Interpretation Introduction

Interpretation:

The balanced equation for the given reaction should be given.

Concept introduction:

Redox reaction:

The reduction and oxidation reactions are occur simultaneously with in a single reaction is known as redox reaction.

Balancing of redox reaction:

The unbalanced charge (electron) and atoms (ions) in the equation of redox reactions are commonly balanced by half reaction method.

In this method, the given redox reaction is separated by two half reactions, one is oxidation and another one is reduction.

The medium of the reaction is used to balance the Hydrogen and Oxygen ions in the half cell reactions.

Balancing of redox reaction in acid medium:

In the acid medium, the addition of H+ ion to balance the Hydrogen and water is added to balance the Oxygen atom.

Charge is balanced by addition of electron in the sides with the greater positive charge.

Balancing of redox reaction in basic medium:

In the basic medium, the addition of OH− ion and electron to balance the charge and Hydrogen and Oxygen atoms are balanced by addition of water in the equation.

(b)

Interpretation Introduction

Interpretation:

The number of moles of oxide were formed, and number of moles of semimetal were in the initial 0.200 g sample should be calculated.

Concept Introduction:

Precipitation reaction:

If precipitate is formed, when two soluble salt solutions are combined together is known as precipitation reaction.

Mole:

Mole of the compound present in the solution is calculated by molarity concentration of the compound multiplied with litre volume of solution.

Mole =Molarity ×Liter

Mass:

Mass of the compound is calculated by mole of the compound is multiplied with molar mass of the compound.

Mass = Molar mass × mole

Mass percent:

The mass percent of analyte in give sample is given by below equation,

Mass % = Mass of analyteMass of sample×100

(c)

Interpretation Introduction

Interpretation:

The semimetal should be determined.

Concept Introduction:

Precipitation reaction:

If precipitate is formed, when two soluble salt solutions are combined together is known as precipitation reaction.

Mole:

Mole of the compound present in the solution is calculated by molarity concentration of the compound multiplied with litre volume of solution.

Mole =Molarity ×Liter

Mass:

Mass of the compound is calculated by mole of the compound is multiplied with molar mass of the compound.

Mass = Molar mass × mole

Mass percent:

The mass percent of analyte in give sample is given by below equation,

Mass % = Mass of analyteMass of sample×100

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 7, Problem 7.136MP

(a)

Interpretation Introduction

Interpretation:

The balanced equation for the given reaction should be given.

Concept introduction:

Redox reaction:

The reduction and oxidation reactions are occur simultaneously with in a single reaction is known as redox reaction.

Balancing of redox reaction:

The unbalanced charge (electron) and atoms (ions) in the equation of redox reactions are commonly balanced by half reaction method.

In this method, the given redox reaction is separated by two half reactions, one is oxidation and another one is reduction.

The medium of the reaction is used to balance the Hydrogen and Oxygen ions in the half cell reactions.

Balancing of redox reaction in acid medium:

In the acid medium, the addition of H+ ion to balance the Hydrogen and water is added to balance the Oxygen atom.

Charge is balanced by addition of electron in the sides with the greater positive charge.

Balancing of redox reaction in basic medium:

In the basic medium, the addition of OH− ion and electron to balance the charge and Hydrogen and Oxygen atoms are balanced by addition of water in the equation.

(b)

Interpretation Introduction

Interpretation:

The number of moles of oxide were formed, and number of moles of semimetal were in the initial 0.200 g sample should be calculated.

Concept Introduction:

Precipitation reaction:

If precipitate is formed, when two soluble salt solutions are combined together is known as precipitation reaction.

Mole:

Mole of the compound present in the solution is calculated by molarity concentration of the compound multiplied with litre volume of solution.

Mole =Molarity ×Liter

Mass:

Mass of the compound is calculated by mole of the compound is multiplied with molar mass of the compound.

Mass = Molar mass × mole

Mass percent:

The mass percent of analyte in give sample is given by below equation,

Mass % = Mass of analyteMass of sample×100

(c)

Interpretation Introduction

Interpretation:

The semimetal should be determined.

Concept Introduction:

Precipitation reaction:

If precipitate is formed, when two soluble salt solutions are combined together is known as precipitation reaction.

Mole:

Mole of the compound present in the solution is calculated by molarity concentration of the compound multiplied with litre volume of solution.

Mole =Molarity ×Liter

Mass:

Mass of the compound is calculated by mole of the compound is multiplied with molar mass of the compound.

Mass = Molar mass × mole

Mass percent:

The mass percent of analyte in give sample is given by below equation,

Mass % = Mass of analyteMass of sample×100

Answer 6

Chapter 7, Problem 7.136MP

(a)

Interpretation Introduction

Interpretation:

The balanced equation for the given reaction should be given.

Concept introduction:

Redox reaction:

The reduction and oxidation reactions are occur simultaneously with in a single reaction is known as redox reaction.

Balancing of redox reaction:

The unbalanced charge (electron) and atoms (ions) in the equation of redox reactions are commonly balanced by half reaction method.

In this method, the given redox reaction is separated by two half reactions, one is oxidation and another one is reduction.

