To determine: Whether either reaction of the given reactions (reaction 1 or reaction 2) is capable of performing work.
Introduction: Equilibrium constant represents the relation between reactants and products in a reaction at equilibrium. The concentrations of reactants and products are constant at equilibrium. Under conditions of a biochemical reaction, free energy (G) is defined as the amount of energy available to perform work.
To determine: Which reaction is capable of performing work.
Introduction: Equilibrium constant represents the relation between reactants and products in a reaction at equilibrium. The concentrations of reactants and products are constant at equilibrium. Under conditions of a biochemical reaction, free energy (G) is defined as the amount of energy available to perform work.
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Chapter 7 Solutions
Biology (MindTap Course List)
- Consider the following reaction:ATP → AMP + 2 PiCalculate the equilibrium constant (Keq) given the following ΔG°′ values:ATP → AMP + PPi (−32.2 kJ/mol)PPi → 2Pi (−33.5 kJ/mol)arrow_forwardPlease do both and explainarrow_forwardCalculate ΔG° (answer in kJ/mol) for each of the following reactions from the equilibrium constant at the temperature given. (d)CoO(s)+CO(g)⇌Co(s)+CO2(g) T=550°C Kp=4.90×102 (e)CH3NH2(aq)+H2O(l)⟶CH3NH3+(aq)+OH−(aq) T=25°C Kp=4.4×10−4 (f)PbI2(s)⟶Pb2+(aq)+2I−(aq) T=25°C Kp=8.7×10arrow_forward
- Find the initial velocity for an enzymatic reaction when Vmax = 6.5 x 10–5 mol.sec–1, [S] = 3.0 x 10–3 M, and KM = 4.5 x 10–3 M.arrow_forward3L5arrow_forwardCalculate the standard free energy change for the following reaction: 3-PG + ATP 1,3-BPG + ADP ---> Given the following standard free energies of hydrolysis: ATP = - 31 kJ/mol 1,3-BPG = - 49.6 kJ/mol 18.6 kJ/mol 80.6 kJ/mol -80.6 kJ/mol 18.6 kJ/molarrow_forward
- Which of the following statements is true? (a) The largerthe Q, the larger the ΔG°. (b) If Q = 0, the system is at equilibrium.(c) If a reaction is spontaneous under standardconditions, it is spontaneous under all conditions. (d) Thefree-energy change for a reaction is independent of temperature.(e) If Q > 1, ΔG > ΔG°.arrow_forwardNonearrow_forwardCalculate the value of K for a reaction that has ΔG° = 37.6 kJ mol-1 at 37.0 °C. (R = 8.3145 J mol-1 K-1)arrow_forward
- Calculate the value of K for a reaction that has ΔG° = 37.6 kJ mol-1 at 37.0 °C. (R = 8.3145 J mol-1 K-1) in kj/molarrow_forwardsuppose the same experiment was done using the mixture of tube 2 of this experiment( as described in problem 1) in which Fe(SCN)2+ is assumed to form rather than FeSCN2+. That is, assume that equilibrium reaction 5 is the equilibrium that is occurring. Using the spectronic 20 the molarity of Fe(scn)2+ was found to be 0.265 x 10^04M. Write the chemical equilibrium equation ad the mathematical form of the equilibrium expression. calculate the initial molarity of Fe, HSCN, Fe(SCN)2+ and H. Calculate final molarity of Fe3+, HSCN, Fe(SCN)2+ and H+. What is the value of the equilibrium constant?arrow_forwardGiven the following data, determine the rate law for the reaction below. 2H2 (g) + 2NO(g) → 2H2O(g) + N2(g) Experiment 1 23 [H2] (M) [NO] (M) Initial Rate (M/s) 0.0369 0.0262 0.0248 0.1107 0.0262 0.0774 0.0369 0.0524 0.0992 Rate = k[H2][NO] Rate = k[H2][NO] Rate = k[NO]2 Rate = k[H2][NO]² Rate = k[H2][NO]arrow_forward
- Biology 2eBiologyISBN:9781947172517Author:Matthew Douglas, Jung Choi, Mary Ann ClarkPublisher:OpenStax