The medium of the reaction is used to balance the Hydrogen and Oxygen ions in the half cell reactions.

Balancing of redox reaction in acid medium:

In the acid medium, the addition of H+ ion to balance the Hydrogen and water is added to balance the Oxygen atom.

Charge is balanced by addition of electron in the sides with the greater positive charge.

Balancing of redox reaction in basic medium:

In the basic medium, the addition of OH− ion and electron to balance the charge and Hydrogen and Oxygen atoms are balanced by addition of water in the equation.

Answer 7

Chapter 7, Problem 7.136MP

(a)

Interpretation Introduction

Interpretation:

The balanced equation for the given reaction should be given.

Concept introduction:

Redox reaction:

The reduction and oxidation reactions are occur simultaneously with in a single reaction is known as redox reaction.

Balancing of redox reaction:

The unbalanced charge (electron) and atoms (ions) in the equation of redox reactions are commonly balanced by half reaction method.

In this method, the given redox reaction is separated by two half reactions, one is oxidation and another one is reduction.

The medium of the reaction is used to balance the Hydrogen and Oxygen ions in the half cell reactions.

Balancing of redox reaction in acid medium:

In the acid medium, the addition of H+ ion to balance the Hydrogen and water is added to balance the Oxygen atom.

Charge is balanced by addition of electron in the sides with the greater positive charge.

Balancing of redox reaction in basic medium:

In the basic medium, the addition of OH− ion and electron to balance the charge and Hydrogen and Oxygen atoms are balanced by addition of water in the equation.

Answer 8

(b)

Interpretation Introduction

Interpretation:

The number of moles of oxide were formed, and number of moles of semimetal were in the initial 0.200 g sample should be calculated.

Concept Introduction:

Precipitation reaction:

If precipitate is formed, when two soluble salt solutions are combined together is known as precipitation reaction.

Mole:

Mole of the compound present in the solution is calculated by molarity concentration of the compound multiplied with litre volume of solution.

Mole =Molarity ×Liter

Mass:

Mass of the compound is calculated by mole of the compound is multiplied with molar mass of the compound.

Mass = Molar mass × mole

Mass percent:

The mass percent of analyte in give sample is given by below equation,

Mass % = Mass of analyteMass of sample×100

Answer 9

(b)

Interpretation Introduction

Interpretation:

The number of moles of oxide were formed, and number of moles of semimetal were in the initial 0.200 g sample should be calculated.

Concept Introduction:

Precipitation reaction:

If precipitate is formed, when two soluble salt solutions are combined together is known as precipitation reaction.

Mole:

Mole of the compound present in the solution is calculated by molarity concentration of the compound multiplied with litre volume of solution.

Mole =Molarity ×Liter

Mass:

Mass of the compound is calculated by mole of the compound is multiplied with molar mass of the compound.

Mass = Molar mass × mole

Mass percent:

The mass percent of analyte in give sample is given by below equation,

Mass % = Mass of analyteMass of sample×100

Answer 10

(c)

Interpretation Introduction

Interpretation:

The semimetal should be determined.

Concept Introduction:

Precipitation reaction:

If precipitate is formed, when two soluble salt solutions are combined together is known as precipitation reaction.

Mole:

Mole of the compound present in the solution is calculated by molarity concentration of the compound multiplied with litre volume of solution.

Mole =Molarity ×Liter

Mass:

Mass of the compound is calculated by mole of the compound is multiplied with molar mass of the compound.

Mass = Molar mass × mole

Mass percent:

The mass percent of analyte in give sample is given by below equation,

Mass % = Mass of analyteMass of sample×100

Answer 11

(c)

Interpretation Introduction

Interpretation:

The semimetal should be determined.

Concept Introduction:

Precipitation reaction:

If precipitate is formed, when two soluble salt solutions are combined together is known as precipitation reaction.

Mole:

Mole of the compound present in the solution is calculated by molarity concentration of the compound multiplied with litre volume of solution.

Mole =Molarity ×Liter

Mass:

Mass of the compound is calculated by mole of the compound is multiplied with molar mass of the compound.

Mass = Molar mass × mole

Mass percent:

The mass percent of analyte in give sample is given by below equation,

Mass % = Mass of analyteMass of sample×100

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 15

Ch. 7.1 - What is the molar concentration of Br ions in a...Ch. 7.1 - Three different substances, A2X, A2Y, and A2Z, are...Ch. 7.2 - Prob. 7.3P Ch. 7.3 - Write net ionic equations for the following...Ch. 7.4 - Predict whether each of the following compounds is...Ch. 7.4 - Predict whether a precipitation reaction will...Ch. 7.4 - How might you use a precipitation reaction to...Ch. 7.4 - An aqueous solution containing an anion,...Ch. 7.5 - Prob. 7.9P Ch. 7.5 - Give likely chemical formulas corresponding to the...

Solution Summary: The author explains that the balanced equation for the given reaction should be given. Redox reactions are separated by two half reactions, one is oxidation and the other is reduction.

Want to see the full answer?

Chapter 7 Solutions